Chapter 16: Chi Square
Embed Size (px)
description
Transcript of Chapter 16: Chi Square

Chapter 16: Chi SquareChapter 16: Chi Square
PSY295-001—Spring 2003PSY295-001—Spring 2003
SummerfeltSummerfelt

Chapter 16 Chi-SquareChapter 16 Chi-Square 22
OverviewOverview
z, t, ANOVA, regression, & correlation z, t, ANOVA, regression, & correlation have have – Used at least one continuous variableUsed at least one continuous variable– Relied on underlying population parametersRelied on underlying population parameters– Been based on particular distributionsBeen based on particular distributions
Chi square (Chi square (χχ22)) is is– Based on categorical variablesBased on categorical variables– Non-parametricNon-parametric– Distribution-freeDistribution-free

Chapter 16 Chi-SquareChapter 16 Chi-Square 33
Categorical VariablesCategorical Variables
Generally the count of objects falling in Generally the count of objects falling in each of several categories.each of several categories.
Examples:Examples:– number of fraternity, sorority, and nonaffiliated number of fraternity, sorority, and nonaffiliated
members of a classmembers of a class– number of students choosing answers: 1, 2, 3, number of students choosing answers: 1, 2, 3,
4, or 54, or 5
Emphasis on frequency in each categoryEmphasis on frequency in each category

Chapter 16 Chi-SquareChapter 16 Chi-Square 44
Contingency TablesContingency Tables
Two independent variablesTwo independent variables– Can be various levels similar to two-way Can be various levels similar to two-way
ANOVAANOVA– Gender identity, level of happinessGender identity, level of happiness

Chapter 16 Chi-SquareChapter 16 Chi-Square 55
Intimacy and DepressionIntimacy and Depression
Everitt & Smith (1979)Everitt & Smith (1979)
Asked depressed and non-depressed Asked depressed and non-depressed women about intimacy with women about intimacy with boyfriend/husbandboyfriend/husband
Data on next slideData on next slide

Chapter 16 Chi-SquareChapter 16 Chi-Square 66
DataData

Chapter 16 Chi-SquareChapter 16 Chi-Square 77
What Do the Data Say?What Do the Data Say?
It It lookslooks as if depressed women are more as if depressed women are more likely to report lack of intimacy.likely to report lack of intimacy.
What alternative explanations?What alternative explanations?
Is the relationship reliably different from Is the relationship reliably different from chance?chance?– Chi-square testChi-square test

Chapter 16 Chi-SquareChapter 16 Chi-Square 88
Chi-Square on Contingency Chi-Square on Contingency TableTable
The formulaThe formula
Expected frequenciesExpected frequenciesE = E = RT X CTRT X CT GT GT
RTRT = Row total, = Row total, CTCT = Column total, = Column total, GTGT = Grand total = Grand total
EEO 2
2 )(

Chapter 16 Chi-SquareChapter 16 Chi-Square 99
Expected FrequenciesExpected Frequencies
EE1111 = (37*138)/419 = 12.19 = (37*138)/419 = 12.19
EE1212 = (37*281)/419 = 24.81 = (37*281)/419 = 24.81
EE2121 = (382*138)/419 = 125.81 = (382*138)/419 = 125.81
EE2222 = (382*281)/419 = 256.19 = (382*281)/419 = 256.19
Enter on following table Enter on following table

Chapter 16 Chi-SquareChapter 16 Chi-Square 1010
Observed and Expected Freq.Observed and Expected Freq.

Chapter 16 Chi-SquareChapter 16 Chi-Square 1111
Degrees of FreedomDegrees of Freedom
For contingency table, For contingency table, dfdf = ( = (RR - 1)( - 1)(CC - 1) - 1)
For our example this is (2 - 1)(2 - 1) = 1For our example this is (2 - 1)(2 - 1) = 1– Note that knowing any Note that knowing any oneone cell and the cell and the
marginal totals, you could reconstruct all other marginal totals, you could reconstruct all other cells.cells.

Chapter 16 Chi-SquareChapter 16 Chi-Square 1212
Chi-Square CalculationChi-Square Calculation
61.25
19.25619.256270
81.12581.125112
81.24)81.2411(
19.12)19.1226()(
22
2222
EEO
84.3)1(2
05.

Chapter 16 Chi-SquareChapter 16 Chi-Square 1313
ConclusionsConclusions
Since 25.61 > 3.84, reject Since 25.61 > 3.84, reject HH00
Conclude that depression and intimacy are Conclude that depression and intimacy are not independent.not independent.– How one responds to “satisfaction with How one responds to “satisfaction with
intimacy” depends on whether they are intimacy” depends on whether they are depressed.depressed.
– Could be depression-->dissatisfaction, lack of Could be depression-->dissatisfaction, lack of intimacy --> depression, depressed people intimacy --> depression, depressed people see world as not meeting needs, etc.see world as not meeting needs, etc.

Chapter 16 Chi-SquareChapter 16 Chi-Square 1414
Larger Contingency TablesLarger Contingency Tables
Is addiction linked to childhood Is addiction linked to childhood experimentation?experimentation?
Do adults who are, and are not, addicted to Do adults who are, and are not, addicted to substances (alcohol or drug) differ in childhood substances (alcohol or drug) differ in childhood categories of drug experimentation?categories of drug experimentation?
One variable = adult addictionOne variable = adult addiction– yes or noyes or no
Other variable = number of experimentation Other variable = number of experimentation categories (out of 4) as childrencategories (out of 4) as children
– Tobacco, alcohol, marijuana/hashish, or Tobacco, alcohol, marijuana/hashish, or acid/cocaine/other acid/cocaine/other

Chapter 16 Chi-SquareChapter 16 Chi-Square 1515
Adult Addiction
No Yes Total 0 512
(494.49) 54 (71.51)
566
1 227 (230.65)
37 (33.35)
264
2 59 (64.65)
15 (9.35)
74
Number Childhood Experiment Categories
3-4 18 (26.21)
12 (3.79)
30
Total 816 118 934

Chapter 16 Chi-SquareChapter 16 Chi-Square 1616
Chi-Square CalculationChi-Square Calculation
62.29
79.379.312
21.2621.2618
...51.71
)51.7154(49.494
)49.494512()(
22
2222
EEO
82.7)3(2
05.

Chapter 16 Chi-SquareChapter 16 Chi-Square 1717
ConclusionsConclusions
29.62 > 7.8229.62 > 7.82– Reject Reject HH00
– Conclude that adult addiction is related to Conclude that adult addiction is related to childhood experimentationchildhood experimentation
– Increasing levels of childhood Increasing levels of childhood experimentation are associated with greater experimentation are associated with greater levels of adult addiction.levels of adult addiction.
e.g. Approximately 10% of children not e.g. Approximately 10% of children not experimenting later become addicted as adults.experimenting later become addicted as adults.
Cont.

Chapter 16 Chi-SquareChapter 16 Chi-Square 1818
Conclusions--cont.Conclusions--cont.
Approximately 40% of highly experimenting Approximately 40% of highly experimenting children are later addicted as adults.children are later addicted as adults.
These data suggest that childhood These data suggest that childhood experimentation may lead to adult experimentation may lead to adult addiction.addiction.

Chapter 16 Chi-SquareChapter 16 Chi-Square 1919
Tests on ProportionsTests on Proportions
Proportions can be converted to Proportions can be converted to frequencies, and tested using frequencies, and tested using 22..
Use a Use a zz test directly on the proportions if test directly on the proportions if you have two proportionsyou have two proportions
From last exampleFrom last example– 10% of nonabused children abused as adults10% of nonabused children abused as adults– 40% of abused children abused as adults40% of abused children abused as adults
Cont.

Chapter 16 Chi-SquareChapter 16 Chi-Square 2020
Proportions--cont.Proportions--cont.
There were 566 nonabused children There were 566 nonabused children and 30 heavily abused children.and 30 heavily abused children.
17.5059.305.
0035.305.
301
5661
)111.1(111.
40.095.
11)1(
21
21
NNPP
PPz
111.30566
40.*30095.*566
21
2211
NNPNP
P
Cont.

Chapter 16 Chi-SquareChapter 16 Chi-Square 2121
Proportions--cont.Proportions--cont.
zz = 5.17 = 5.17
This is a standard This is a standard zz score. score.– Therefore .05 (2-tailed) cutoff = Therefore .05 (2-tailed) cutoff = ++1.961.96– Reject null hypothesis that the population Reject null hypothesis that the population
proportions of abuse in both groups are equal.proportions of abuse in both groups are equal.
This is just the square root of the This is just the square root of the 22 you you would have with would have with 22 on those 4 cells. on those 4 cells.

Chapter 16 Chi-SquareChapter 16 Chi-Square 2222
Independent ObservationsIndependent Observations
We require that observations be We require that observations be independent.independent.– Only one score from each respondentOnly one score from each respondent– Sum of frequencies must equal number of Sum of frequencies must equal number of
respondentsrespondents
If we don’t have independence of If we don’t have independence of observations, test is not valid.observations, test is not valid.

Chapter 16 Chi-SquareChapter 16 Chi-Square 2323
Small Expected FrequenciesSmall Expected Frequencies
Assume Assume OO would be normally distributed would be normally distributed around around EE over many replications of over many replications of experiment.experiment.
This could not happen if This could not happen if EE is small. is small.
Rule of thumb: Rule of thumb: EE >> 5 in each cell 5 in each cell– Not firm ruleNot firm rule– Violated in earlier example, but probably not a Violated in earlier example, but probably not a
problemproblem
Cont.

Chapter 16 Chi-SquareChapter 16 Chi-Square 2424
Expected Frequencies--cont.Expected Frequencies--cont.
More of a problem in tables with few cells.More of a problem in tables with few cells.
Never have expected frequency of 0.Never have expected frequency of 0.
Collapse adjacent cells if necessary.Collapse adjacent cells if necessary.