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Page 1: B = m (H M B H M Magnetization - ece.cmu.educit717/assets/images/Units.pdf · Some Useful Magnetic Units, Equations, and Definitions (mksa) B =m ... The magnetic field generated by

Carnegie Mellon UniversityCIT 39-717: Laboratory Methods in Data Storage Research

Data Storage Systems Center Page 1

Some Useful Magnetic Units, Equations, and Definitions (mksa)

( )MHB += 0µ Eq. 1a

B Magnetic flux density (Wb/m2, webers per square meter), equal to the flux per unit area Φ /A.µ 0 Permeability of free space (constant, 4π • 10–7 H/m, henries per meter).H Magnetic field (A/m, amperes per meter), produced by currents in conductors and equivalent currents in

magnetic materials.M Magnetization (A/m) or magnetic moment per unit volume (m/V).

Eq. 1a is sometimes written in one of the following formsMHB += 0µ Eq. 1b

MHB 0µ+= Eq. 1c

MHB += Eq. 1dwhere H and M adopt Wb/m2 units in the absence of µ 0.

Magnetization can only occur in a material. Therefore, in free space M = 0 and Eq. 1a reduces to B = µ 0H.

The magnetic field generated by a solenoid is given by

Lin

H⋅= Eq. 2

n Number of turns (dimensionless)i Current (A)L Length (m)

Starting with one of Maxwell’s equations:

tBE

∂∂−=×∇v

vvEq. 3a

we can find

( )

∫∫∫ ∫

⋅∂∂−=⋅

⋅∂∂−=⋅×∇

AC

A A

AdBt

ldE

AdBt

dAE

vvvv

vvvv

Eq. 3b

Substituting ∫ ⋅=ΦA

AdBvv

and ∫ ⋅=C

ldEVvv

yields Faraday’s Law:

tV

∂Φ∂−= . Eq. 3c

Physically, this means that the voltage produced in a coil of wire is equal to the time derivative of the magnetic flux(without any proportionality constants!). Note: if the flux is not changing, then no voltage will be producedregardless of the strength of the field. On the other hand, if the coil is in motion then the voltage produced will beproportional to both the field strength and the velocity.

Starting with another one of Maxwell’s equations:

tDJH

∂∂+=×∇v

vvvEq. 4a

assuming that there are no time-varying electronic fields (i.e., 0→∂∂

tDv

) and utilizing the Stokes theorem, we see

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Carnegie Mellon UniversityCIT 39-717: Laboratory Methods in Data Storage Research

Data Storage Systems Center Page 2

( )∫

∫ ∫=⋅

⋅=⋅×∇

Ctotal

A A

IldH

AdJAdHvv

vvvvv

Eq. 4b

also known as Ampere’s Law. We can use this to derive the field inside a solenoid (Eq. 2).

The remaining two Maxwell’s equations areρ=⋅∇ D

vv or ∫ ∫ ==⋅

S V

qdVSdD ρvv

Eq. 5a

and 0=⋅∇ Bvv

or ∫ =⋅S

SdB 0vv

Eq. 5b

The former, also known as Gauss’ Law, simply states that the electric flux through a closed surface is equal to theenclosed charge; this law is rarely used in magnetostatics. Eq. 5b, on the other hand, implies that there are nomagnetic monopoles – magnetic fields are always the result of a dipole.

Magnetic instruments and researchers often use a different set of units, including cgsa and English linear measures;for example, it is not uncommon to hear researchers in the DSSC talk about 10 Gbit/in2 areal density and 3000 Oemedia coercivity. Most scientists and engineers, however, use the mksa system. A short table is presented below,derived from Cullity1 and additional notes written in the margins:

1 B. D. Cullity, Introduction to Magnetic Materials, pp. 622-3, Addison-Wesley Publishing Company, Reading, Mass.; 1972.

Magnetism cgsa units mksa units B = H + 4π M B = µ 0(H + M)B in gauss (G) B in webers/meter2 (Wb) = tesla (T)H in oersteds (Oe) H in amperes/meter (A/m)M in emu/cm3 M in amperes/meterµ 0 (vacuum) = 1 µ 0 (vacuum) = 4π × 10-7 weber/(ampere meter) cgsa to mksa mksa to cgsa 1 G = 10-4 Wb/m2 1 Wb/m2 = 104 G1 Oe = 79.6 A/m 1 A/m = 12.57 × 10-3 Oe1 emu/cm3 = 12.57×10-4 Wb/m2 1 Wb/m2 = 796 emu/cm3

mksa only 1 Wb = 1 V s1 Wb/A = 1 H (inductance)

Length 1 angstrom (Å) = 10-10 m = 10-8 cm1 in = 0.0254 m = 2.54 cm1 mil = 10-3 in = 25.4 µm1 µ in = 10-6 in = 25.4 nm

Energy 1 erg = 10-7 J 1 J = 107 erg1 eV = 1.602 × 10-19 J 1 J = 6.25 × 1018 eV

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Carnegie Mellon UniversityCIT 39-717: Laboratory Methods in Data Storage Research

Data Storage Systems Center Page 3

The Biot-Savart law is useful for determining the field generated by various coil shapes:

∫ ×=C r

rlIdH

24ˆ

π

vv

Eq. 6

This can also be used to calculate the field generated by a solenoid.

Applied field energy density: θµµ cos00 ⋅⋅−=⋅−= HMHMEH

vvEq. 7a

Anisotropy energy density: θ2sinuK KE = Eq. 7b

Demagnetization energy density: ddd HMHME ⋅=⋅−= 00 21

21 µµ

vvEq. 7c