CEEN 3304 T3 Flexural Analysis and Design of Beamsusers.tamuk.edu/kfgfa00/CEEN 3304/Lectures/CEEN...

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1 Page 1 CEEN 3304 Concrete Design Flexural Analysis and Design of Beams Francisco Aguíñiga Assistant Professor Civil and Architectural Engineering Program Texas A&M University – Kingsville Page 2 Stress distributions

Transcript of CEEN 3304 T3 Flexural Analysis and Design of Beamsusers.tamuk.edu/kfgfa00/CEEN 3304/Lectures/CEEN...

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CEEN 3304 Concrete Design

Flexural Analysis and Design of Beams

Francisco AguíñigaAssistant Professor

Civil and Architectural Engineering ProgramTexas A&M University – Kingsville

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Stress distributions

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Concrete beam behavior

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Composite beams

Satisfy Mint = M, and P = 0

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Composite beamsdF = σdA = (E1ε)dzdydF’ = σ’dA’ = (E2ε)ndzdyEquating dF and dF’n = E1/E2

The force in material 1 isdF = σdA = σ’dA’σdzdy = σ’ndzdyσ = n σ’

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Uncracked concrete beams

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Stresses in uncracked beam

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Stresses in uncracked beam

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Stresses on cracked beam

1. Find neutral axis2. Find Icr3. Find stresses

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Stresses on cracked beam

( ) ( ) 02

2

=−− kddnAkdb s

bkdf

C c

2=

ss fAT =

jdfATjdM ss==

jdAMfs

s =

2

22kjbd

fbkdjd

fCjdM cc ===

2

2kjbd

Mfc =

bdAs=ρ

( ) nnnk ρρρ −+= 22

3kddjd −=

31 kj −=

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Design aids

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Example 3.2

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Ultimate flexural strength

Steel fails when fs = fy

Concrete fails when εc = εu = 0.003Knowing c need to know: C and β

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Ultimate flexural strength

0.72

0.425

0.325

0.56

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Ultimate flexural strength

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Ultimate flexural strength

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Example 3.3

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Ultimate flexural strength

Whitney’s equivalent rectangular stress block

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Rectangular stress block

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Rectangular stress block

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Moment capacity of beams

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Design aids – resistance factor

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Example 3.4

Solve the same beam using the rectangular stress block

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Limiting reinforcement ratios

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ACI strength reduction factors

ACI (9.3.2)Tension-controlled failure

When εc = 0.003, εs > 0.005, So φ = 0.9

Compression-controlled failureWhen εc = 0.003, εs < εy = 0.002, So φ = 0.65

Transition-controlled failureWhen εc = 0.003, εy < εs < 0.005So φ = A1 + B1εt

y

yAε

ε−

−=

005.09.000325.0

1y

Bε−

=005.0

25.01

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ACI strength reduction factors

Tension-controlled failureWhen εc = 0.003, εs > 0.005So φ = 0.9

Compression-controlled failure

When εc = 0.003, εs < εy

So φ = 0.65Transition-controlled failure

When εc = 0.003We have εy < εs < 0.005So φ = A1 + B1εt

ρmax

ρtc

ρbal

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ACI transition-controlled failure

Reason for limiting εt > 0.004 in tension-controlled failure (ACI 10.3.5)

In 2002 ACI codeLimit ρ to ρmax to 0.75ρbal

Results in εt = 0.00376, so limit εt to 0.004End up with ρmax < 0.75ρbal

bdAs=ρ

ty

cbal f

βρ

+=

003.0003.085.0 '

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ACI tension-controlled failure

From

For εt = 0.004, c/dt = 3/7And cmax = 3/7 dt

So amax = β1cmax = 3/7β1dt

So ρmax = 0.364 β1 f’c/fy (dt/d)

ttdc

ε+=

003.0003.0

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ACI tension-controlled failure

From

For εt = 0.005, c/dt = 3/8And cmax = 3/8 dt

So amax = β1cmax = 3/8β1dt

So ρmax = 0.319 β1 f’c/fy (dt/d)

ttdc

ε+=

003.0003.0

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ACI minimum reinforcement

ACI 10.5.1 requires that

dbf

dbff

A wy

wy

cs

2003 '

min, ≥=

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Example - analysis

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Example - analysis

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Design of R/C beams

ACI 9.5.2.1 minimum span/depth ratios for beams

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Design of R/C slabs

ACI 9.5.2.1 minimum span/depth ratios for one-way slabs

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Design of R/C beams

Selection of widthACI 7.6.1, 7.6.2, and 3.3.2Minimum space for single layer bars

smin = largest of (db or 1 in. or ¾ max aggregate size)

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Design of R/C beams

Minimum space for multiple layers of bars

Bars in upper layer placed directly above bottom layerClear distance between layers > 1 in.Also satisfy single layer requirements

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Design of R/C beamsMinimum cover

Cast in place concrete – protection¾ in. for slabs and 1 ½ in. for beams and columns

Exposed to weather or in contact with soilCover > 2 in.Concrete cast directly on ground - cover >= 3 in.

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Design of R/C beams

Minimum widthUsually #3 or #4 are used for stirrupsMinimum cover for bars in beam is 1.5 in.bmin = 2 x 1.5 in. + 2 x 1/2in. + 4 x 1 in. + 3 x 1 in. = 11 in.

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Design example 1

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Design example 1

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Design example 1

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Design example 1

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Design example 2

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Design example 2

As = 0.0124 x 13 x (28 – 2.5) = 4.11 in.2

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T-beams

Effective flange width – beams with slab on both sides (ACI 8.10)

beff < ¼ span of beamEff. overhang width on each side < 8 hf and ½ clear distance to next web

Effective flange width – beams with slab on one side only (ACI 8.10)

Effective overhang width less than1/12 span of beam6 hf and ½ clear distance to next web

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T-beams

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T-beams

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T-beams

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T-beams