Basics of QCD Lecture 3: PDFs and DGLAP
Transcript of Basics of QCD Lecture 3: PDFs and DGLAP
Basics of QCDLecture 3: PDFs and DGLAP
Gavin Salam
CERN Theory Unit
ICTP–SAIFR school on QCD and LHC physicsJuly 2015, Sao Paulo, Brazil
Factorization & parton distributions[PDFs]
Cross section for some hardprocess in hadron-hadroncollisions
x2 p
2
p1 p2
x 1p 1
σ
Z H
σ =∑i ,j
∫dx1fi/p(x1, µ
2F )
∫dx2fj/p(x2, µ
2F ) σij(s, µ2
R , µ2F ) , s = x1x2s
I Total X-section is factorized into a ‘hard part’ σ(x1p1, x2p2, µ2) and
‘normalization’ from parton distribution functions (PDF).
I Measure total cross section ↔ need to know PDFs to be able to testhard part (e.g. Higgs electroweak couplings).
I Picture seems intuitive, butI how can we determine the PDFs? NB: non-perturbativeI does picture really stand up to QCD corrections?
Gavin Salam (CERN) QCD basics 3 2 / 32
Factorization & parton distributions[PDFs]
Cross section for some hardprocess in hadron-hadroncollisions
x2 p
2
p1 p2
x 1p 1
σ
Z H
σ =∑i ,j
∫dx1fi/p(x1, µ
2F )
∫dx2fj/p(x2, µ
2F ) σij(s, µ2
R , µ2F ) , s = x1x2s
I Total X-section is factorized into a ‘hard part’ σ(x1p1, x2p2, µ2) and
‘normalization’ from parton distribution functions (PDF).
I Measure total cross section ↔ need to know PDFs to be able to testhard part (e.g. Higgs electroweak couplings).
I Picture seems intuitive, butI how can we determine the PDFs? NB: non-perturbativeI does picture really stand up to QCD corrections?
Gavin Salam (CERN) QCD basics 3 2 / 32
Factorization & parton distributions[PDFs]
Cross section for some hardprocess in hadron-hadroncollisions
x2 p
2
p1 p2
x 1p 1
σ
Z H
σ =∑i ,j
∫dx1fi/p(x1, µ
2F )
∫dx2fj/p(x2, µ
2F ) σij(s, µ2
R , µ2F ) , s = x1x2s
I Total X-section is factorized into a ‘hard part’ σ(x1p1, x2p2, µ2) and
‘normalization’ from parton distribution functions (PDF).
I Measure total cross section ↔ need to know PDFs to be able to testhard part (e.g. Higgs electroweak couplings).
I Picture seems intuitive, butI how can we determine the PDFs? NB: non-perturbativeI does picture really stand up to QCD corrections?
Gavin Salam (CERN) QCD basics 3 2 / 32
Factorization & parton distributions[PDFs]
Cross section for some hardprocess in hadron-hadroncollisions
x2 p
2
p1 p2
x 1p 1
σ
Z H
σ =∑i ,j
∫dx1fi/p(x1, µ
2F )
∫dx2fj/p(x2, µ
2F ) σij(s, µ2
R , µ2F ) , s = x1x2s
I Total X-section is factorized into a ‘hard part’ σ(x1p1, x2p2, µ2) and
‘normalization’ from parton distribution functions (PDF).
I Measure total cross section ↔ need to know PDFs to be able to testhard part (e.g. Higgs electroweak couplings).
I Picture seems intuitive, butI how can we determine the PDFs? NB: non-perturbativeI does picture really stand up to QCD corrections?
Gavin Salam (CERN) QCD basics 3 2 / 32
Factorization & parton distributions[PDFs]
Cross section for some hardprocess in hadron-hadroncollisions
x2 p
2
p1 p2
x 1p 1
σ
Z H
σ =∑i ,j
∫dx1fi/p(x1, µ
2F )
∫dx2fj/p(x2, µ
2F ) σij(s, µ2
R , µ2F ) , s = x1x2s
I Total X-section is factorized into a ‘hard part’ σ(x1p1, x2p2, µ2) and
‘normalization’ from parton distribution functions (PDF).
I Measure total cross section ↔ need to know PDFs to be able to testhard part (e.g. Higgs electroweak couplings).
I Picture seems intuitive, butI how can we determine the PDFs? NB: non-perturbativeI does picture really stand up to QCD corrections?
Gavin Salam (CERN) QCD basics 3 2 / 32
Deep Inelastic Scattering: kinematics[PDFs]
[DIS kinematics]
Hadron-hadron is complex because of two incoming partons — so startwith simpler Deep Inelastic Scattering (DIS).
e+
xp
k
p
"(1−y)k"
q (Q 2 = −q2)
proton
Kinematic relations:
x =Q2
2p.q; y =
p.q
p.k; Q2 = xys
√s = c.o.m. energy
I Q2 = photon virtuality ↔ transverseresolution at which it probes protonstructure
I x = longitudinal momentum fraction ofstruck parton in proton
I y = momentum fraction lost by electron(in proton rest frame)
Gavin Salam (CERN) QCD basics 3 3 / 32
Deep Inelastic Scattering: kinematics[PDFs]
[DIS kinematics]
Hadron-hadron is complex because of two incoming partons — so startwith simpler Deep Inelastic Scattering (DIS).
e+
xp
k
p
"(1−y)k"
q (Q 2 = −q2)
proton
Kinematic relations:
x =Q2
2p.q; y =
p.q
p.k; Q2 = xys
√s = c.o.m. energy
I Q2 = photon virtuality ↔ transverseresolution at which it probes protonstructure
I x = longitudinal momentum fraction ofstruck parton in proton
I y = momentum fraction lost by electron(in proton rest frame)
Gavin Salam (CERN) QCD basics 3 3 / 32
Deep Inelastic scattering (DIS): example[PDFs]
[DIS kinematics]
Q2 = 25030 GeV 2; y = 0:56;
e+
x=0.50
e+
Q2
x
proton
e+
jet
proton
jet
Gavin Salam (CERN) QCD basics 3 4 / 32
E.g.: extracting u & d distributions[PDFs]
[DIS X-sections]
Write DIS X-section to zeroth order in αs (‘quark parton model’):
d2σem
dxdQ2' 4πα2
xQ4
(1 + (1− y)2
2F em
2 +O (αs)
)∝ F em
2 [structure function]
F2 = x(e2uu(x) + e2
dd(x)) = x
(4
9u(x) +
1
9d(x)
)[u(x), d(x): parton distribution functions (PDF)]
NB:
I use perturbative language for interactions of up and down quarks
I but distributions themselves have a non-perturbative origin.
F2 gives us combination of u and d .How can we extract them separately?
Gavin Salam (CERN) QCD basics 3 5 / 32
E.g.: extracting u & d distributions[PDFs]
[DIS X-sections]
Write DIS X-section to zeroth order in αs (‘quark parton model’):
d2σem
dxdQ2' 4πα2
xQ4
(1 + (1− y)2
2F em
2 +O (αs)
)∝ F em
2 [structure function]
F2 = x(e2uu(x) + e2
dd(x)) = x
(4
9u(x) +
1
9d(x)
)[u(x), d(x): parton distribution functions (PDF)]
NB:
I use perturbative language for interactions of up and down quarks
I but distributions themselves have a non-perturbative origin.
F2 gives us combination of u and d .How can we extract them separately?
Gavin Salam (CERN) QCD basics 3 5 / 32
Extracting full flavour structure?[Quark distributions]
[u & d ]
I Using neutrons and isospin
F n2 =
4
9un(x) +
1
9dn(x)
' 4
9dp(x) +
1
9up(x)
I Using charged-current (W±) scattering[neutrinos instead of electrons in initial or final-state]
I W + interacts only with d , uI angular structure of interaction differs between d and u
Gavin Salam (CERN) QCD basics 3 6 / 32
Extracting full flavour structure?[Quark distributions]
[u & d ]
I Using neutrons and isospin
F n2 =
4
9un(x) +
1
9dn(x) ' 4
9dp(x) +
1
9up(x)
I Using charged-current (W±) scattering[neutrinos instead of electrons in initial or final-state]
I W + interacts only with d , uI angular structure of interaction differs between d and u
Gavin Salam (CERN) QCD basics 3 6 / 32
Extracting full flavour structure?[Quark distributions]
[u & d ]
I Using neutrons and isospin
F n2 =
4
9un(x) +
1
9dn(x) ' 4
9dp(x) +
1
9up(x)
I Using charged-current (W±) scattering[neutrinos instead of electrons in initial or final-state]
I W + interacts only with d , uI angular structure of interaction differs between d and u
Gavin Salam (CERN) QCD basics 3 6 / 32
All quarks[Quark distributions]
[u & d ]
0
0.1
0.2
0.3
0.4
0.5
0.6
0 0.2 0.4 0.6 0.8 1
x
quarks: xq(x)
Q2 = 10 GeV
2
uVdV
dS
uSsS
cS
CTEQ6D fit
These & other methods→ whole setof quarks & antiquarks
NB: also strange and charm quarks
I valence quarks (uV = u − u) arehardx → 1 : xqV (x) ∼ (1− x)3
quark counting rules
x → 0 : xqV (x) ∼ x0.5
Regge theory
I sea quarks (uS = 2u, . . . ) fairlysoft (low-momentum)x → 1 : xqS(x) ∼ (1− x)7
x → 0 : xqS(x) ∼ x−0.2
Gavin Salam (CERN) QCD basics 3 7 / 32
All quarks[Quark distributions]
[u & d ]
0
0.1
0.2
0.3
0.4
0.5
0.6
0 0.2 0.4 0.6 0.8 1
x
quarks: xq(x)
Q2 = 10 GeV
2
uVdV
dS
uSsS
cS
CTEQ6D fit
These & other methods→ whole setof quarks & antiquarks
NB: also strange and charm quarks
I valence quarks (uV = u − u) arehardx → 1 : xqV (x) ∼ (1− x)3
quark counting rules
x → 0 : xqV (x) ∼ x0.5
Regge theory
I sea quarks (uS = 2u, . . . ) fairlysoft (low-momentum)x → 1 : xqS(x) ∼ (1− x)7
x → 0 : xqS(x) ∼ x−0.2
Gavin Salam (CERN) QCD basics 3 7 / 32
All quarks[Quark distributions]
[u & d ]
0
0.1
0.2
0.3
0.4
0.5
0.6
0 0.2 0.4 0.6 0.8 1
x
quarks: xq(x)
Q2 = 10 GeV
2
uVdV
dS
uSsS
cS
CTEQ6D fit
These & other methods→ whole setof quarks & antiquarks
NB: also strange and charm quarks
I valence quarks (uV = u − u) arehardx → 1 : xqV (x) ∼ (1− x)3
quark counting rules
x → 0 : xqV (x) ∼ x0.5
Regge theory
I sea quarks (uS = 2u, . . . ) fairlysoft (low-momentum)x → 1 : xqS(x) ∼ (1− x)7
x → 0 : xqS(x) ∼ x−0.2
Gavin Salam (CERN) QCD basics 3 7 / 32
Momentum sum rule[Quark distributions]
[u & d ]
Check momentum sum-rule (sum over all species carries all momentum):∑i
∫dx xqi (x) = 1
qi momentum
dV 0.111uV 0.267dS 0.066uS 0.053sS 0.033cS 0.016
total 0.546
Where is missing momentum?Only parton type we’ve neglected so far is the
gluon
Not directly probed by photon or W±.NB: it’s crucial to know it for gg → H
To discuss gluons we must go beyond ‘naive’leading order picture, and bring in QCD split-ting. . .
Gavin Salam (CERN) QCD basics 3 8 / 32
Momentum sum rule[Quark distributions]
[u & d ]
Check momentum sum-rule (sum over all species carries all momentum):∑i
∫dx xqi (x) = 1
qi momentum
dV 0.111uV 0.267dS 0.066uS 0.053sS 0.033cS 0.016
total 0.546
Where is missing momentum?Only parton type we’ve neglected so far is the
gluon
Not directly probed by photon or W±.NB: it’s crucial to know it for gg → H
To discuss gluons we must go beyond ‘naive’leading order picture, and bring in QCD split-ting. . .
Gavin Salam (CERN) QCD basics 3 8 / 32
Momentum sum rule[Quark distributions]
[u & d ]
Check momentum sum-rule (sum over all species carries all momentum):∑i
∫dx xqi (x) = 1
qi momentum
dV 0.111uV 0.267dS 0.066uS 0.053sS 0.033cS 0.016
total 0.546
Where is missing momentum?Only parton type we’ve neglected so far is the
gluon
Not directly probed by photon or W±.NB: it’s crucial to know it for gg → H
To discuss gluons we must go beyond ‘naive’leading order picture, and bring in QCD split-ting. . .
Gavin Salam (CERN) QCD basics 3 8 / 32
Momentum sum rule[Quark distributions]
[u & d ]
Check momentum sum-rule (sum over all species carries all momentum):∑i
∫dx xqi (x) = 1
qi momentum
dV 0.111uV 0.267dS 0.066uS 0.053sS 0.033cS 0.016
total 0.546
Where is missing momentum?Only parton type we’ve neglected so far is the
gluon
Not directly probed by photon or W±.NB: it’s crucial to know it for gg → H
To discuss gluons we must go beyond ‘naive’leading order picture, and bring in QCD split-ting. . .
Gavin Salam (CERN) QCD basics 3 8 / 32
Momentum sum rule[Quark distributions]
[u & d ]
Check momentum sum-rule (sum over all species carries all momentum):∑i
∫dx xqi (x) = 1
qi momentum
dV 0.111uV 0.267dS 0.066uS 0.053sS 0.033cS 0.016
total 0.546
Where is missing momentum?Only parton type we’ve neglected so far is the
gluon
Not directly probed by photon or W±.NB: it’s crucial to know it for gg → H
To discuss gluons we must go beyond ‘naive’leading order picture, and bring in QCD split-ting. . .
Gavin Salam (CERN) QCD basics 3 8 / 32
Recall final-state splitting[Initial-state splitting]
[1st order analysis]
Yesterday: calculated q → qg (θ � 1, E � p) for final state of arbitraryhard process (σh):
σh+g ' σhαsCF
π
dE
E
dθ2
θ2
ω =
pzp
(1−z)p
θσh
Rewrite with different kinematic variables
σh+g ' σhαsCF
π
dz
1− z
dk2t
k2t
E = (1− z)pkt = E sin θ ' Eθ
If we avoid distinguishing q + g final state from q (infrared-collinear safety),then divergent real and virtual corrections cancel
σh+V ' −σhαsCF
π
dz
1− z
dk2t
k2t
p pσ
h
Gavin Salam (CERN) QCD basics 3 9 / 32
Initial-state splitting[Initial-state splitting]
[1st order analysis]
For initial state splitting, hard process occurs after splitting, andmomentum entering hard process is modified: p → zp.
σg+h(p) ' σh(zp)αsCF
π
dz
1− z
dk2t
k2t
zpp
(1−z)p
σh
For virtual terms, momentum entering hard process is unchanged
σV+h(p) ' −σh(p)αsCF
π
dz
1− z
dk2t
k2t
p pσ
h
Total cross section gets contribution with two different hard X-sections
σg+h + σV+h 'αsCF
π
∫dk2
t
k2t
dz
1− z[σh(zp)− σh(p)]
NB: We assume σh involves momentum transfers ∼ Q � kt , so ignore extra
transverse momentum in σhGavin Salam (CERN) QCD basics 3 10 / 32
Initial-state collinear divergence[Initial-state splitting]
[1st order analysis]
σg+h + σV+h 'αsCF
π
∫ Q2
0
dk2t
k2t︸ ︷︷ ︸
infinite
∫dz
1− z[σh(zp)− σh(p)]︸ ︷︷ ︸
finite
I In soft limit (z → 1), σh(zp)− σh(p)→ 0: soft divergence cancels.
I For 1− z 6= 0, σh(zp)− σh(p) 6= 0, so z integral is non-zero but finite.
BUT: kt integral is just a factor, and is infiniteThis is a collinear (kt → 0) divergence.
Cross section with incoming parton is not collinear safe!
This always happens with coloured initial-state particlesSo how do we do QCD calculations in such cases?
Gavin Salam (CERN) QCD basics 3 11 / 32
Initial-state collinear divergence[Initial-state splitting]
[1st order analysis]
σg+h + σV+h 'αsCF
π
∫ Q2
0
dk2t
k2t︸ ︷︷ ︸
infinite
∫dz
1− z[σh(zp)− σh(p)]︸ ︷︷ ︸
finite
I In soft limit (z → 1), σh(zp)− σh(p)→ 0: soft divergence cancels.
I For 1− z 6= 0, σh(zp)− σh(p) 6= 0, so z integral is non-zero but finite.
BUT: kt integral is just a factor, and is infiniteThis is a collinear (kt → 0) divergence.
Cross section with incoming parton is not collinear safe!
This always happens with coloured initial-state particlesSo how do we do QCD calculations in such cases?
Gavin Salam (CERN) QCD basics 3 11 / 32
Initial-state collinear divergence[Initial-state splitting]
[1st order analysis]
σg+h + σV+h 'αsCF
π
∫ Q2
0
dk2t
k2t︸ ︷︷ ︸
infinite
∫dz
1− z[σh(zp)− σh(p)]︸ ︷︷ ︸
finite
I In soft limit (z → 1), σh(zp)− σh(p)→ 0: soft divergence cancels.
I For 1− z 6= 0, σh(zp)− σh(p) 6= 0, so z integral is non-zero but finite.
BUT: kt integral is just a factor, and is infiniteThis is a collinear (kt → 0) divergence.
Cross section with incoming parton is not collinear safe!
This always happens with coloured initial-state particlesSo how do we do QCD calculations in such cases?
Gavin Salam (CERN) QCD basics 3 11 / 32
Initial-state collinear divergence[Initial-state splitting]
[1st order analysis]
σg+h + σV+h 'αsCF
π
∫ Q2
0
dk2t
k2t︸ ︷︷ ︸
infinite
∫dz
1− z[σh(zp)− σh(p)]︸ ︷︷ ︸
finite
I In soft limit (z → 1), σh(zp)− σh(p)→ 0: soft divergence cancels.
I For 1− z 6= 0, σh(zp)− σh(p) 6= 0, so z integral is non-zero but finite.
BUT: kt integral is just a factor, and is infiniteThis is a collinear (kt → 0) divergence.
Cross section with incoming parton is not collinear safe!
This always happens with coloured initial-state particlesSo how do we do QCD calculations in such cases?
Gavin Salam (CERN) QCD basics 3 11 / 32
Collinear cutoff[Initial-state splitting]
[1st order analysis]
Q 2
pxp
zxp
(1−z)xp
σh
1 GeV 2
By what right did we go to kt = 0?
We assumed pert. QCD to be valid forall scales, but below 1 GeV it becomesnon-perturbative.
Cut out this divergent region, & insteadput non-perturbative quark distributionin proton.
σ0 =
∫dx σh(xp) q(x , 1 GeV2)
σ1 'αsCF
π
∫ Q2
1 GeV2
dk2t
k2t︸ ︷︷ ︸
finite (large)
∫dx dz
1− z[σh(zxp)− σh(xp)] q(x , 1 GeV2)︸ ︷︷ ︸
finite
In general: replace 1 GeV2 cutoff with arbitrary factorization scale µ2F .
Gavin Salam (CERN) QCD basics 3 12 / 32
Collinear cutoff[Initial-state splitting]
[1st order analysis]
Q 2
pxp
zxp
(1−z)xp
σh
µ 2
By what right did we go to kt = 0?
We assumed pert. QCD to be valid forall scales, but below 1 GeV it becomesnon-perturbative.
Cut out this divergent region, & insteadput non-perturbative quark distributionin proton.
σ0 =
∫dx σh(xp) q(x , µ2
F )
σ1 'αsCF
π
∫ Q2
µ2F
dk2t
k2t︸ ︷︷ ︸
finite (large)
∫dx dz
1− z[σh(zxp)− σh(xp)] q(x , µ2
F )︸ ︷︷ ︸finite
In general: replace 1 GeV2 cutoff with arbitrary factorization scale µ2F .
Gavin Salam (CERN) QCD basics 3 12 / 32
Summary so far[Initial-state splitting]
[1st order analysis]
I Collinear divergence for incoming partons not cancelled by virtuals.Real and virtual have different longitudinal momenta
I Situation analogous to renormalization: need to regularize (but in IRinstead of UV).
Technically, often done with dimensional regularization
I Physical sense of regularization is to separate (factorize) protonnon-perturbative dynamics from perturbative hard cross section.
Choice of factorization scale, µ2, is arbitrary between 1 GeV2 and Q2
I In analogy with running coupling, we can vary factorization scale and geta renormalization group equation for parton distribution functions.
Dokshizer Gribov Lipatov Altarelli Parisi equations (DGLAP)
Gavin Salam (CERN) QCD basics 3 13 / 32
Summary so far[Initial-state splitting]
[1st order analysis]
I Collinear divergence for incoming partons not cancelled by virtuals.Real and virtual have different longitudinal momenta
I Situation analogous to renormalization: need to regularize (but in IRinstead of UV).
Technically, often done with dimensional regularization
I Physical sense of regularization is to separate (factorize) protonnon-perturbative dynamics from perturbative hard cross section.
Choice of factorization scale, µ2, is arbitrary between 1 GeV2 and Q2
I In analogy with running coupling, we can vary factorization scale and geta renormalization group equation for parton distribution functions.
Dokshizer Gribov Lipatov Altarelli Parisi equations (DGLAP)
Q2
increase
Q2
increase
u
u
u
g
gg
du
ud d
ug
gu
u
Gavin Salam (CERN) QCD basics 3 13 / 32
DGLAP equation (q ← q)[Initial-state splitting]
[DGLAP]
Change convention: (a) now fix outgoing longitudinal momentum x ; (b)take derivative wrt factorization scale µ2
p
x
xp
x
x/z x(1−z)/z
(1+δ)µ2(1+δ)µ2
µ 2µ 2
+
dq(x , µ2)
d lnµ2=αs
2π
∫ 1
xdz pqq(z)
q(x/z , µ2)
z− αs
2π
∫ 1
0dz pqq(z) q(x , µ2)
pqq is real q ← q splitting kernel: pqq(z) = CF1 + z2
1− z
Until now we approximated it in soft (z → 1) limit, pqq ' 2CF
1−z
Gavin Salam (CERN) QCD basics 3 14 / 32
DGLAP rewritten[Initial-state splitting]
[DGLAP]
Awkward to write real and virtual parts separately. Use more compactnotation:
dq(x , µ2)
d lnµ2=αs
2π
∫ 1
xdz Pqq(z)
q(x/z , µ2)
z︸ ︷︷ ︸Pqq⊗q
, Pqq = CF
(1 + z2
1− z
)+
This involves the plus prescription:∫ 1
0dz [g(z)]+ f (z) =
∫ 1
0dz g(z) f (z)−
∫ 1
0dz g(z) f (1)
z = 1 divergences of g(z) cancelled if f (z) sufficiently smooth at z = 1
Gavin Salam (CERN) QCD basics 3 15 / 32
DGLAP flavour structure[Initial-state splitting]
[DGLAP]
Proton contains both quarks and gluons — so DGLAP is a matrix in flavourspace:
d
d ln Q2
(qg
)=
(Pq←q Pq←g
Pg←q Pg←g
)⊗(
qg
)[In general, matrix spanning all flavors, anti-flavors, Pqq′ = 0 (LO), Pqg = Pqg ]
Splitting functions are:
Pqg (z) = TR
[z2 + (1− z)2
], Pgq(z) = CF
[1 + (1− z)2
z
],
Pgg (z) = 2CA
[z
(1− z)++
1− z
z+ z(1− z)
]+ δ(1− z)
(11CA − 4nf TR)
6.
Have various symmetries / significant properties, e.g.
I Pqg , Pgg : symmetric z ↔ 1− z (except virtuals)
I Pqq, Pgg : diverge for z → 1 soft gluon emission
I Pgg , Pgq: diverge for z → 0 Implies PDFs grow for x → 0
2015 EPS HEP prize to Bjorken, Altarelli, Dokshitzer, Lipatov & Parisi
Gavin Salam (CERN) QCD basics 3 16 / 32
DGLAP flavour structure[Initial-state splitting]
[DGLAP]
Proton contains both quarks and gluons — so DGLAP is a matrix in flavourspace:
d
d ln Q2
(qg
)=
(Pq←q Pq←g
Pg←q Pg←g
)⊗(
qg
)[In general, matrix spanning all flavors, anti-flavors, Pqq′ = 0 (LO), Pqg = Pqg ]
Splitting functions are:
Pqg (z) = TR
[z2 + (1− z)2
], Pgq(z) = CF
[1 + (1− z)2
z
],
Pgg (z) = 2CA
[z
(1− z)++
1− z
z+ z(1− z)
]+ δ(1− z)
(11CA − 4nf TR)
6.
Have various symmetries / significant properties, e.g.
I Pqg , Pgg : symmetric z ↔ 1− z (except virtuals)
I Pqq, Pgg : diverge for z → 1 soft gluon emission
I Pgg , Pgq: diverge for z → 0 Implies PDFs grow for x → 0
2015 EPS HEP prize to Bjorken, Altarelli, Dokshitzer, Lipatov & Parisi
Gavin Salam (CERN) QCD basics 3 16 / 32
Higher-order calculations[Initial-state splitting]
[DGLAP]
P (1)ps (x) = 4 CF nf
(20
9
1
x− 2 + 6x − 4H0 + x2
[8
3H0 −
56
9
]+ (1 + x)
[5H0 − 2H0,0
])
P (1)qg (x) = 4 CAnf
(20
9
1
x− 2 + 25x − 2pqg(−x)H−1,0 − 2pqg(x)H1,1 + x2
[44
3H0 −
218
9
]+4(1 − x)
[H0,0 − 2H0 + xH1
]− 4ζ2x − 6H0,0 + 9H0
)+ 4 CF nf
(2pqg(x)
[H1,0 + H1,1 + H2
−ζ2
]+ 4x2
[H0 + H0,0 +
5
2
]+ 2(1 − x)
[H0 + H0,0 − 2xH1 +
29
4
]−
15
2− H0,0 −
1
2H0
)
P (1)gq (x) = 4 CACF
(1
x+ 2pgq(x)
[H1,0 + H1,1 + H2 −
11
6H1
]− x2
[8
3H0 −
44
9
]+ 4ζ2 − 2
−7H0 + 2H0,0 − 2H1x + (1 + x)
[2H0,0 − 5H0 +
37
9
]− 2pgq(−x)H−1,0
)− 4 CF nf
(2
3x
−pgq(x)
[2
3H1 −
10
9
])+ 4 CF
2(pgq(x)
[3H1 − 2H1,1
]+ (1 + x)
[H0,0 −
7
2+
7
2H0
]− 3H0,0
+1 −3
2H0 + 2H1x
)
P (1)gg (x) = 4 CAnf
(1 − x −
10
9pgg(x) −
13
9
(1
x− x2
)−
2
3(1 + x)H0 −
2
3δ(1 − x)
)+ 4 CA
2(
27
+(1 + x)
[11
3H0 + 8H0,0 −
27
2
]+ 2pgg(−x)
[H0,0 − 2H−1,0 − ζ2
]−
67
9
(1
x− x2
)− 12H0
−44
3x2
H0 + 2pgg(x)
[67
18− ζ2 + H0,0 + 2H1,0 + 2H2
]+ δ(1 − x)
[8
3+ 3ζ3
])+ 4 CF nf
(2H0
+2
3
1
x+
10
3x2 − 12 + (1 + x)
[4 − 5H0 − 2H0,0
]−
1
2δ(1 − x)
).
NLO:
Pab =αs
2πP(0)+
α2s
16π2P(1)
Curci, Furmanski
& Petronzio ’80
Gavin Salam (CERN) QCD basics 3 17 / 32
NNLO splitting functions[Initial-state splitting]
[DGLAP]
Divergences for x�
1 are understood in the sense of✁
-distributions.
The third-order pure-singlet contribution to the quark-quark splitting function (2.4), corre-
sponding to the anomalous dimension (3.10), is given by
P✂
2✄
ps
☎x
✆✝ 16CACFnf
✞4
3
☎ 1
x
✁x2✆✟ 13
3H✠ 1✡ 0
☛ 14
9H0
✁ 1
2H✠ 1ζ2
☛ H✠ 1✡✠ 1✡ 0☛ 2H✠ 1✡ 0✡ 0
☛ H✠ 1✡ 2
☞✁ 2
3
☎ 1
x☛ x2✆✟ 16
3ζ2
✁H2✡ 1
✁9ζ3
✁ 9
4H1✡ 0
☛ 6761
216
✁ 571
72H1
✁ 10
3H2
✁H1ζ2
☛ 1
6H1✡ 1
☛ 3H1✡ 0✡ 0✁
2H1✡ 1✡ 0✁
2H1✡ 1✡ 1
☞✁☎
1☛ x✆✟ 182
9H1
✁ 158
3
✁ 397
36H0✡ 0
☛ 13
2H✠ 2✡ 0
✁3H0✡ 0✡ 0✡ 0
✁ 13
6H1✡ 0
✁3xH1✡ 0
✁H✠ 3✡ 0
✁H✠ 2ζ2
✁2H✠ 2✡✠ 1✡ 0
✁3H✠ 2✡ 0✡ 0
✁ 1
2H0✡ 0ζ2
✁ 1
2H1ζ2
☛ 9
4H1✡ 0✡ 0
☛ 3
4H1✡ 1
✁H1✡ 1✡ 0
✁H1✡ 1✡ 1
☞✁☎
1✁
x✆✟
7
12H0ζ2
✁ 31
6ζ3
✁ 91
18H2
✁ 71
12H3
✁ 113
18ζ2
☛ 826
27H0
✁ 5
2H2✡ 0
✁ 16
3H✠ 1✡ 0
✁6xH✠ 1✡ 0
✁ 31
6H0✡ 0✡ 0
☛ 17
6H2✡ 1
✁ 117
20ζ2
2✁9H0ζ3
✁ 5
2H✠ 1ζ2
✁2H2✡ 1✡ 0
✁ 1
2H✠ 1✡ 0✡ 0
☛ 2H✠ 1✡ 2✁
H2ζ2☛ 7
2H2✡ 0✡ 0
✁H✠ 1✡✠ 1✡ 0
✁2H2✡ 1✡ 1
✁H3✡ 1
☛ 1
2H4
☞✁
5H✠ 2✡ 0✁
H2✡ 1
✁H0✡ 0✡ 0✡ 0
☛ 1
2ζ2
2✁4H✠ 3✡ 0
✁4H0ζ3
☛ 32
9H0✡ 0
☛ 29
12H0
☛ 235
12ζ2
☛ 511
12☛ 97
12H1
✁ 33
4H2
☛ H3
☛ 11
2H0ζ2
☛ 11
2ζ3
☛ 3
2H2✡ 0
☛ 10H0✡ 0✡ 0✁ 2
3x2
✟83
4H0✡ 0
☛ 243
4H0
✁10ζ2
✁ 511
8
✁ 97
8H1
☛ 4
3H2
☛ 4ζ3☛ H0ζ2✁
H3✁
H2✡ 0☛ 6H✠ 2✡ 0
☞✌✁
16CFnf2
✞2
27H0
☛ 2☛ H2✁
ζ2✁ 2
3x2
✟
H2☛ ζ2✁
3
☛ 19
6H0
☞✁ 2
9
☎ 1
x☛ x2✆✟
H1✡ 1✁ 5
3H1
✁ 2
3
☞✁☎
1☛ x✆✟ 1
6H1✡ 1
☛ 7
6H1
✁xH1
✁ 35
27H0
✁ 185
54
☞
✁ 1
3
☎1
✁x
✆✟ 4
3H2
☛ 4
3ζ2
✁ζ3
✁H2✡ 1
☛ 2H3✁
2H0ζ2✁ 29
6H0✡ 0
✁H0✡ 0✡ 0
☞✌✁
16CF2nf
✞85
12H1
☛ 25
4H0✡ 0
☛ H0✡ 0✡ 0✁ 583
12H0
☛ 101
54
✁ 73
4ζ2
☛ 73
4H2
✁H3
☛ 5H2✡ 0☛ H2✡ 1☛ H0ζ2✁
x2✟
55
12
☛ 85
12H1
☛ 22
3H0✡ 0
☛ 109
6☛ 13
54H0
✁ 28
9ζ2
☛ 28
9H2
☛ 16
3H0ζ2
✁ 16
3H3
✁4H2✡ 0
✁ 4
3H2✡ 1
☛ 26
3ζ3
✁ 22
3H0✡ 0✡ 0
☞✁ 4
3
☎ 1
x☛ x2✆✟ 23
12H1✡ 0
☛ 523
144H1
☛ 3ζ3✁ 55
16
✁ 1
2H1✡ 0✡ 0
✁H1✡ 1
☛ H1✡ 1✡ 0☛ H1✡ 1✡ 1
☞
✁☎1☛ x
✆✟
1
2H1✡ 0✡ 0
✁ 7
12H1✡ 1
☛ 2743
72H0
☛ 53
12H0✡ 0
☛ 251
12H1
☛ 5
4ζ2
✁ 5
4H2
☛ 8
3H1✡ 0
✁3xH1✡ 0
✁3H0ζ2
☛ 3H3☛ H1✡ 1✡ 0☛ H1✡ 1✡ 1
☞✁☎
1✁
x✆✟ 1669
216
✁ 5
2H0✡ 0✡ 0
✁4H2✡ 1
✁7H2✡ 0
✁10xζ3
☛ 37
10ζ2
2
☛ 7H0ζ3✁
6H0✡ 0ζ2☛ 4H0✡ 0✡ 0✡ 0✁
H2✡ 0✡ 0☛ 2H2✡ 1✡ 0☛ 2H2✡ 1✡ 1☛ 4H3✡ 0☛ H3✡ 1☛ 6H4
☞✌✍ (4.12)
Due to Eqs. (3.11) and (3.12) the three-loop gluon-quark and quark-gluon splitting functions read
P
✂2
✄
qg
☎x
✆✝ 16CACFnf
✞
pqg
☎x
✆✟ 39
2H1ζ3
☛ 4H1✡ 1✡ 1✁
3H2✡ 0✡ 0☛ 15
4H1✡ 2
✁ 9
4H1✡ 1✡ 0
✁3H2✡ 1✡ 0
✁H0ζ3
☛ 2H2✡ 1✡ 1✁
4H2ζ2☛ 173
12H0ζ2
☛ 551
72H0✡ 0
✁ 64
3ζ3
☛ ζ22☛ 49
4H2
☛ 3
2H1✡ 0✡ 0✡ 0
☛ 1
3H1✡ 0✡ 0
16
385
72H1 0
31
2H1 1
113
12H1
49
4H2 0
5
2H1ζ2
79
6H0 0 0
173
12H3
1259
32
2833
216H0
6H2 1 3H1 2 0 9H1 0ζ2 6H1 1ζ2 H1 1 0 0 3H1 1 1 0 4H1 1 1 1 3H1 1 2 6H1 2 1
6H1 349
4ζ2 pqg x
17
2H 1ζ3
5
2H 1 1 0
5
2H 1 2
9
2H 1 0
5
2H 2 0
3
2H 1 0 0
2H3 1 2H4 6H 2 2 6H 2 1 0 6H 2 0 0 2H0 0ζ2 9H 2ζ2 3H 1 2 0 2H 1 2 1
6H 1 1 1 0 6H 1 1 0 0 6H 1 1 2 9H 1 0ζ2 9H 1 1ζ2 2H 1 2 011
2H 1 0 0 0
6H 1 31
xx2 55
124ζ3
23
9H1 0
4
3H1 1 0
1
xx2 2
3H1 0 0
371
108H1
23
9H1 1
2
3H1 1 1 1 x 6H2 1 0 3H2 1 1
5
6H1 1 1 7H2 0 0 2H1 2 39H0ζ3 4H2ζ2
16
3ζ3
H1 1 0154
3H0ζ2
899
24H0 0
121
10ζ2
2 607
36H2
5
2H1ζ2
65
6H1 0 0
29
12H1 0
13
18H1 1
1189
108H1
67
3H2 1 29H2 0
949
36ζ2
67
2H0 0 0
142
3H3
215
32
3989
48H0 2H 3 0
1 x H 1 0 0 10H 2ζ2 6H 2 0 0 2H0 0ζ2 9H 1 1 0 7H 1 2 9H 2 0 2H3 1
4H 2 1 0 4H4 4H3 0 4H0 0 0 037
2H 1 0
5
21 x H 1ζ2 4H 2 0 0 2H0 0ζ2
H2ζ2 3H1 1 0 2H0 0 0 0 H 3 0 9H2 1 09
2H2 1 1
11
3H1 1 1
19
2H2 0 0
9
2H1 2
91
2H0ζ3 8H 2ζ2
5
2H 1 1 0
5
2H 1 2
9
2H 1 0
39
2H 2 0
473
12H0ζ2
1853
48H0 0
217
12ζ3
59
4ζ2
2 169
18H2
13
4H1ζ2
2
3H1 0 0
167
24H1 0
191
18H1 1
1283
108H1
185
12H2 1
75
4H2 0
170
9ζ2
85
4H0 0 0
425
12H3
7693
192
3659
48H0 2x xH2 2 4H3 0 4H 2 2
16CAnf2 1
6pqg x H1 2 H1ζ2 H1 0 0 H1 1 0 H1 1 1
229
18H0
4
3H0 0
11
2x
1
6H2
53
18H0
17
6H0 0 ζ3
11
18ζ2
139
108
1
3pqg x H 1 0 0
53
162
1
xx2 2
91 x 6H0 0 0
7
6xH1 H0 0
7
2xH1 1
7
9x 1 x H 1 0
7
4H0
19
54H1 H0 0 0
5
9H1 1
5
9H 1 0
85
21616CA
2nf pqg x 3H1 331
6H1 0 0
17
2H2 1
7
5ζ2
2 55
12H1 1 0
31
12H3
31
2H1ζ3
5
12H2 0
63
8H1 0
23
12H1 2
155
6ζ3
25
24H2
2537
27H0
867
8
23
2H 1 0 0 3H4 H1 1 1
383
72H1 1
25
2H 2 0
3
8ζ2
7
4H1ζ2 3H0 0ζ2
31
12H0ζ2
103
216H1
5
2H1 0 0 0
2561
72H0 0
H1 1 1 2H2 0 0 3H1 2 0 5H1 0ζ2 3H0 0 0 H1 1ζ2 H1 1 0 0 4H1 1 1 0 2H1 1 1 1
2H1 1 2 2H1 2 0 pqg x H 1 1ζ2 2H 1 2 6H 1 1 0 H1 1 1 2H 2ζ2 H 2 0 0
727
36H 1 0 H 1ζ2 2H 2 2
5
2H 1ζ3 H 1 2 0 2H 1 1 0 0 2H 1 1 2
3
2H 1 0 0 0
17
6H 1 1 1 0 2H 1 3 2H 1 2 11
xx2 2
3H2 1
32
9ζ2 2H1 0 0
4
3H1 1 0
10
9H1 1
8
3H 1 0 0
3
2H1 0 6ζ3
161
36H1
2351
108
2
3
1
xx2 26
3H 1 0
28
9H0 2H 1 1 0
2H 1 2 H1ζ2 H 1ζ210
3H2 H1 1 1 1 x 15H0 0 0 0 5H2ζ2
65
6ζ3
11
6H1 1 1
3
2H4
5
2H0 0ζ2 H1 1 0
31
6H2 0
17
12H1 0
551
20ζ2
2 29
4H1 0 0
113
4H2
18691
72H0
2243
108
265
6H 1 0 0
33
2H2 0 0 19H2 1
31
12H1 1
23
2H 2 0
497
36ζ2
29
6H1ζ2
143
12H3
11
6H1 1 1
19
12H0ζ2
1223
72H1
43
6H0 0 0
3011
36H0 0 1 x 8H2 1 0 4H 1 2
7H 1 1 035
6H1 1 1 5H 2ζ2 11H 2 0 0
1
3H 1 0
15
2H 1ζ2 8H3 1 10H 2 1 0
5H2ζ2 4H2 1 1 H 3 0 36H0ζ3 5H2ζ2 2H 1 2 6H 1 1 0 6H2 1 0 3H2 1 1
11H0 0 0 0 5H3 125
4H1 1 1
13
2H 2ζ2
27
2H 2 0 0
11
2H 3 0
13
2H2ζ2
17
4H1 0 0
13H 2 1 017
12H1 1 1
3
4H4
1
4H0 0ζ2 H1 2
11
2H1 1 0
79
12H2 0
67
8H1 0
263
8ζ2
2
119
3ζ3
967
24H2
305
12H 1 0 24H0ζ3 H 1ζ2
13375
72H0
1889
1838H 1 0 0
21
2H2 1
79
4H2 0 0
217
24H1 1
7
2H 2 0
79
72ζ2
4
3H1ζ2
17
12H1 1 1
17
12H0ζ2
31
18H1 3H0 0 0
145
12H3
1553
24H0 0 16CFnf
2 7
6H0 0 0
11
36H1
739
96
163
24H0
7
24H0 0 2H0 0 0 0
5
9H1 1
5
9H2
5
18H1 0
5
9ζ2
1
6pqg x H2 1
91
2
35
3H0
22
3H0 0 H1 1 1 6H0 0 0
ζ3 2H1 0 07
9H1
77
81
1
xx2 1 x
1
12H1
6463
4324H0 0 0 0
16
3H0 0 0
7
9xH1 1
7
9xH2
8
9xH1 0
7
9xζ2 1 x
3475
216H0
103
12H0 0 16CF
2nf pqg x 7H1 3 7H4
2H 3 0 7H1ζ3 5H2 2 6H3 0 6H3 1 H2 1 0 4H2 0 0 3H2 1 2H2 1 15
2H2 0
61
8H2
61
8ζ2
87
8H1
11
2H1 2
61
8H1 1
17
2H1 0 7H0 0ζ2
5
2H1 0 0
5
2H1 1 0
19
2ζ3
81
32
11
2H3
11
2H0ζ2
7
2H1ζ2
15
2H0 0 0
87
8H0
11
5ζ2
23H1 1 1 5H2ζ2 7H0ζ3
11H0 0 2H1 2 0 7H1 0ζ2 3H1 0 0 0 5H1 1ζ2 4H1 1 0 0 H1 1 1 0 2H1 1 1 1 5H1 1 2
6H1 2 0 6H1 2 1 4pqg x H0 0 0 0 H 2 0 H 1 1 0 H 2 0 01
2H 1 2 0
5
8H 1 0
5
4H 1 0 0
1
2H 3 0
1
2H 1ζ2 H 1 1 0 0
1
4H 1 0 0 0 2 1 x H2 1 0 H2 0 0 H2 2
H3 1 2H3 0 2H 1ζ2 H1 2 H1 0 0 H1 1 0 H2ζ2 ζ22 43
8H2
49
8ζ2
13
8H1 1
18
and
✁ 655
576☛ 151
6ζ3
☛ 185
18H1✡ 1
✁ 1
6H1✡ 1✡ 1
☛ 95
9H2
✁ 29
6H2✡ 1
☛ 171
4H✠ 1✡ 0
☛ 12H✠ 1✡ 0✡ 0✁
7H✠ 1ζ2
✁16H✠ 1✡✠ 1✡ 0
✁ 5
3H2✡ 0
✁ 3
2H2✡ 1✡ 1
✁4H0✡ 0✡ 0✡ 0
☞☛ 35H✠ 2✡ 0☛ 179
27H0
✁ 2041
144H0✡ 0
☛ 19
6H0✡ 0✡ 0
☛ 2H3✡ 0☛ 13
2H0ζ2
☛ 13H✠ 3✡ 0☛ 13
2H3✡ 1
✁ 15
2H3
☛ 2005
64
✁ 157
4ζ2
✁8ζ3
✁ 1291
432H1
✁ 55
12H1✡ 1
✁ 3
2H2
✁ 1
2H2✡ 1
✁ 27
4H✠ 1✡ 0
☛ 11
2H1✡ 0✡ 0
☛ 8H2✡ 0✡ 0☛ 4ζ2
2✁ 3
2H1✡ 2
☛ H2✡ 2✁ 5
2H1ζ2
✁8H✠ 1✡✠ 1✡ 0
✁4H2✡ 0
✁ 3
2H2✡ 1✡ 1
☛ H✠ 1ζ2✁
7H2ζ2✁
6H✠ 2ζ2✁
12H✠ 2✡✠ 1✡ 0☛ 6H✠ 2✡ 0✡ 0✁
x
✟
3H1✡ 1✡ 1☛ H0✡ 0ζ2
✁ 9
2H✠ 1✡ 0✡ 0
☛ 35
8H1✡ 0
✁2H4
✁3H1✡ 1✡ 0
✁H✠ 1✡ 2
☞✌✁
16CA2CF
✞
x2✟
2
3H1ζ2
☛ 2105
81☛ 77
18H0✡ 0
☛ 6H3✁ 16
3ζ3
☛ 10H✠ 1✡ 0☛ 14
3H2✡ 0
☛ 2
3H✠ 1ζ2
☛ 14
3H0✡ 0✡ 0
✁ 104
9H2
☛ 4
3H1✡ 0✡ 0
✁ 37
9H1✡ 1
✁ 4
3H✠ 1✡✠ 1✡ 0
☛ 104
9ζ2
☛ 8
3H2✡ 1
✁ 145
18H1✡ 0
✁ 4
3H✠ 1✡ 2
✁ 2
3H1✡ 1✡ 1
☛ 109
27H1
✁ 8
3H✠ 1✡ 0✡ 0
✁6H0ζ2
✁4H✠ 2✡ 0
✁ 584
27H0
☞✁
pgq
☎x
✆✟ 7
2H1ζ3
✁ 138305
2592☛ 1
3H2✡ 0
✁ 13
4H✠ 1ζ2
✁2H2✡ 1✡ 1
✁ 11
2H1✡ 0✡ 0
✁4H3✡ 1
☛ 43
6H1✡ 1✡ 1
☛ 109
12ζ2
☛ 17
3H2✡ 1
☛ 71
24H1✡ 0
☛ 11
6H✠ 2✡ 0
☛ 21
2ζ3
✁ 3
2H1✡ 0✡ 0✡ 0
☛ H1✡✠ 2✡ 0
✁ 395
54H0
☛ 2H1✡ 0ζ2☛ H1✡ 1ζ2☛ 55
12H1✡ 1✡ 0
✁2H1✡ 1✡ 0✡ 0
✁4H1✡ 1✡ 1✡ 0
✁2H1✡ 1✡ 1✡ 1
✁4H1✡ 1✡ 2
☛ 55
12H1✡ 2
✁6H1✡ 2✡ 0
✁4H1✡ 2✡ 1
✁4H1✡ 3
✁3H2✡ 1✡ 0
✁3H2✡ 2
☞✁
pgq
☎☛ x✆✟ 23
2H✠ 1ζ3
✁5H✠ 2ζ2
✁2H✠ 2✡✠ 1✡ 0
✁ 109
12H✠ 1✡ 0
✁H0ζ3
✁ 17
5ζ2
2✁ 1
6H1ζ2
✁2H2ζ2
☛ 65
24H1✡ 1
☛ 19
2H✠ 1✡✠ 1✡ 0
☛ 4H3✡ 0☛ 3H2✡ 0✡ 0
☛ 7H✠ 2✡ 0✡ 0☛ 3
2H✠ 1✡ 2
✁ 3379
216H1
☛ 4H✠ 2✡ 2☛ 49
6H✠ 1✡ 0✡ 0
☛ 11
2H✠ 1✡ 0✡ 0✡ 0
☛ 13H✠ 1✡✠ 1ζ2☛ 8H✠ 1✡ 3
☛ 6H✠ 1✡✠ 1✡✠ 1✡ 0✁
12H✠ 1✡✠ 1✡ 0✡ 0✁
10H✠ 1✡✠ 1✡ 2✁
10H✠ 1✡ 0ζ2✁
5H✠ 1✡✠ 2✡ 0☛ 2H✠ 1✡ 2✡ 0☛ 2H✠ 1✡ 2✡ 1
✁ 11
6H0ζ2
☞✁☎
1☛ x✆✟ 41699
2592☛ 3H✠ 2✡✠ 1✡ 0☛ 3
2H✠ 2ζ2
☛ 128
9ζ2
☛ 4H3✡ 0✁ 26
3ζ3
☛ 5
2H✠ 2✡ 0✡ 0
☛ 7H1ζ2✁ 97
12H1✡ 0✡ 0
✁ 10
3H✠ 1✡ 0✡ 0
✁ 245
12H3
☛ 8H0✡ 0✡ 0✡ 0
☞✁☎
1✁
x✆✟
4H3✡ 1☛ H2✡ 1✡ 1✁ 29
6H✠ 1✡ 2
✁ 17
6H✠ 2✡ 0
☛ 12H2✡ 0☛ 31
12H2✡ 1
✁ 1
2H2✡ 0✡ 0
☛ H2ζ2✁ 61
36H1✡ 0
☛ 4H0ζ3☛ 13
3H✠ 1ζ2
☛ 46
3H✠ 1✡✠ 1✡ 0
✁ 25
4H4
✁ 93
4H0ζ2
☛ 55
9H1✡ 1
☛ 71
18H2
✁ 49
18H0✡ 0
☛ 13
2H0✡ 0ζ2
☛ 47
40ζ2
2☞✁ 6131
2592☛ 31
2H✠ 2ζ2
☛ 15H✠ 2✡✠ 1✡ 0✁ 9
2H✠ 1✡ 0✡ 0
☛ 3H2✡ 1✡ 1☛ 9
4H2✡ 1
✁ 53
3H✠ 2✡ 0
☛ 1
2H✠ 2✡ 0✡ 0
☛ 5H2✡ 0☛ 7
6H1✡ 1✡ 1
☛ 8H0ζ3
☛ 67
40ζ2
2✁ 29
6H✠ 1✡ 2
☛ H✠ 1✡ 0✁
8H✠ 2✡ 2✁
25H0ζ2✁ 412
9H1
✁ 928
9H0
✁ 1
4H4
☛ 65H3☛ 38H0✡ 0
☛ 9H✠ 3✡ 0☛ 17
3H0✡ 0✡ 0
✁x
✟27
2H✠ 1✡ 0
☛ 1
2H0✡ 0✡ 0✡ 0
✁ 3
4H0✡ 0ζ2
✁ 1
2H✠ 3✡ 0
☛ 14H0✡ 0✡ 0✁ 1
12H1✡ 1✡ 1
☛ 43
36ζ2
☛ 1
2H2ζ2
✁ 7
72H0
✁ 749
54H1
✁ 135
4ζ3
✁ 97
24H1✡ 0
✁ 43
12H1ζ2
☛ 85
12H✠ 1ζ2
☛ 13
3H1✡ 0✡ 0
20
53
12H2
39
4H1 1 2H3 1
13
6H 1 1 0
7
4H2 0 0 4H1 1 0 4H1 2 16CFnf
2 1
9
1
9
1
x2
9x
1
6xH1
1
6pgq x H1 1
5
3H1 16CF
2nf
4
9x2 H0 0
11
6H0
7
2H 1 0
1
3pgq x H1 2 H1 0 H1ζ2 9ζ3
83
12H1 1 2H 2 0
7
36H1 2H0ζ2
1625
48
3
2H1 0 0
2H1 1 05
2H1 1 1
31
18pgq x
95
93H0 ζ2 H 1 0
1
32 x 6H0 0 0 0 H3
13051
28813
2ζ3 4H 2 0 H2 0
1
2H1 0
1
2H2 1 2H0 0 0
653
24H0 0 1 x H0ζ2
1187
216H0
8
9H2
85
18H 1 0
101
18ζ2
80
27H0
23
18ζ2
1
3H1 1
5
4xH1 1
1
9H1
37
12xH1
23
18H 1 0
1501
54H0ζ2 H0 0 0
101
3H0 0
1
3H1 0 16CF
3 pgq x 3H1 1ζ2 3H1ζ27
2ζ2
23
8H1 1 8H1ζ3 6H1 2 0 2H1 0ζ2 3H1 1 0 3H1 1 0 0 H1 1 1 0 2H1 1 1 1 3H1 1 2
2H1 2 0 2H1 2 19
2H1 1 1
3
2H1 0 0
47
16
47
16H1
15
2ζ3 pgq x 2H 1 2 0
6H 1 1 0 3H 1ζ27
4H1 0
16
5ζ2
26H 1 0 0
7
2H 1 0 4H 1 1 0 0 2H 1 0ζ2
H 1 0 0 0 1 x 9H1 0 0 H1 1 1 10H1ζ2 3H0ζ3 H2 2 H2ζ2 H0 0 0 5H2 0 0
4H3 H2 1 1 3H0 0ζ2 3H3 1 3H4211
16H1
49
20ζ2
21 x 11ζ3
1
4H1 1
1
4H1 0
91
16H0 36H 1 0 8H 1 0 0 14H 1 1 0 7H 1ζ2 2H1 2 4H0ζ2 H2 1 2H 2 0 0
5H 2 011
2H2 2H0 0 0 0 2H 1 1 0 H 1ζ2
13
4ζ2
9
4H1 0
9
20ζ2
2 287
32
11
16H1
4H 1 0 0 16H 3 0 4H 2ζ2 8H 2 1 0 5H2ζ219
4H2 H2 2
35
8H0 0 9H0ζ3
25H 2 0 6H 2 0 03
2x
58
3ζ2
7
3H1ζ2 4H1 1
3
2H1 1 1
5
2H1 0 0
175
96H3 1
19
3ζ3
2H2 0 14H0 H0 0ζ2 H 1 0 H43
2H2 1
1
3H2 1 1 3H2 0 0
5
6H3 H1 2
7
6H0ζ2
2
3H1 1 0
29
6H0 0 0
185
8H0 0 (4.14)
Finally the Mellin inversion of Eq. (3.13) yields the NNLO gluon-gluon splitting function
P2
gg x 16CACFnf x2 4
9H2 3H1 0
97
12H1
8
3H 2 0
2
3H0ζ2
103
27H0
16
3ζ2 2H3
6H 1 0 2H2 0127
18H0 0
511
12pgg x 2ζ3
55
24
4
3
1
xx2 17
24H1 0
43
18H0
521
144H1
6923
432
1
2H2 1 2H1ζ2 H0ζ2 2H1 0 0
1
12H1 1 H1 1 0 H1 1 1
175
12H2
6H 1 0 8H0ζ3 6H 2 053
6H0ζ2
49
2H0
185
4ζ2
511
12
1
2H2 0 3H1 0 4H0 0 0 0
21
67
12H0 0
43
2ζ3 H2 1
97
12H1 4ζ2
2 9
2H3 8H 3 0
33
2H0 0 0
4
3
1
xx2 1
2H2 H2 0
11
3H 1 0 H 2 0
19
6ζ2 2ζ3 H 1ζ2 4H 1 1 0
1
2H 1 0 0 H 1 2 1 x 9H1ζ2
12H0 0 0 0293
108
61
6H0ζ2
7
3H1 0
857
36H1 9H0ζ3 16H 2 1 0 4H 2 0 0 8H 2ζ2
13
2H1 0 0
3
4H1 1 H1 1 0 H1 1 1 1 x
1
6H2 0
95
3H 1 0
149
36H2
3451
108H0
7H 2 0302
9H0 0
19
6H3
991
36ζ2
163
6ζ3
35
3H0 0 0
17
6H2 1
43
10ζ2
213H 1ζ2
18H 1 1 0 H3 1 6H4 4H 1 2 6H0 0ζ2 8H2ζ2 7H2 0 0 2H2 1 0 2H2 1 1 4H3 0
9H 1 0 0241
288δ 1 x 16CAnf
2 19
54H0
1
24xH0
1
27pgg x
13
54
1
xx2 5
3H1
1 x11
72H1
71
216
2
91 x ζ2
13
12xH0
1
2H0 0 H2
29
288δ 1 x
16CA2nf x2 ζ3
11
9ζ2
11
9H0 0
2
3H3
2
3H0ζ2
1639
108H0 2H 2 0
1
3pgg x
10
3ζ2
209
368ζ3 2H 2 0
1
2H0
10
3H0 0
20
3H1 0 H1 0 0
20
3H2 H3
10
9pgg x ζ2
2H 1 03
10H0ζ2 H0 0
1
3
1
xx2 H3 H0ζ2
13
3H2
5443
1083H1ζ2
205
36H1
13
3H1 0 H1 0 0
1
xx2 151
54H0
8
3ζ2
1
3H 1ζ2 ζ3 2H 1 1 0
2
3H 1 0 0
37
9H 1 0
2
3H 1 2 1 x
5
6H 2 0 H 3 0 2H0 0 0
269
36ζ2
4097
2163H 2ζ2
6H 2 1 0 3H 2 0 07
2H1ζ2
677
72H1 H1 0
7
4H1 0 0 1 x
193
36H2
11
2H 1ζ2
39
20ζ2
2 7
12H3
53
9H0 0
7
12H0ζ2
5
2H0 0ζ2 5ζ3 7H 1 1 0
77
6H 1 0
9
2H 1 0 0
2H 1 2 3H2ζ22
3H2 0
3
2H2 0 0
3
2H4
1
9ζ2 7H 2 0 2H2
458
27H0 H0 0ζ2
3
2ζ2
24H 3 0 x
131
12H0 0
8
3H0ζ2
7
2H3 H0 0 0 0
7
6H0 0 0
1943
216H0 6H0ζ3
δ 1 x233
288
1
6ζ2
1
12ζ2
2 5
3ζ3 16CA
3 x2 33H 2 0 33H0ζ21249
18H0 0
44H0 0 0110
3H3
44
3H2 0
85
6ζ2
6409
108H0 pgg x
245
24
67
9ζ2
3
10ζ2
2 11
3ζ3
4H 3 0 6H 2ζ2 4H 2 1 011
3H 2 0 4H 2 0 0 4H 2 2
1
6H0 7H0ζ3
67
9H0 0
8H0 0ζ2 4H0 0 0 0 6H1ζ3 4H1 2 0 10H2 0 0 6H1 0ζ2 8H1 0 0 0 8H1 1 0 0 8H4
134
9H1 0
11
6H1 0 0 8H1 2 0 8H1 3
134
9H2 4H2ζ2 8H3 1 8H2 2
11
6H3 10H3 0
8H2 1 0 pgg x11
2ζ2
2 11
6H0ζ2 4H 3 0 16H 2ζ2 12H 2 2
134
9H 1 0 2H2ζ2
8H 2 1 0 12H 1ζ3 18H 2 0 0 8H 1 2 0 16H 1 1ζ2 24H 1 1 0 0 16H 1 1 2
22
The large-
NNLO, P(2)ab : Moch, Vermaseren & Vogt ’04
Gavin Salam (CERN) QCD basics 3 18 / 32
Effect of (LO) DGLAP: initial quarks[Initial-state splitting]
[Example evolution]
0
0.5
1
1.5
2
2.5
3
0.01 0.1 1
x
xq(x,Q2), xg(x,Q
2)
Q2 = 12.0 GeV
2
xg(x,Q2)
xq + xqbar
Take example evolution starting withjust quarks:
∂lnQ2q = Pq←q ⊗ q∂lnQ2g = Pg←q ⊗ q
I quark is depleted at large x
I gluon grows at small x
Gavin Salam (CERN) QCD basics 3 19 / 32
Effect of (LO) DGLAP: initial quarks[Initial-state splitting]
[Example evolution]
0
0.5
1
1.5
2
2.5
3
0.01 0.1 1
x
xq(x,Q2), xg(x,Q
2)
Q2 = 15.0 GeV
2
xg(x,Q2)
xq + xqbar
Take example evolution starting withjust quarks:
∂lnQ2q = Pq←q ⊗ q∂lnQ2g = Pg←q ⊗ q
I quark is depleted at large x
I gluon grows at small x
Gavin Salam (CERN) QCD basics 3 19 / 32
Effect of (LO) DGLAP: initial quarks[Initial-state splitting]
[Example evolution]
0
0.5
1
1.5
2
2.5
3
0.01 0.1 1
x
xq(x,Q2), xg(x,Q
2)
Q2 = 27.0 GeV
2
xg(x,Q2)
xq + xqbar
Take example evolution starting withjust quarks:
∂lnQ2q = Pq←q ⊗ q∂lnQ2g = Pg←q ⊗ q
I quark is depleted at large x
I gluon grows at small x
Gavin Salam (CERN) QCD basics 3 19 / 32
Effect of (LO) DGLAP: initial quarks[Initial-state splitting]
[Example evolution]
0
0.5
1
1.5
2
2.5
3
0.01 0.1 1
x
xq(x,Q2), xg(x,Q
2)
Q2 = 35.0 GeV
2
xg(x,Q2)
xq + xqbar
Take example evolution starting withjust quarks:
∂lnQ2q = Pq←q ⊗ q∂lnQ2g = Pg←q ⊗ q
I quark is depleted at large x
I gluon grows at small x
Gavin Salam (CERN) QCD basics 3 19 / 32
Effect of (LO) DGLAP: initial quarks[Initial-state splitting]
[Example evolution]
0
0.5
1
1.5
2
2.5
3
0.01 0.1 1
x
xq(x,Q2), xg(x,Q
2)
Q2 = 46.0 GeV
2
xg(x,Q2)
xq + xqbar
Take example evolution starting withjust quarks:
∂lnQ2q = Pq←q ⊗ q∂lnQ2g = Pg←q ⊗ q
I quark is depleted at large x
I gluon grows at small x
Gavin Salam (CERN) QCD basics 3 19 / 32
Effect of (LO) DGLAP: initial quarks[Initial-state splitting]
[Example evolution]
0
0.5
1
1.5
2
2.5
3
0.01 0.1 1
x
xq(x,Q2), xg(x,Q
2)
Q2 = 60.0 GeV
2
xg(x,Q2)
xq + xqbar
Take example evolution starting withjust quarks:
∂lnQ2q = Pq←q ⊗ q∂lnQ2g = Pg←q ⊗ q
I quark is depleted at large x
I gluon grows at small x
Gavin Salam (CERN) QCD basics 3 19 / 32
Effect of (LO) DGLAP: initial quarks[Initial-state splitting]
[Example evolution]
0
0.5
1
1.5
2
2.5
3
0.01 0.1 1
x
xq(x,Q2), xg(x,Q
2)
Q2 = 90.0 GeV
2
xg(x,Q2)
xq + xqbar
Take example evolution starting withjust quarks:
∂lnQ2q = Pq←q ⊗ q∂lnQ2g = Pg←q ⊗ q
I quark is depleted at large x
I gluon grows at small x
Gavin Salam (CERN) QCD basics 3 19 / 32
Effect of (LO) DGLAP: initial quarks[Initial-state splitting]
[Example evolution]
0
0.5
1
1.5
2
2.5
3
0.01 0.1 1
x
xq(x,Q2), xg(x,Q
2)
Q2 = 150.0 GeV
2
xg(x,Q2)
xq + xqbar
Take example evolution starting withjust quarks:
∂lnQ2q = Pq←q ⊗ q∂lnQ2g = Pg←q ⊗ q
I quark is depleted at large x
I gluon grows at small x
Gavin Salam (CERN) QCD basics 3 19 / 32
Effect of (LO) DGLAP: initial gluons[Initial-state splitting]
[Example evolution]
0
1
2
3
4
5
0.01 0.1 1
x
xq(x,Q2), xg(x,Q
2)
Q2 = 12.0 GeV
2
xg(x,Q2)
xq + xqbar
2nd example: start with just gluons.
∂lnQ2q = Pq←g ⊗ g∂lnQ2g = Pg←g ⊗ g
I gluon is depleted at large x .
I high-x gluon feeds growth ofsmall x gluon & quark.
Gavin Salam (CERN) QCD basics 3 20 / 32
Effect of (LO) DGLAP: initial gluons[Initial-state splitting]
[Example evolution]
0
1
2
3
4
5
0.01 0.1 1
x
xq(x,Q2), xg(x,Q
2)
Q2 = 15.0 GeV
2
xg(x,Q2)
xq + xqbar
2nd example: start with just gluons.
∂lnQ2q = Pq←g ⊗ g∂lnQ2g = Pg←g ⊗ g
I gluon is depleted at large x .
I high-x gluon feeds growth ofsmall x gluon & quark.
Gavin Salam (CERN) QCD basics 3 20 / 32
Effect of (LO) DGLAP: initial gluons[Initial-state splitting]
[Example evolution]
0
1
2
3
4
5
0.01 0.1 1
x
xq(x,Q2), xg(x,Q
2)
Q2 = 27.0 GeV
2
xg(x,Q2)
xq + xqbar
2nd example: start with just gluons.
∂lnQ2q = Pq←g ⊗ g∂lnQ2g = Pg←g ⊗ g
I gluon is depleted at large x .
I high-x gluon feeds growth ofsmall x gluon & quark.
Gavin Salam (CERN) QCD basics 3 20 / 32
Effect of (LO) DGLAP: initial gluons[Initial-state splitting]
[Example evolution]
0
1
2
3
4
5
0.01 0.1 1
x
xq(x,Q2), xg(x,Q
2)
Q2 = 35.0 GeV
2
xg(x,Q2)
xq + xqbar
2nd example: start with just gluons.
∂lnQ2q = Pq←g ⊗ g∂lnQ2g = Pg←g ⊗ g
I gluon is depleted at large x .
I high-x gluon feeds growth ofsmall x gluon & quark.
Gavin Salam (CERN) QCD basics 3 20 / 32
Effect of (LO) DGLAP: initial gluons[Initial-state splitting]
[Example evolution]
0
1
2
3
4
5
0.01 0.1 1
x
xq(x,Q2), xg(x,Q
2)
Q2 = 46.0 GeV
2
xg(x,Q2)
xq + xqbar
2nd example: start with just gluons.
∂lnQ2q = Pq←g ⊗ g∂lnQ2g = Pg←g ⊗ g
I gluon is depleted at large x .
I high-x gluon feeds growth ofsmall x gluon & quark.
Gavin Salam (CERN) QCD basics 3 20 / 32
Effect of (LO) DGLAP: initial gluons[Initial-state splitting]
[Example evolution]
0
1
2
3
4
5
0.01 0.1 1
x
xq(x,Q2), xg(x,Q
2)
Q2 = 60.0 GeV
2
xg(x,Q2)
xq + xqbar
2nd example: start with just gluons.
∂lnQ2q = Pq←g ⊗ g∂lnQ2g = Pg←g ⊗ g
I gluon is depleted at large x .
I high-x gluon feeds growth ofsmall x gluon & quark.
Gavin Salam (CERN) QCD basics 3 20 / 32
Effect of (LO) DGLAP: initial gluons[Initial-state splitting]
[Example evolution]
0
1
2
3
4
5
0.01 0.1 1
x
xq(x,Q2), xg(x,Q
2)
Q2 = 90.0 GeV
2
xg(x,Q2)
xq + xqbar
2nd example: start with just gluons.
∂lnQ2q = Pq←g ⊗ g∂lnQ2g = Pg←g ⊗ g
I gluon is depleted at large x .
I high-x gluon feeds growth ofsmall x gluon & quark.
Gavin Salam (CERN) QCD basics 3 20 / 32
Effect of (LO) DGLAP: initial gluons[Initial-state splitting]
[Example evolution]
0
1
2
3
4
5
0.01 0.1 1
x
xq(x,Q2), xg(x,Q
2)
Q2 = 150.0 GeV
2
xg(x,Q2)
xq + xqbar
2nd example: start with just gluons.
∂lnQ2q = Pq←g ⊗ g∂lnQ2g = Pg←g ⊗ g
I gluon is depleted at large x .
I high-x gluon feeds growth ofsmall x gluon & quark.
Gavin Salam (CERN) QCD basics 3 20 / 32
DGLAP evolution[Initial-state splitting]
[Example evolution]
I As Q2 increases, partons lose longitudinal momentum; distributions allshift to lower x .
I gluons can be seen because they help drive the quark evolution.
Now consider data
Gavin Salam (CERN) QCD basics 3 21 / 32
DGLAP with initial gluon = 0[Determining gluon]
[Evolution versus data]
0
0.4
0.8
1.2
1.6
0.001 0.01 0.1 1
x
F2p (x,Q
2)
Q2 = 12.0 GeV
2
DGLAP: g(x,Q02) = 0
ZEUS
NMC
Fit quark distributions to F2(x ,Q20 ),
at initial scale Q20 = 12 GeV2.
NB: Q0 often chosen lower
Assume there is no gluon at Q20 :
g(x ,Q20 ) = 0
Use DGLAP equations to evolve tohigher Q2; compare with data.
Complete failure!
Gavin Salam (CERN) QCD basics 3 22 / 32
DGLAP with initial gluon = 0[Determining gluon]
[Evolution versus data]
0
0.4
0.8
1.2
1.6
0.001 0.01 0.1 1
x
F2p (x,Q
2)
Q2 = 15.0 GeV
2
DGLAP: g(x,Q02) = 0
ZEUS
NMC
Fit quark distributions to F2(x ,Q20 ),
at initial scale Q20 = 12 GeV2.
NB: Q0 often chosen lower
Assume there is no gluon at Q20 :
g(x ,Q20 ) = 0
Use DGLAP equations to evolve tohigher Q2; compare with data.
Complete failure!
Gavin Salam (CERN) QCD basics 3 22 / 32
DGLAP with initial gluon = 0[Determining gluon]
[Evolution versus data]
0
0.4
0.8
1.2
1.6
0.001 0.01 0.1 1
x
F2p (x,Q
2)
Q2 = 27.0 GeV
2
DGLAP: g(x,Q02) = 0
ZEUS
NMC
Fit quark distributions to F2(x ,Q20 ),
at initial scale Q20 = 12 GeV2.
NB: Q0 often chosen lower
Assume there is no gluon at Q20 :
g(x ,Q20 ) = 0
Use DGLAP equations to evolve tohigher Q2; compare with data.
Complete failure!
Gavin Salam (CERN) QCD basics 3 22 / 32
DGLAP with initial gluon = 0[Determining gluon]
[Evolution versus data]
0
0.4
0.8
1.2
1.6
0.001 0.01 0.1 1
x
F2p (x,Q
2)
Q2 = 35.0 GeV
2
DGLAP: g(x,Q02) = 0
ZEUS
NMC
Fit quark distributions to F2(x ,Q20 ),
at initial scale Q20 = 12 GeV2.
NB: Q0 often chosen lower
Assume there is no gluon at Q20 :
g(x ,Q20 ) = 0
Use DGLAP equations to evolve tohigher Q2; compare with data.
Complete failure!
Gavin Salam (CERN) QCD basics 3 22 / 32
DGLAP with initial gluon = 0[Determining gluon]
[Evolution versus data]
0
0.4
0.8
1.2
1.6
0.001 0.01 0.1 1
x
F2p (x,Q
2)
Q2 = 46.0 GeV
2
DGLAP: g(x,Q02) = 0
ZEUS
NMC
Fit quark distributions to F2(x ,Q20 ),
at initial scale Q20 = 12 GeV2.
NB: Q0 often chosen lower
Assume there is no gluon at Q20 :
g(x ,Q20 ) = 0
Use DGLAP equations to evolve tohigher Q2; compare with data.
Complete failure!
Gavin Salam (CERN) QCD basics 3 22 / 32
DGLAP with initial gluon = 0[Determining gluon]
[Evolution versus data]
0
0.4
0.8
1.2
1.6
0.001 0.01 0.1 1
x
F2p (x,Q
2)
Q2 = 60.0 GeV
2
DGLAP: g(x,Q02) = 0
ZEUS
NMC
Fit quark distributions to F2(x ,Q20 ),
at initial scale Q20 = 12 GeV2.
NB: Q0 often chosen lower
Assume there is no gluon at Q20 :
g(x ,Q20 ) = 0
Use DGLAP equations to evolve tohigher Q2; compare with data.
Complete failure!
Gavin Salam (CERN) QCD basics 3 22 / 32
DGLAP with initial gluon = 0[Determining gluon]
[Evolution versus data]
0
0.4
0.8
1.2
1.6
0.001 0.01 0.1 1
x
F2p (x,Q
2)
Q2 = 90.0 GeV
2
DGLAP: g(x,Q02) = 0
ZEUS Fit quark distributions to F2(x ,Q20 ),
at initial scale Q20 = 12 GeV2.
NB: Q0 often chosen lower
Assume there is no gluon at Q20 :
g(x ,Q20 ) = 0
Use DGLAP equations to evolve tohigher Q2; compare with data.
Complete failure!
Gavin Salam (CERN) QCD basics 3 22 / 32
DGLAP with initial gluon = 0[Determining gluon]
[Evolution versus data]
0
0.4
0.8
1.2
1.6
0.001 0.01 0.1 1
x
F2p (x,Q
2)
Q2 = 150.0 GeV
2
DGLAP: g(x,Q02) = 0
ZEUS Fit quark distributions to F2(x ,Q20 ),
at initial scale Q20 = 12 GeV2.
NB: Q0 often chosen lower
Assume there is no gluon at Q20 :
g(x ,Q20 ) = 0
Use DGLAP equations to evolve tohigher Q2; compare with data.
Complete failure!
Gavin Salam (CERN) QCD basics 3 22 / 32
DGLAP with initial gluon 6= 0[Determining gluon]
[Evolution versus data]
0
0.4
0.8
1.2
1.6
0.001 0.01 0.1 1
x
F2p (x,Q
2)
Q2 = 12.0 GeV
2
DGLAP (CTEQ6D)
ZEUS
NMC If gluon 6= 0, splitting g → qq gen-erates extra quarks at large Q2.
å faster rise of F2
Find a gluon distribution that leadsto correct evolution in Q2.
Done for us by CTEQ, MRST, . . .
PDF fitting collaborations.
Success!
Gavin Salam (CERN) QCD basics 3 23 / 32
DGLAP with initial gluon 6= 0[Determining gluon]
[Evolution versus data]
0
0.4
0.8
1.2
1.6
0.001 0.01 0.1 1
x
F2p (x,Q
2)
Q2 = 15.0 GeV
2
DGLAP (CTEQ6D)
ZEUS
NMC If gluon 6= 0, splitting g → qq gen-erates extra quarks at large Q2.
å faster rise of F2
Find a gluon distribution that leadsto correct evolution in Q2.
Done for us by CTEQ, MRST, . . .
PDF fitting collaborations.
Success!
Gavin Salam (CERN) QCD basics 3 23 / 32
DGLAP with initial gluon 6= 0[Determining gluon]
[Evolution versus data]
0
0.4
0.8
1.2
1.6
0.001 0.01 0.1 1
x
F2p (x,Q
2)
Q2 = 27.0 GeV
2
DGLAP (CTEQ6D)
ZEUS
NMC If gluon 6= 0, splitting g → qq gen-erates extra quarks at large Q2.
å faster rise of F2
Find a gluon distribution that leadsto correct evolution in Q2.
Done for us by CTEQ, MRST, . . .
PDF fitting collaborations.
Success!
Gavin Salam (CERN) QCD basics 3 23 / 32
DGLAP with initial gluon 6= 0[Determining gluon]
[Evolution versus data]
0
0.4
0.8
1.2
1.6
0.001 0.01 0.1 1
x
F2p (x,Q
2)
Q2 = 35.0 GeV
2
DGLAP (CTEQ6D)
ZEUS
NMC If gluon 6= 0, splitting g → qq gen-erates extra quarks at large Q2.
å faster rise of F2
Find a gluon distribution that leadsto correct evolution in Q2.
Done for us by CTEQ, MRST, . . .
PDF fitting collaborations.
Success!
Gavin Salam (CERN) QCD basics 3 23 / 32
DGLAP with initial gluon 6= 0[Determining gluon]
[Evolution versus data]
0
0.4
0.8
1.2
1.6
0.001 0.01 0.1 1
x
F2p (x,Q
2)
Q2 = 46.0 GeV
2
DGLAP (CTEQ6D)
ZEUS
NMC If gluon 6= 0, splitting g → qq gen-erates extra quarks at large Q2.
å faster rise of F2
Find a gluon distribution that leadsto correct evolution in Q2.
Done for us by CTEQ, MRST, . . .
PDF fitting collaborations.
Success!
Gavin Salam (CERN) QCD basics 3 23 / 32
DGLAP with initial gluon 6= 0[Determining gluon]
[Evolution versus data]
0
0.4
0.8
1.2
1.6
0.001 0.01 0.1 1
x
F2p (x,Q
2)
Q2 = 60.0 GeV
2
DGLAP (CTEQ6D)
ZEUS
NMC If gluon 6= 0, splitting g → qq gen-erates extra quarks at large Q2.
å faster rise of F2
Find a gluon distribution that leadsto correct evolution in Q2.
Done for us by CTEQ, MRST, . . .
PDF fitting collaborations.
Success!
Gavin Salam (CERN) QCD basics 3 23 / 32
DGLAP with initial gluon 6= 0[Determining gluon]
[Evolution versus data]
0
0.4
0.8
1.2
1.6
0.001 0.01 0.1 1
x
F2p (x,Q
2)
Q2 = 90.0 GeV
2
DGLAP (CTEQ6D)
ZEUSIf gluon 6= 0, splitting g → qq gen-erates extra quarks at large Q2.
å faster rise of F2
Find a gluon distribution that leadsto correct evolution in Q2.
Done for us by CTEQ, MRST, . . .
PDF fitting collaborations.
Success!
Gavin Salam (CERN) QCD basics 3 23 / 32
DGLAP with initial gluon 6= 0[Determining gluon]
[Evolution versus data]
0
0.4
0.8
1.2
1.6
0.001 0.01 0.1 1
x
F2p (x,Q
2)
Q2 = 150.0 GeV
2
DGLAP (CTEQ6D)
ZEUSIf gluon 6= 0, splitting g → qq gen-erates extra quarks at large Q2.
å faster rise of F2
Find a gluon distribution that leadsto correct evolution in Q2.
Done for us by CTEQ, MRST, . . .
PDF fitting collaborations.
Success!
Gavin Salam (CERN) QCD basics 3 23 / 32
Gluon distribution[Determining full PDFs]
[Global fits]
0
1
2
3
4
5
6
0.01 0.1 1
x
xq(x), xg(x)
Q2 = 10 GeV
2
uV
dS, uS
gluon
CTEQ6D fitGluon distribution is HUGE!
Can we really trust it?
I Consistency: momentum sum-ruleis now satisfied.
NB: gluon mostly at small x
I Agrees with vast range of data
Gavin Salam (CERN) QCD basics 3 24 / 32
DIS data and global fits[Determining full PDFs]
[Global fits]
x
Q2 /
GeV
2
y =
1
y = 0
.004
HERA Data:
H1 1994-2000
ZEUS 1994-1997
ZEUS BPT 1997
ZEUS SVX 1995
H1 SVX 1995, 2000
H1 QEDC 1997
Fixed Target Experiments:
NMC
BCDMS
E665
SLAC
10-1
1
10
102
103
104
10-6
10-5
10-4
10-3
10-2
10-1
1
Gavin Salam (CERN) QCD basics 3 25 / 32
DIS data and global fits[Determining full PDFs]
[Global fits]
x6
105
10 4103
10 210 110 1
]2
[ G
eV
2 T /
p2
/ M
2Q
1
10
210
310
410
510
610
710FT DIS
HERA1
FT DY
TEV EW
TEV JET
ATLAS EW
LHCB EW
LHC JETS
HERA2
ATLAS JETS 2.76TEV
ATLAS HIGH MASS
ATLAS WpT
CMS W ASY
CMS JETS
CMS WC TOT
CMS WC RAT
LHCB Z
TTBAR
NNPDF3.0 NLO dataset
Gavin Salam (CERN) QCD basics 3 25 / 32
Other processes[Determining full PDFs]
[Back to factorization]
Factorization of QCD cross-sections into convolution of:
I hard (perturbative) process-dependent partonic subprocess
I non-perturbative, process-independent parton distribution functions
e+
Q2
x1 x2
q(x, Q2) q1(x1, Q2) g2(x2, Q2)
proton proton 1 proton 2
qg −> 2 jetse+q −> e+ + jet
x
σep = σeq ⊗ q σpp→2 jets = σqg→2 jets ⊗ q1 ⊗ g2 + · · ·Gavin Salam (CERN) QCD basics 3 26 / 32
Other processes[Determining full PDFs]
[Back to factorization]
Factorization of QCD cross-sections into convolution of:
I hard (perturbative) process-dependent partonic subprocess
I non-perturbative, process-independent parton distribution functions
e+
Q2
x1 x2
q(x, Q2) q1(x1, Q2) g2(x2, Q2)
proton proton 1 proton 2
qg −> 2 jetse+q −> e+ + jet
x
σep = σeq ⊗ q σpp→2 jets = σqg→2 jets ⊗ q1 ⊗ g2 + · · ·Gavin Salam (CERN) QCD basics 3 26 / 32
Taking PDFs from HERA to LHC[Determining full PDFs]
[Back to factorization]
Suppose we produce a system ofmass M at LHC from partons withmomentum fractions x1, x2:
I M =√
x1x2s
I rapidity y =1
2ln
x1
x2pseudorapidity ≡ η ≡ ln tan θ
2
= rapidity for massless objects
. 5 at LHC
Are PDFs being used in region wheremeasured?
Only partial kinematic overlap
I DGLAP evolution is essential forthe prediction of PDFs in theLHC domain.
Gavin Salam (CERN) QCD basics 3 27 / 32
Taking PDFs from HERA to LHC[Determining full PDFs]
[Back to factorization]
⇐=DGLAP
⇐=DGLAP
Suppose we produce a system ofmass M at LHC from partons withmomentum fractions x1, x2:
I M =√
x1x2s
I rapidity y =1
2ln
x1
x2pseudorapidity ≡ η ≡ ln tan θ
2
= rapidity for massless objects
. 5 at LHC
Are PDFs being used in region wheremeasured?
Only partial kinematic overlap
I DGLAP evolution is essential forthe prediction of PDFs in theLHC domain.
Gavin Salam (CERN) QCD basics 3 27 / 32
Comparisons to hadron-collider data[Determining full PDFs]
[Back to factorization]M
uon
char
ge a
sym
met
ry
|ηµ|
CMS, √s=7 TeV, L=4.7 [fb]-1
PT > 25 GeV
CT14, 68% C.L.
0.10
0.15
0.20
0.25
0.30
0 0.5 1 1.5 2 2.5
Muo
n ch
arge
asy
mm
etry
|ηµ|
CMS, √s=7 TeV, L=4.7 [fb]-1
PT > 35 GeV
CT14, 68% C.L.
0.10
0.15
0.20
0.25
0.30
0 0.5 1 1.5 2 2.5
Ele
ctro
n ch
arge
asy
mm
etry
|ηe|
CMS, √s=7 TeV, L=840 [pb]-1
PT > 35 GeV
CT14, 68% C.L.0.08
0.12
0.16
0.20
0.24
0 0.5 1 1.5 2 2.5
FIG. 20: Charge asymmetry of decay muons and electrons from W ± production measured by the
CMS experiment. The data values have pT ℓ > 25 or 35 GeV for the muon data and pT ℓ > 35
GeV for the electron data. The vertical error bars on the data points include both statistical and
systematic uncertainties. The curve shows the CT14 theoretical calculation; the shaded region is
the PDF uncertainty at 68% C.L.
the missing transverse energy to be greater than 25 GeV, and the lepton-neutrino transverse
mass to be greater than 40 GeV.
The curve in Fig. 19 shows the NNLO theoretical calculation based on CT14 NNLO
PDFs. The shaded region is the PDF uncertainty at 68% C.L. Again the points with error
bars represent the unshifted data with total experimental errors added in quadrature. The
data fluctuate around the CT14 predictions and are described well by the CT14 error band.
Figure 20 presents a similar comparison of the unshifted data and CT14 NNLO theory for
the charge asymmetry of decay muons [46] and electrons [47] from inclusive W ± production
from the CMS experiment at the LHC 7 TeV. The asymmetry for muons is measured with
4.7 pb−1 of integrated luminosity, with pT ℓ > 25 and 35 GeV; the asymmetry for electrons is
36
Ele
ctro
n ch
arge
asy
mm
etry
|ηe|
D0, L=9.7 fb-1
CT14 NNLOCT14 NNLOCT10 NNLOCTEQ6.6 NLOE
eT > 25 GeV, ET,miss > 25 GeV
-0.8
-0.6
-0.4
-0.2
0.0
0.2
0 0.5 1 1.5 2 2.5 3
Ele
ctro
n ch
arge
asy
mm
etry
|ηe|
D0, L=0.75 fb-1
CT10 NNLOCT10 NNLOCT14 NNLOCTEQ6.6 NLOE
eT > 25 GeV, ET,miss > 25 GeV
-0.8
-0.6
-0.4
-0.2
0.0
0.2
0 0.5 1 1.5 2 2.5 3
FIG. 22: Charge asymmetry of decay electrons from W ± production measured by the DØ exper-
iment in Run-2 at the Tevatron. The data values have EeT > 25 GeV and ET,miss > 25 GeV. The
curve shows the CT14 theoretical calculation; the shaded region is the PDF uncertainty at 68%
C.L.
The
ory
- S
hift
ed D
ata
|ηe|
D0, L=9.7 fb-1
CT14 NNLOCT14 NNLOCT10 NNLOCTEQ6.6 NLO
-0.10
-0.05
0.00
0.05
0 0.5 1 1.5 2 2.5 3
The
ory
- S
hift
ed D
ata
|ηe|
D0, L=0.75 fb-1
CT10 NNLOCT10 NNLOCT14 NNLOCTEQ6.6 NLO
-0.2
-0.1
0.0
0.1
0.2
0 0.5 1 1.5 2 2.5 3
FIG. 23: Same as Fig. 22, plotted as the Charge asymmetry as the difference between theory and
shifted data for Ach from DØ Run-2 (9.7 fb−1).
E. Constraints on strangeness PDF from CCFR, NuTeV, and LHC experiments
Let us now turn to the strangeness PDF s(x, Q), which has become smaller at x > 0.05 in
CT14 compared to our previous analyses, CT10 and CTEQ6.6. Although the CT14 central
s(x, Q) lies within the error bands of either earlier PDF set, it is important to verify that the
new result is consistent with the data that are sensitive to the strange-quark PDF. With our
selection of experiments, four related fixed-target measurements are known to be sensitive
to s(x, Q): these are the measurements of dimuon production in neutrino and antineutrino
39
NLO
NNLO1�
d�d|yZ |
CMS Z, 20 < M < 30 GeV
.
0.05
0.04
0.03
0.02
0.01
.
|yZ|
Data
/T
heo
ry
21.510.50
1.2
1.1
1
0.9
NLO
NNLO1�
d�d|yZ |
CMS Z, 30 < M < 45 GeV
.
0.06
0.05
0.04
0.03
0.02
0.01
.
|yZ|
Data
/T
heo
ry
21.510.50
1.1
1
0.9
NLO
NNLO1�
d�d|yZ |
CMS Z, 45 < M < 60 GeV
.
0.03
0.02
0.01
.
|yZ|
Data
/T
heo
ry
21.510.50
1.2
1.1
1
0.9
NLO
NNLO1�
d�d|yZ |
CMS Z, 60 < M < 120 GeV
.
0.7
0.6
0.5
0.4
0.3
0.2
0.1
.
|yZ|
Data
/T
heo
ry
21.510.50
1.1
1
0.9
NLO
NNLO1�
d�d|yZ |
CMS Z, 120 < M < 200 GeV
.
0.008
0.007
0.006
0.005
0.004
0.003
0.002
0.001
.
|yZ|
Data
/T
heo
ry
21.510.50
1.2
1.1
1
0.9
0.8
NLO
NNLO1�
d�d|yZ |
CMS Z, 200 < M < 1500 GeV
.
0.002
0.0015
0.001
0.0005
.
|yZ |
Data
/T
heo
ry
21.510.50
1.4
1.2
1
0.8
0.6
Figure 11: The fit quality for the CMS double di↵erential Drell-Yan data for (1/�Z) · d�/d|yZ |versus |yZ |, in [78], for the lowest two mass bins (20 < M < 30 GeV and 30 < M < 45 GeV)
(top), the mass bins (45 < M < 60 GeV and 60 < M < 120 GeV) (middle) and the mass bins
(120 < M < 200 GeV and 200 < M < 1500 GeV) (bottom), at NLO and NNLO. Note that
correlated uncertainties are made available in the form of a correlation matrix, so the shift of data
relative to theory cannot be shown.
23
MMHT v. Z rapidity @
CMS
Lepton charge asym. v. CT14 @ D0 & CMS
NLO, ATLAS jets (7 TeV), 0.0 < |y| < 0.3
.
pT [GeV]
Dat
a/T
heo
ry
1000100
1
NLO, ATLAS jets (7 TeV), 0.3 < |y| < 0.8
.
pT [GeV]
Dat
a/T
heo
ry
1000100
1
NLO, ATLAS jets (7 TeV), 0.8 < |y| < 1.2
.
pT [GeV]
Dat
a/T
heo
ry
1000100
1
NLO, ATLAS jets (7 TeV), 1.2 < |y| < 2.1
.
pT [GeV]
Dat
a/T
heo
ry
1000100
1
NLO, ATLAS jets (7 TeV), 2.1 < |y| < 2.8
.
pT [GeV]
Dat
a/T
heo
ry
1000100
1
NLO, ATLAS jets (7 TeV), 2.8 < |y| < 3.6
.
pT [GeV]
Dat
a/T
heo
ry
1000100
1
NLO, ATLAS jets (7 TeV), 3.6 < |y| < 4.4
.
pT [GeV]
Dat
a/T
heo
ry
1000100
1
Figure 13: The fit quality for the ATLAS 7 TeV jet data in various rapidity intervals [99] at
NLO. The red points represent unshifted data and theory, and the black points (clustering around
Data/Theory=1) correspond to data and theory shifted using correlated systematics.
28
ATLAS inclusive jetsratio to MMHT
Gavin Salam (CERN) QCD basics 3 28 / 32
Precision of today’s PDFs (from PDF4LHC)[Determining full PDFs]
[Back to factorization]
x 5−10 4−10 3−10 2−10 1−10
) [r
ef]
2)
/ u (
x, Q
2u
( x,
Q
0.85
0.9
0.95
1
1.05
1.1
1.15
1.2
1.25
1.3
NNPDF3.0
CT14
MMHT14
2 = 100 GeV2NNLO, Q
up quark
x 5−10 4−10 3−10 2−10 1−10
) [r
ef]
2)
/ d (
x, Q
2d
( x,
Q
0.85
0.9
0.95
1
1.05
1.1
1.15
1.2
1.25
1.3
NNPDF3.0
CT14
MMHT14
2 = 100 GeV2NNLO, Q
down quark
x 5−10 4−10 3−10 2−10 1−10
) [r
ef]
2)
/ g (
x, Q
2g
( x,
Q
0.85
0.9
0.95
1
1.05
1.1
1.15
1.2
1.25
1.3
NNPDF3.0
CT14
MMHT14
2 = 100 GeV2NNLO, Q
gluon
x 5−10 4−10 3−10 2−10 1−10
) [r
ef]
2 (
x, Q
+)
/ s2
( x
, Q+ s
0.8
0.9
1
1.1
1.2
1.3
1.4
NNPDF3.0
CT14
MMHT14
2 = 100 GeV2NNLO, Q
s + s
Gavin Salam (CERN) QCD basics 3 29 / 32
Precision of today’s PDFs (from PDF4LHC)[Determining full PDFs]
[Back to factorization]
x 5−10 4−10 3−10 2−10 1−10
) [r
ef]
2)
/ u (
x, Q
2u
( x,
Q
0.85
0.9
0.95
1
1.05
1.1
1.15
1.2
1.25
1.3
NNPDF3.0
CT14
MMHT14
2 = 100 GeV2NNLO, Q
up quark
x 5−10 4−10 3−10 2−10 1−10
) [r
ef]
2)
/ d (
x, Q
2d
( x,
Q
0.85
0.9
0.95
1
1.05
1.1
1.15
1.2
1.25
1.3
NNPDF3.0
CT14
MMHT14
2 = 100 GeV2NNLO, Q
down quark
x 5−10 4−10 3−10 2−10 1−10
) [r
ef]
2)
/ g (
x, Q
2g
( x,
Q
0.85
0.9
0.95
1
1.05
1.1
1.15
1.2
1.25
1.3
NNPDF3.0
CT14
MMHT14
2 = 100 GeV2NNLO, Q
gluon
x 5−10 4−10 3−10 2−10 1−10
) [r
ef]
2 (
x, Q
+)
/ s2
( x
, Q+ s
0.8
0.9
1
1.1
1.2
1.3
1.4
NNPDF3.0
CT14
MMHT14
2 = 100 GeV2NNLO, Q
s + s
Gavin Salam (CERN) QCD basics 3 29 / 32
In the range 10−3 < x < 0.1 manyparton distributions are known with
precisions of a couple of percent.
Conclusions on PDFs[Conclusions]
I Factorization is key to our ability carry out calculations for hadroncolliders
I Beyond leading order, factorization implies shuffling of divergencesbetween the PDFs and the perturbative part of the calculation
I Equation for (factorisation) scale dependence of PDFs is DGLAP
I Our knowledge of PDFs comes both from the direct DIS measurements(for quarks) and from the scale-dependence of those measurements (forgluons), as well as Tevatron & LHC data.
I Today’s precision on (some) PDFs approaches the percent level, which iscrucial for Higgs precision prospects.
Gavin Salam (CERN) QCD basics 3 30 / 32
PDF exercise 1[Conclusions]
Check that LO DGLAP evolution preserves the momentum sum ruleunchanged.
Hints:
I One way of doing this is to use Mellin moments: f(N)i/p (µ2) =
∫ 1
0dx xN fi/p(x , µ2)
I Which Mellin moment tells you about the momentum carried by parton flavouri?
I Show that the N th Mellin moment of the DGLAP convolution, i.e.∫ 1
0dx xN
∫ 1
xdzz P(z)f (x/z) is given by the product of the N th Mellin moments of
P and f , i.e. P(N)f (N) ≡∫ 1
0dz zNP(z)×
∫ 1
0dx xN f (x).
I Then work out the appropriate Mellin moments and you should be able to provemomentum conservation.
Gavin Salam (CERN) QCD basics 3 31 / 32
PDF exercise 2[Conclusions]
Show that at asymptotically large Q2, the fraction of a hadron’smomentum that is contained in the gluons tends to the value
2CF
2CF + nf TR
(and compare this to the result shown earlier in the slides)
Hints:
I write the evolution equation for the momentum in the quarks and gluons interms of Mellin moments as a differential matrix equation:
∂lnµ2
(Σ(N)(µ2)g (N)(µ2)
)=αs(µ
2)
2π
(P
(N)ΣΣ P
(N)Σg
P(N)gΣ P
(N)gg
)(Σ(N)(µ2)g (N)(µ2)
)where Σ corresponds to a sum over all quark flavours. Watch out for the factors
of 2 and nf in P(N)Σg .
I Examine the asymptotic solutions of this equation
Gavin Salam (CERN) QCD basics 3 32 / 32
EXTRAS
Gavin Salam (CERN) QCD basics 3 33 / 32
Anti-quarks in proton[Extras]
[Sea & valence]
u
d
u
u
d
u
u
u
u
d
u
u
u
d
d
How can there be infinite number ofquarks in proton?
Proton wavefunction fluctuates — extrauu, dd pairs (sea quarks) can appear:
Antiquarks also have distributions, u(x), d(x)
F2 =4
9(xu(x) + xu(x)) +
1
9(xd(x) + xd(x))
NB: photon interaction ∼ square of charge → +ve
I Previous transparency: we were actually looking at ∼ u + u, d + d
I Number of extra quark-antiquark pairs can be infinite, so∫dx (u(x) + u(x)) =∞
as long as they carry little momentum (mostly at low x)
Gavin Salam (CERN) QCD basics 3 34 / 32
Anti-quarks in proton[Extras]
[Sea & valence]
u
d
u
u
d
u
u
u
u
d
u
u
u
d
d
How can there be infinite number ofquarks in proton?
Proton wavefunction fluctuates — extrauu, dd pairs (sea quarks) can appear:
Antiquarks also have distributions, u(x), d(x)
F2 =4
9(xu(x) + xu(x)) +
1
9(xd(x) + xd(x))
NB: photon interaction ∼ square of charge → +ve
I Previous transparency: we were actually looking at ∼ u + u, d + d
I Number of extra quark-antiquark pairs can be infinite, so∫dx (u(x) + u(x)) =∞
as long as they carry little momentum (mostly at low x)
Gavin Salam (CERN) QCD basics 3 34 / 32
Anti-quarks in proton[Extras]
[Sea & valence]
u
d
u
u
d
u
u
u
u
d
u
u
u
d
d
How can there be infinite number ofquarks in proton?
Proton wavefunction fluctuates — extrauu, dd pairs (sea quarks) can appear:
Antiquarks also have distributions, u(x), d(x)
F2 =4
9(xu(x) + xu(x)) +
1
9(xd(x) + xd(x))
NB: photon interaction ∼ square of charge → +ve
I Previous transparency: we were actually looking at ∼ u + u, d + d
I Number of extra quark-antiquark pairs can be infinite, so∫dx (u(x) + u(x)) =∞
as long as they carry little momentum (mostly at low x)
Gavin Salam (CERN) QCD basics 3 34 / 32
“Valence” quarks[Extras]
[Sea & valence]
When we say proton has 2 up quarks & 1 down quark we mean∫dx (u(x)− u(x)) = 2 ,
∫dx (d(x)− d(x)) = 1
u − u = uV is known as a valence distribution.
How do we measure difference between u and u? Photon interactsidentically with both → no good. . .
Question: what interacts differently with particle & antiparticle?
Answer: W + or W−
Gavin Salam (CERN) QCD basics 3 35 / 32
“Valence” quarks[Extras]
[Sea & valence]
When we say proton has 2 up quarks & 1 down quark we mean∫dx (u(x)− u(x)) = 2 ,
∫dx (d(x)− d(x)) = 1
u − u = uV is known as a valence distribution.
How do we measure difference between u and u? Photon interactsidentically with both → no good. . .
Question: what interacts differently with particle & antiparticle?
Answer: W + or W−
Gavin Salam (CERN) QCD basics 3 35 / 32
“Valence” quarks[Extras]
[Sea & valence]
When we say proton has 2 up quarks & 1 down quark we mean∫dx (u(x)− u(x)) = 2 ,
∫dx (d(x)− d(x)) = 1
u − u = uV is known as a valence distribution.
How do we measure difference between u and u? Photon interactsidentically with both → no good. . .
Question: what interacts differently with particle & antiparticle?
Answer: W + or W−
Gavin Salam (CERN) QCD basics 3 35 / 32
By how much do PDFs evolve?[Extras]
[Size of PDF evolution]g(x
, Q
= 1
00 G
eV
) / g(x
, Q
= 2
GeV
)
x
Gluon evolution from 2 to 100 GeV
Input: CTEQ61 at Q = 2 GeV
Evolution: HOPPET 1.1.1
LO evolution
0.01
0.1
1
10
100
0.0001 0.001 0.01 0.1 1
Illustrate for the gluon distributionHere using fixed Q scales
But for HERA → LHC
relevant Q range is x-dependent
I See factors ∼ 0.1− 10
I Remember: LHC involves productof two parton densities
It’s crucial to get this right!
Without DGLAP evolution, you
couldn’t predict anything at LHC
Gavin Salam (CERN) QCD basics 3 36 / 32
Which PDF channels contribute?[Extras]
[Channels for dijet production]
Inclusive jet cross sections with MSTW 2008 NLO PDFs
(GeV)T
p100
Fra
cti
on
al co
ntr
ibu
tio
ns
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
= 1.96 TeVsTevatron,
jets→gg
jets→gq
jets→qq
0.1 < y < 0.7
(GeV)T
p100
Fra
cti
on
al co
ntr
ibu
tio
ns
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
(GeV)T
p100 1000
Fra
cti
on
al co
ntr
ibu
tio
ns
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
= 14 TeVsLHC,
algorithm with D = 0.7T
kT
= pF
µ = R
µfastNLO with
jets→gg
jets→gq
jets→qq
0.0 < y < 0.8
(GeV)T
p100 1000
Fra
cti
on
al co
ntr
ibu
tio
ns
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
A large fraction of jets are gluon-induced
Gavin Salam (CERN) QCD basics 3 37 / 32
Evolution uncertainty[Extras]
[Higher order uncertainties]uncert
ain
ty o
n g
(x, Q
= 1
00 G
eV
)
x
Uncert. on gluon ev. from 2 to 100 GeV
Input: CTEQ61 at Q = 2 GeV
Evolution: HOPPET 1.1.1
LO evolution
-0.4
-0.3
-0.2
-0.1
0
0.1
0.2
0.3
0.4
0.5
0.0001 0.001 0.01 0.1 1
Estimate uncertainties on evolutionby changing the scale used for αs in-side the splitting functions
Talk more about such
tricks in next lecture
I with LO evolution, uncertainty is∼ 30%
I NLO brings it down to ∼ 5%
I NNLO → 2% Commensurate with
data uncertainties
Gavin Salam (CERN) QCD basics 3 38 / 32
Evolution uncertainty[Extras]
[Higher order uncertainties]uncert
ain
ty o
n g
(x, Q
= 1
00 G
eV
)
x
Uncert. on gluon ev. from 2 to 100 GeV
Input: CTEQ61 at Q = 2 GeV
Evolution: HOPPET 1.1.1
LO evolution
NLO evolution
-0.4
-0.3
-0.2
-0.1
0
0.1
0.2
0.3
0.4
0.5
0.0001 0.001 0.01 0.1 1
Estimate uncertainties on evolutionby changing the scale used for αs in-side the splitting functions
Talk more about such
tricks in next lecture
I with LO evolution, uncertainty is∼ 30%
I NLO brings it down to ∼ 5%
I NNLO → 2% Commensurate with
data uncertainties
Gavin Salam (CERN) QCD basics 3 38 / 32
Evolution uncertainty[Extras]
[Higher order uncertainties]uncert
ain
ty o
n g
(x, Q
= 1
00 G
eV
)
x
Uncert. on gluon ev. from 2 to 100 GeV
Input: CTEQ61 at Q = 2 GeV
Evolution: HOPPET 1.1.1
LO evolution
NLO evolution
NNLO evolution
-0.4
-0.3
-0.2
-0.1
0
0.1
0.2
0.3
0.4
0.5
0.0001 0.001 0.01 0.1 1
Estimate uncertainties on evolutionby changing the scale used for αs in-side the splitting functions
Talk more about such
tricks in next lecture
I with LO evolution, uncertainty is∼ 30%
I NLO brings it down to ∼ 5%
I NNLO → 2% Commensurate with
data uncertainties
Gavin Salam (CERN) QCD basics 3 38 / 32