Chapter 5 Review

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Chapter 5 Review

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Chapter 5 Review. 1.) If there is an angle in standard position of the measure given , in which quadrant does the terminal side lie?. Quad III. Quad IV. Quad I. Quad II. 2.) Change angle measure to radian measure in terms of π , or degree measure. Degrees to radians π/180 - PowerPoint PPT Presentation

Transcript of Chapter 5 Review

Page 1: Chapter 5 Review

Chapter 5 Review

Page 2: Chapter 5 Review

1.) If there is an angle in standard position of the measure given, in which quadrant does the terminal side lie?

Quad IIIQuad IV

Quad IIQuad I

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2.) Change angle measure to radian measure in terms of π, or degree measure

Degrees to radians

π/180

Radians to degrees

180/π

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4.) Change the given angle to a degree measure rounded to the nearest tenth.

1. 52°25’

2. -132°3’45”

3. 5°5’123”

52 +25

60= 52.4°

−132 −3

60−

45

3600= −132.1°

5 +5

60+

123

3600= 5.1°

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5.) Find the reference angle for each angle.

Reference angle is the acute angle formed with the x-axis

And it is always positive

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5.) Find the reference angle for each angle.

Reference angle is the acute angle formed with the x-axis

And it is always positive!

θ

-150°

θ

−19π

18

θ θ

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Find a positive and a negative coterminal angle for each given angle.

ADD 2π

OR

SUBTRACT 2π

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Find the measure of each angle in red using the green angle given.

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Find the length of each arc. Round your answers to the nearest tenth.

s = rθ

REMEMBER YOU MUSTBE IN RADIANS

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Find the length of each arc. Leave your answer in terms of π

s = rθ

REMEMBER YOU MUSTBE IN RADIANS

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Find the area of each sector. Round your answers to the nearest tenth.

s =1

2r2θ

REMEMBER YOU MUSTBE IN RADIANS

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Find the area of each sector. Leave your answer in terms of π

s =1

2r2θ

REMEMBER YOU MUSTBE IN RADIANS

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I will give you one trig function’s value, and I will tell you in which quadrant the terminal sides lies, YOU TELL ME THE 5 OTHER TRIG FUNCTIONS.1. cos θ = 3/5 quadrant I

1. sin θ = -2/3 quadrant IV

secθ =5

3

sinθ =4

5

cscθ =5

4

tanθ =4

3

cotθ =3

4

cscθ =−3

2

cosθ =5

3

secθ =3 5

5

tanθ =−2 5

5

cotθ =− 5

2

cosθ =adj

hyp

secθ =hyp

adj

sinθ =opp

hyp

cscθ =hyp

opp

tanθ =opp

adj

cotθ =adj

opp

θ

3

54

θ-2

3

5

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Find the exact value, WITHOUT USING A CALCULATOR!

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Solve each triangle. Round answers to the nearest tenth.

Use your trig ratios

And Pythagorean theorem

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Solve each triangle. Round answers to the nearest tenth.

Use your trig ratios

And Pythagorean theorem

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18.) Use the Law of Sines to solve each triangle. Round your answers to the nearest tenth.

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Use the Law of Cosines and solve the triangle complety:

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Find the area of each triangle:

Area =1

2ab(sinC)

Area =1

2bc(sinA)

Area =1

2ac(sinB)

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Find the area of each triangle:

C

BA

FIRST FIND THE LAST ANGLE BY SUBTRACTING FROM 180

SECOND, DECIDE WHICH OF THE THREE FORMULAS YOU WOULD USE

Area =1

2a

2 (sinB)(sinC)

sinA

Area =1

2b

2 (sinA)(sinC)

sinB

Area =1

2c

2 (sinB)(sinA)

sinC

Given two angles and a side

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Find the area of the triangle with sides 31, 44, and 60 units:

GIVEN THREE SIDES = HERO’S FORMULA

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Find the area of each triangle:1. A = 20°, a = 19, C = 64°

2. a = 5, b = 7, c = 9

3. a = 11.7, b = 13.5, C = 85°20’

4. A = 42°, B = 65°, a = 63

Area =1

2(19)2 (sin64°)(sin96°)

sin20°= 471.7

s =1

2(5 + 7 + 9) =10.5

Area = 10.5(10.5 − 5)(10.5 − 7)(10.5 − 9) =17.4

Area =1

2(11.7)(13.5)sin(85.3°) = 78.1

Area =1

2(63)2 (sin65°)(sin96°)

sin 42°= 2570.5

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28.) Find the area of a circular segment to the nearest tenth if the measure of its central angle is 135° and the measure of its radius is 6.9 units.

s =1

2r2(θ − sinθ )

Θ = central angle in radiansr = radius

s =1

2(6.9)2 3π

4− sin

4

⎝ ⎜

⎠ ⎟

s = 39.3units2