Chapter 9ocw.snu.ac.kr/sites/default/files/NOTE/9958.pdf · 2018. 1. 30. · Chapter 9 Elimination...
Transcript of Chapter 9ocw.snu.ac.kr/sites/default/files/NOTE/9958.pdf · 2018. 1. 30. · Chapter 9 Elimination...
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Chapter 9
Elimination reactions
E2 and E1 reactionsCompetition between SN and E
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Elimination reactions elimination and/or substitution
2 mechanisms ~ E2 and E1
Ch 9 #2
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bimolecular
mechanism ~ concerted
1,2-elimination or β-elimination
leaving group effect
E2: bimolecular elimination rxn
no substitution?
Ch 9 #3
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E2: regioselectivity (1) ~ Zaitsev’s rule
Zaitsev’s rule “The more substituted alkene product is obtained
when a proton is removed from the β-carbon that is bonded to the fewest hydrogens.”
a product [thermodynamic] control
Ch 9 #4
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Generally,
1° > 2° (no 3°) for SN2 Nu: attacks C3° > 2° > 1° for E2 (and E1, except 1°) B: attacks [takes] H
Ch 9 #5
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E2: regioselectivity (2) ~ resonance Resonance-stabilized alkene [conjugated diene] is more
stable. It may not be the more-substituted.
Ch 9 #6
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E2: regioselectivity (3) ~ steric Ch 9 #7
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E2: regioselectivity (4) ~ leaving group
F is the poorest leaving group.
alkene-like TS carbanion-like TS
Ch 9 #8
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stability of carbanion
Effect of leaving group on E2 product
Major product of E2 rxn is the more stable alkene. exceptions ~ steric reactant(s), (very) poor leaving group
Ch 9 #9
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E1: unimolecular elimination reaction
unimolecular
mechanism
weak base takes H from sp3 C? C+ accepts e of C: + hyperconjugation
no substitution?
Ch 9 #10
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E1: reactivity C+ stability
trend same to SN1
trend same to E2
leaving group effect
trend same to SN2, SN1, and E2
Ch 9 #11
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E1: regioselectivity more substituted product ~ Zaitsev’s rule
Ch 9 #12
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E1: C+ rearrangement Ch 9 #13
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Competition betw E2 and E1
E2 is favored by (high concentration of) strong base (like HO–, RO–), and
in aprotic polar solvent (like DMF, DMSO).
E1 is favored by weak base (like H2O, ROH), and
in protic polar solvent (like H2O, ROH).
SN2 is favored by good Nu: in aprotic polar solvent.
SN1 is favored by poor Nu: in protic polar solvent.
Ch 9 #14
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Stereochemistry of E2 and E1 E2 is an anti-elimination rxn. 4 atoms [H, C, C, X] must be periplanar [coplanar] to form C=C double bond.
anti-periplanar (highly) favored over syn-periplanar
Ch 9 #15
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E2 is stereoselective when 2 β-H’s 2 products (stereoselective)
Ch 9 #16
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when 1 β-H 1 product
stereospecific? (2R,3S) ?
Ch 9 #17
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E1 also is stereoselective.
2 β-H’s 2 products (stereoselective)
1 β-H’s 2 products (stereoselective)
Ch 9 #18
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Elimination from substituted cx E2 must be anti-periplanar.
E2 of menthyl chloride is slow.
H and X must be trans-diaxial.
Ch 9 #19
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E2 of neomenthyl chloride is rather fast.
+
Ch 9 #20
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E1 need not be periplanar.
+
Cl
CH3OH
CH3O
2 SN + 2 E products
1 product
Ch 9 #21
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Stereochemistry of SN and E Ch 9 #22
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Kinetic isotope effect
kH = 7.1 kD C–D stronger than C–H (why?)
(deuterium) kinetic isotope effect = kH/kD = 7.1
supports E2 (concerted) mechanism, not E1
Ch 9 #23
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Competition betw SN and E
SN2/E21. 1° favors SN2 over E2.
why? above comparison? just observed.
SN2/E2 is favored by good Nu:/strong B: in aprotic polar solvent.
SN1/E1 is favored by poor Nu:/weak B: in protic polar solvent.
X XX
Ch 9 #24
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SN2/E2 (cont’d)2. Steric hindrance favors E2 over SN2.
Ch 9 #25
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SN2/E2 (cont’d)3. Stronger B: [Nu:] favors E2 over SN2.
why? just observed.
RCOO– ~ a medium baseH3O+ > RCOOH > H2O
Ch 9 #26
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SN2/E2 (cont’d)4. High temperature favors E2 over SN2.
why? T∆S
Ch 9 #27
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SN2/E2 (cont’d)5. 3° undergoes E2 only.
Ch 9 #28
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SN1/E1 hard to control the ratio of SN1 to E1
no SN1/E1 for 1°
more SN1 over E1 for 3° why? no SN2 for 3°? just observed.
Ch 9 #29
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Ch 9 #30
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Using SN in synthesis Williamson (ether) synthesis
SN2
preparation of RO–
need very strong base for alcohol
need less strong base for phenol
Ch 9 #31
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Williamson (ether) synthesis (cont’d) Substrate [RX] should be 1°.
SN1 (using ROH) for 2° or 3° substrate
no SN, no ether
(b) is (much) better (a) gives E2 product also
Ch 9 #32
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alkynes from acetylide ion
SN2
Substrate [RX] better be 1°.
Ch 9 #33
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Using E in synthesis preparation of alkene
E2(/SN2) rather than E1(/SN1)
2° better, more hindered better
more E2 by using t-BuO– instead of –OH, high temperature
Ch 9 #34
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preparation of alkyne from dihalides
need very strong base (–NH2 > –OH) vinyl halide
from alkene
Ch 9 #35
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Designing synthesis II Ex 1>
direct hydrocyanation? possible, using catalyst
using SN/E
CN– ~ stronger B: than Br–, weaker B: than OH–
SN2 over E2 (or maybe SN1/E1)
Ex 2>
pKa of HCN = 9.1
E2, no SN2 anti-Markovnikov, syn
Ch 9 #36
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Ex 3>
Ex 4>
E2, no SN2not BH3
not BH3SN2 (low E2)
Ch 9 #37
Chapter 9���Elimination reactionsElimination reactionsE2: bimolecular elimination rxnE2: regioselectivity (1) ~ Zaitsev’s rule슬라이드 번호 5E2: regioselectivity (2) ~ resonanceE2: regioselectivity (3) ~ stericE2: regioselectivity (4) ~ leaving group슬라이드 번호 9E1: unimolecular elimination reactionE1: reactivityE1: regioselectivityE1: C+ rearrangement Competition betw E2 and E1Stereochemistry of E2 and E1슬라이드 번호 16슬라이드 번호 17슬라이드 번호 18Elimination from substituted cx슬라이드 번호 20슬라이드 번호 21Stereochemistry of SN and EKinetic isotope effectCompetition betw SN and E슬라이드 번호 25슬라이드 번호 26슬라이드 번호 27슬라이드 번호 28슬라이드 번호 29슬라이드 번호 30Using SN in synthesis 슬라이드 번호 32슬라이드 번호 33Using E in synthesis 슬라이드 번호 35Designing synthesis II슬라이드 번호 37