Circular Motion

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Circular Motion 2D Forces and Motion

description

Circular Motion. 2D Forces and Motion. Which is faster? The horse on the outside or the horse on the inside?. Merry-Go-Round. Same rotational speed for all animals on the Merry-Go-Round because they are attached rigidly. Animals further out have a greater linear speed. Rotational Speed. - PowerPoint PPT Presentation

Transcript of Circular Motion

Page 1: Circular Motion

Circular Motion

2D Forces and Motion

Page 2: Circular Motion

Which is faster? The horse on the outside or the horse on the inside?

Page 3: Circular Motion

Merry-Go-Round

Same rotational speed for all animals on the Merry-Go-Round because they are attached rigidly.

Animals further out have a greater linear speed.

Page 4: Circular Motion

Rotational Speed

Also calledAngular SpeedCircular Speedω (lower case

Omega Ω)

Page 5: Circular Motion

Linear Speed (v)Also calledTangential Speedv or vT

Page 6: Circular Motion

Describe Earth’s motion using the words rotate, revolve, and

axis.

Rotation: Spin. Axis is located within the object.Days on Earth.Revolution: Object turns about an external axis.Earth years.

Axis: Straight line around which rotation takes place.Days on Earth.

Page 7: Circular Motion

Frequency vs. Period

Period (T)- The time it takes for one full rotation or revolution of an object in seconds.

Frequency (f)- The number or rotations or revolutions per unit time, measured in Hertz (Hz)

1

1

Tf

fT

Page 8: Circular Motion

Revolution Lab QUESTIONS:

1) HOW IS RADIUS RELATED TO REVOLUTION SPEED? 2) WHAT HAPPENS WHEN YOU ARE SPINNING THE

STOPPER AT A CONSTANT RATE AND THEN SUDDENLY PULL DOWN ON THE STRING? WHY DOES THIS HAPPEN?

3) DOES A SPINNING OBJECT ACCELERATE? IF SO, WHAT IS THE DIRECTION OF ACCELERATION?

CHALLENGES: 1) Spin a rubber stopper above your head at several

different lengths to answer the question above. Do multiple trials.

2) Graph your data to help find the mathematical relationship between radius and revolution speed.

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Tangential Speed

vT = CT

= 2πrT

Page 10: Circular Motion

HOW IS RADIUS RELATED TO REVOLUTION SPEED?

In Uniform Circular Motion (fixed tangential speed), a larger radius will result in a

smaller rotational speed.

v

r

vT

r

Page 11: Circular Motion

HOW IS RADIUS RELATED TO REVOLUTION SPEED?

In Uniform Circular Motion (fixed tangential speed), a larger radius will result in a

smaller rotational speed.

v

r

lrθdldt

= drθdt

vT = r dθdt

vT = rω

Page 12: Circular Motion

Rotational Speed

vT

r€

vT = 2πrT

2πrTr

= 2πT

T = 1f

2πf

Page 13: Circular Motion

WHAT HAPPENS WHEN YOU ARE SPINNING THE STOPPER AT A CONSTANT RATE AND THEN

SUDDENLY PULL DOWN ON THE STRING? WHY DOES THIS HAPPEN?It spirals in because you apply a

constant force inward. You reduce the radius.

Page 14: Circular Motion

WHAT IS THE DIRECTION OF ACCELERATION OF AN OBJECT

IN UNIFORM CIRCULAR MOTION?

a = ΔvΔt

Δvv

= Δrr

Δv = Δrr

v

ar = vΔrurΔt

= v2

r

Page 15: Circular Motion

WHAT IS THE DIRECTION OF ACCELERATION OF AN OBJECT

IN UNIFORM CIRCULAR MOTION?

aT =d vdt

ar = v2

r

There is a radial component of

acceleration responsible for the constant

direction change, and a tangential component of acceleration which

results in an increase or decrease in tangential

speed.

a =d vdt

ˆ θ − v2

rˆ r

a = a r2 + aT

2

θtan−1 aT

ar

⎛ ⎝ ⎜

⎞ ⎠ ⎟

Page 16: Circular Motion

Describe the path of the stopper IF you were to cut the string between the tube

and the bottom weight

Page 17: Circular Motion

Centripetal Force Fc

A force of some kind is required to maintain circular motion. Why?

Any force that causes an object to follow a circular path is called a centripetal force.

Centripetal means “center-seeking”Always acts inwards

Page 18: Circular Motion

Centripetal Acceleration ac

2T

cvar

Tangential Velocity

Radius

Page 19: Circular Motion

Centripetal Force

2

2

c c

c

Tc

F maF ma

varmvFr

Page 20: Circular Motion

The banked ramp exit

The goal is to design a banked ramp exit that drivers can round safely even on ice. radius of curve is 50m speed of cars- 13.4m/s What should the angle of the bank be?

Page 21: Circular Motion

The banked ramp exit

Fg

FN FNy

FNx

Fy∑FNy − Fg = 0

Fx∑FNx = mac

FNy = Fg

FN cosθ = mg

FN sinθ = mac

FN = mgcosθ

mgcosθ

sinθ = mac

gtanθ = ac

θtan−1 ac

g ⎛ ⎝ ⎜

⎞ ⎠ ⎟

θtan−1 v2

rg

⎛ ⎝ ⎜

⎞ ⎠ ⎟

θ ≈20°

Page 22: Circular Motion