Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring...

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Chapter 13 SHM? WOD are underlined

Transcript of Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring...

Page 1: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Chapter 13 SHM? WOD are underlined

Page 2: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Remember Hooke’s Law F = - k Δx

New Symbol: “k”

Spring constant. “Stiffness” of the spring. Depends on each spring’s dimensions and material.

In N/m

Page 3: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Question If I let go, what will happen to the mass? Then what? Then what?

Page 4: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Simple Harmonic Motion Repeating up and down motion, (like cos wave.) (Draw a picture.)

Motion that occurs when the net force obeys Hooke’s Law The force is proportional to the displacement and always directed toward the equilibrium position

Show Example with Spring

The motion of a spring mass system is an example of Simple Harmonic Motion

Are springs the only type of SHM?

Page 5: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Simple Harmonic Motion The motion of a spring mass system is an example of Simple Harmonic Motion

Are springs the only type of SHM: No, Jump Rope, Sound Waves, Pendulum, Swing, up and down motion of an engine piston

Page 6: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Motion of the Spring-Mass System Initially, Δx is negative and the spring pulls it up.

The object’s inertia causes it to overshoot the equilibrium position.

Δx is positive now and the spring pushes it down. Again it will over shoot equilibrium.

Page 7: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Δx, v and a versus t graphs

What type of curve is this?

For Calculus,Derivative of sin is what?

What happens if you bump the spring?

Page 8: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Δx, v and a

Page 9: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Δx, v and a All three look like sinusoidal curves.

V is shifted backwards from Δx

a is shifted backwardwards from v.

Page 10: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Acceleration of an Object in Simple Harmonic Motion Remember F = - k x & F = ma Set them equal to each other: - k x = ma Solve for a:

a = -kΔx / m The acceleration is a function of position

Acceleration is not constant. So non-inertial frame of reference. So, the

kinematic equations are not valid here.

Page 11: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Amplitude: New Symbol “A”

Amplitude, A The amplitude is the maximum position of the object relative to the equilibrium position: (Max Height)

In the absence of friction, an object in simple harmonic motion will oscillate between the positions x = ±A

What friction is there?

Page 12: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Amplitude: New Symbol “A”

Amplitude, A The amplitude is the maximum position of the object relative to the equilibrium position: (Max Height)

In the absence of friction, an object in simple harmonic motion will oscillate between the positions x = ±A

What friction is there? Air Resistance, Molecular Motion in Spring

Page 13: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Period: New Symbol “T”

Period: T uppercase T stands for “period.” Amount of time for the oscillator to go through 1 complete cycle.

(Time for 1 up and 1 down.) Often measured from Max to Max, But can be measured from start to start, etc.

Measured in seconds.

Page 14: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Frequency: Another new symbol “ƒ”

“ƒ” is for frequency. It is the number of cycles an oscillator goes through in one second.

It is measured in 1/seconds 1/seconds => New unit “Hertz” or Hz. What is the frequency of revolutions of a new M16 bullet?

Page 15: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Frequency: Another new symbol “ƒ”

“ƒ” is for frequency. It is the number of cycles an oscillator goes through in one second.

It is measured in 1/seconds 1/seconds => New unit “Hertz” What is the frequency of revolutions of a new M16 bullet?

Ans:5100 Hz or Rev per Second.

Page 16: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Period and Frequency The period, T, is the time per cycle.

The frequency, ƒ, is cycles per time.

Frequency is the reciprocal of the period

ƒ = 1 / T

Page 17: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Quick Recap(Pic for WOD)

A – maximum distance from rest postion. T – time for one complete cycle ƒ = 1 / T

Page 18: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

In the table, label each +, -, or 0.

Page 19: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Question When you compress (or stretch) a spring, you have to do work on it. You apply a force over some distance.

Can you get that energy back?

Page 20: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Elastic Potential Energy

(Energy stored in a spring. Ability of a spring to do work.)

Work done on a spring is stored as potential energy.

The potential energy of the spring can be transformed into kinetic energy of the mass on the end.

Page 21: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Energy Transformations

Suppose a block is moving on a frictionless surface.

Before it hits the spring, the total mechanical energy of the system is the kinetic energy of the block. What happens next?

Page 22: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Energy Transformations, 2

The spring is partially compressed. The mass has slowed down. Σ ME = K.E. + P.E.

Page 23: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Energy Transformations, 3

The spring is now fully compressed The block momentarily stops The total mechanical energy is stored as elastic potential energy of the spring

Page 24: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

At all times, total Mechanical Energy is constant = KE + PE

(Put into notes)Equations for SHM Energy:KE = ½ mv2

PE = ½ kx2

Page 25: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Keep in mind. It takes the same energy to stretch a spring as compress it.

PE = ½ kx2

Is the same as = ½ k(-x)2

So PE is same at Max or Min A.

Page 26: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Back to Period and Frequency Period

Frequency

What variable is not in these equations?

k

m2T

m

k

2

1

T

Page 27: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Back to Period and Frequency Period

Frequency

What variable is not in these equations? A. T and f do not depend on Amplitude.

k

m2T

m

k

2

1

T

Page 28: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Problem A 1 kg block is dropped from a height of 1 m onto a spring with k = 55 N/m. How far will the spring compress?

Page 29: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Problem (revisited) A 1 kg block is dropped from a height of 1 m onto a spring with k = 55 N/m. What will it’s frequency and period of oscillation be?

Page 30: Chapter 13 SHM? WOD are underlined. Remember Hooke’s Law F = - k Δx New Symbol: “k” Spring constant. “Stiffness” of the spring. Depends on each spring’s.

Problem A 1 kg block is dropped from a height of 1 m onto a spring with k = 55 N/m.

Q1. How far will the spring compress? Q2. What will it’s frequency and period of oscillation be?