Characterizing the group of Coleman automorphisms4.E.C. Dade. Locally trivial outer automorphisms of...

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CHARACTERIZING THE GROUP OF COLEMAN AUTOMORPHISMS Arne Van Antwerpen September 4, 2017

Transcript of Characterizing the group of Coleman automorphisms4.E.C. Dade. Locally trivial outer automorphisms of...

Page 1: Characterizing the group of Coleman automorphisms4.E.C. Dade. Locally trivial outer automorphisms of ˙nite groups. 5.A. Van Antwerpen. Coleman automorphisms of ˙nite groups and their

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CHARACTERIZING THE GROUP OFCOLEMAN AUTOMORPHISMS

Arne Van AntwerpenSeptember 4, 2017

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DEFINITIONS

DefinitionLet G be a finite group and σ ∈ Aut(G). If for any prime p dividingthe order of G and any Sylow p-subgroup P of G, there exists ag ∈ G such that σ|P = conj(g)|P, then σ is said to be a Colemanautomorphism.

Denote Autcol(G) for the set of Coleman automorphisms, Inn(G)for the set of inner automorphisms and set

Outcol(G) = Autcol(G)/Inn(G).

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DEFINITIONS

DefinitionLet G be a finite group and σ ∈ Aut(G). If for any prime p dividingthe order of G and any Sylow p-subgroup P of G, there exists ag ∈ G such that σ|P = conj(g)|P, then σ is said to be a Colemanautomorphism.Denote Autcol(G) for the set of Coleman automorphisms, Inn(G)for the set of inner automorphisms and set

Outcol(G) = Autcol(G)/Inn(G).

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ELEMENTARY RESULTS

Theorem (Hertweck and Kimmerle)Let G be a finite group. The prime divisors of |Autcol(G)| are alsoprime divisors of |G|.

LemmaLet N be a normal subgroup of a finite group G. If σ ∈ Autcol(G),then σ|N ∈ Aut(N).

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ELEMENTARY RESULTS

Theorem (Hertweck and Kimmerle)Let G be a finite group. The prime divisors of |Autcol(G)| are alsoprime divisors of |G|.

LemmaLet N be a normal subgroup of a finite group G. If σ ∈ Autcol(G),then σ|N ∈ Aut(N).

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NORMALIZER PROBLEM

Let G be a group and R a ring (denote U(RG) for the units of RG),then we clearly have that

GCU(RG)(G) ⊆ NU(RG)(G)

Is this an equality?

NU(RG)(G) = GCU(RG)(G)

Of special interest: R = Z

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NORMALIZER PROBLEM

Let G be a group and R a ring (denote U(RG) for the units of RG),then we clearly have that

GCU(RG)(G) ⊆ NU(RG)(G)

Is this an equality?

NU(RG)(G) = GCU(RG)(G)

Of special interest: R = Z

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SETUP FOR REFORMULATION

If u ∈ NU(RG)(G), then u induces an automorphism of G:

ϕu : G→ Gg 7→ u−1gu

Denote AutU(G;R) for the group of these automorphisms(AutU(G) if R = Z) and OutU(G;R) = AutU(G;R)/Inn(G)

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SETUP FOR REFORMULATION

If u ∈ NU(RG)(G), then u induces an automorphism of G:

ϕu : G→ Gg 7→ u−1gu

Denote AutU(G;R) for the group of these automorphisms(AutU(G) if R = Z) and OutU(G;R) = AutU(G;R)/Inn(G)

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REFORMULATION

Theorem (Jackowski and Marciniak)G a finite group, R a commutative ring. TFAE1. NU(RG)(G) = GCU(RG)(G)

2. AutU(G;R) = Inn(G)

TheoremLet G be a finite group. Then,

AutU(G) ⊆ Autcol(G)

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REFORMULATION

Theorem (Jackowski and Marciniak)G a finite group, R a commutative ring. TFAE1. NU(RG)(G) = GCU(RG)(G)

2. AutU(G;R) = Inn(G)

TheoremLet G be a finite group. Then,

AutU(G) ⊆ Autcol(G)

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SADLY, A COUNTEREXAMPLE

Theorem (Hertweck)There exists a finite metabelian group G of order 225972 with

AutU(RG)(G) 6= Inn(G).

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SOME MOTIVATION

Theorem (Dade)Let G be a finite group. Then, Outcol(G) is a nilpotent group.

Dade conjectured that Outcol(G) is even an abelian group, dueto the following theorem.

Theorem (Dade)Let A be a finite abelian group. Then there exists a finitemetabelian group G such that Outcol(G) ∼= A.

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SOME MOTIVATION

Theorem (Dade)Let G be a finite group. Then, Outcol(G) is a nilpotent group.Dade conjectured that Outcol(G) is even an abelian group, dueto the following theorem.

Theorem (Dade)Let A be a finite abelian group. Then there exists a finitemetabelian group G such that Outcol(G) ∼= A.

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SOME MOTIVATION

Theorem (Dade)Let G be a finite group. Then, Outcol(G) is a nilpotent group.Dade conjectured that Outcol(G) is even an abelian group, dueto the following theorem.

Theorem (Dade)Let A be a finite abelian group. Then there exists a finitemetabelian group G such that Outcol(G) ∼= A.

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DADE’S CONJECTURE REVISITED

Using the structure of the groups, Hertweck and Kimmerleshowed that Outcol(G) = 1 for several classes of finite groups.

Theorem (Hertweck, Kimmerle)Let G be a finite group. Then Outcol(G) is a finite abelian group.

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DADE’S CONJECTURE REVISITED

Using the structure of the groups, Hertweck and Kimmerleshowed that Outcol(G) = 1 for several classes of finite groups.

Theorem (Hertweck, Kimmerle)Let G be a finite group. Then Outcol(G) is a finite abelian group.

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INTEREST IN CHARACTERIZING AUTCOL(G)

1. As an interesting subclass of Aut(G)

2. To study Outcol(G)

3. To find classes of finite groups where anothercounterexample to the Normalizer problem can be found

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INTEREST IN CHARACTERIZING AUTCOL(G)

1. As an interesting subclass of Aut(G)

2. To study Outcol(G)

3. To find classes of finite groups where anothercounterexample to the Normalizer problem can be found

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INTEREST IN CHARACTERIZING AUTCOL(G)

1. As an interesting subclass of Aut(G)

2. To study Outcol(G)

3. To find classes of finite groups where anothercounterexample to the Normalizer problem can be found

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GENERALIZED DIHEDRAL GROUPS

TheoremLet A be an abelian group and C2 = 〈η〉. Denote D = Ao η, whereη acts by inversion. Then,

Autcol(D) = Inn(D) o K,

where K is an elementary abelian 2-group.

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DEFINING THE OUTER AUTOMORPHISMS

DefinitionLet A be a finite abelian group and Cq = 〈x〉 a cyclic group oforder q = pr , with p a prime number. Write A = Ap1 × ...×Apn , itsSylow decomposition. Then, for any 1 ≤ i ≤ n and non-negativeintegers ki, define the group homomorphisms

φk1...kn : A ∗ Cq → A ∗ Cq

where, for gi ∈ Api ,

gi 7→ x−kigixki and x 7→ x

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ABELIAN-BY-CYCLIC GROUPS

TheoremLet G = Ao Cq, with notation as before. For any 1 ≤ i ≤ n, let ribe the smallest positive integer such that conj(xri)|Api

= id|Api.

Assume that the Sylow subgroups are ordered such thatr1 ≤ ... ≤ rn. Then,

Autcol(G) = Inn(G) o K,

withK =

{Φk1...kn−10 | ki ∈ Zri

}.

Thus,K ∼= Cr1 × ...× Crn−1 .

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NILPOTENT-BY-CYCLIC GROUPS

TheoremLet G be a finite nilpotent-by-(p-power-cyclic) group. Then, undervery technical specifications

Autcol(G) ∼= Inn(G) o K.

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QUESTIONS OF HERTWECK AND KIMMERLE

Questions (Hertweck and Kimmerle)

1. Is Outcol(G) a p′-group if G does not have Cp as a chieffactor?

2. Is Outcol(G) trivial if Op′(G) is trivial?3. Is Outcol(G) trivial if G has a unique minimal non-trivial

normal subgroup?

Partial Answer (Hertweck, Kimmerle)Besides giving several conditions, all three statements hold if Gis assumed to be a p-constrained group.

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QUESTIONS OF HERTWECK AND KIMMERLE

Questions (Hertweck and Kimmerle)

1. Is Outcol(G) a p′-group if G does not have Cp as a chieffactor?

2. Is Outcol(G) trivial if Op′(G) is trivial?

3. Is Outcol(G) trivial if G has a unique minimal non-trivialnormal subgroup?

Partial Answer (Hertweck, Kimmerle)Besides giving several conditions, all three statements hold if Gis assumed to be a p-constrained group.

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QUESTIONS OF HERTWECK AND KIMMERLE

Questions (Hertweck and Kimmerle)

1. Is Outcol(G) a p′-group if G does not have Cp as a chieffactor?

2. Is Outcol(G) trivial if Op′(G) is trivial?3. Is Outcol(G) trivial if G has a unique minimal non-trivial

normal subgroup?

Partial Answer (Hertweck, Kimmerle)Besides giving several conditions, all three statements hold if Gis assumed to be a p-constrained group.

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QUESTIONS OF HERTWECK AND KIMMERLE

Questions (Hertweck and Kimmerle)

1. Is Outcol(G) a p′-group if G does not have Cp as a chieffactor?

2. Is Outcol(G) trivial if Op′(G) is trivial?3. Is Outcol(G) trivial if G has a unique minimal non-trivial

normal subgroup?

Partial Answer (Hertweck, Kimmerle)Besides giving several conditions, all three statements hold if Gis assumed to be a p-constrained group.

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NEW ANSWERS

Partial Answers (Van Antwerpen)

1. No new result.

2. True, if Op(G) = Op′(G) = 1, where p is an odd prime and theorder of every direct component of E(G) is divisible by p.

3. True, if the unique minimal non-trivial normal subgroup isnon-abelian. True, if question 2 has a positive answer.

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NEW ANSWERS

Partial Answers (Van Antwerpen)

1. No new result.2. True, if Op(G) = Op′(G) = 1, where p is an odd prime and the

order of every direct component of E(G) is divisible by p.

3. True, if the unique minimal non-trivial normal subgroup isnon-abelian. True, if question 2 has a positive answer.

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NEW ANSWERS

Partial Answers (Van Antwerpen)

1. No new result.2. True, if Op(G) = Op′(G) = 1, where p is an odd prime and the

order of every direct component of E(G) is divisible by p.3. True, if the unique minimal non-trivial normal subgroup is

non-abelian. True, if question 2 has a positive answer.

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FURTHER RESEARCH

Inkling of IdeaIn case G has a unique minimal non-trivial normal subgroup N,which we may assume to be abelian, we may be able to use theclassification of the simple groups and the list of all Schurmultipliers to give a technical proof.

Related QuestionGross conjectured that for a finite group G with Op′(G) = 1 forsome odd prime p, p-central automorphisms of p-power orderare inner. Hertweck and Kimmerle believed this is possible usingthe classification of Schur multipliers.

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FURTHER RESEARCH

Inkling of IdeaIn case G has a unique minimal non-trivial normal subgroup N,which we may assume to be abelian, we may be able to use theclassification of the simple groups and the list of all Schurmultipliers to give a technical proof.

Related QuestionGross conjectured that for a finite group G with Op′(G) = 1 forsome odd prime p, p-central automorphisms of p-power orderare inner. Hertweck and Kimmerle believed this is possible usingthe classification of Schur multipliers.

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REFERENCES

1. M. Hertweck and W. Kimmerle. Coleman automorphismsof finite groups.

2. S.Jackowski and Z.Marciniak. Group automorphismsinducing the identity map on cohomology.

3. F. Gross. Automorphisms which centralize a Sylowp-subgroup.

4. E.C. Dade. Locally trivial outer automorphisms of finitegroups.

5. A. Van Antwerpen. Coleman automorphisms of finitegroups and their minimal normal subgroups. Arxiv preprint.