Attachment N. Design Example with Normal Weight Concrete Beam ...
Attachment (2)
5
Click here to load reader
-
Upload
santiagotabaresdim -
Category
Sports
-
view
55 -
download
3
Transcript of Attachment (2)
Taller M.T Sistemas 10°Circuito serie y paralelo
Julio 2013Nombre de los alumnosLISSETH YULIANA BURITICA
Simplifique los siguientes circuitos:
Punto 1
RESISTEN Ω
VOLTAJE V CORRIENTE A
POTENCIA W
R1=800 V1= 5.2 I1= 0.0065 P1= 0.0338R2= 3000 V2= 19.5 I2= 0.0065 P2= 0.1267RT= 3800 VT= 25 IT= 0.0065 PT=
0.1625
RT: R1 + R2
RT: 800 + 3800
RT: 3800 Ω
IT: VT/RT: 25/3800 = 0.0065 A
IT: I1+I2: 0.0065
V1: I1 + R1
V1: 0.0065 * 800: 5.2 V
V2: I2*R2
V2: 0.0065*3000: 19.5V
P1: I1*V1
P1: 0.0065*5.2: 0.0338 W
P2: I2*V2
P2: 0.0065*19.5: 0.1267 W
PT: IT*VT
PT: 0.0065*25: 0.1625 W
Punto 2
RESISTEN VOLTAJE CORRIENTE POTENCIAR1= V1= I1= P1=R2= V2= I2= P2=R3= V3= I3= P3=R4 V4= I4= P4=RT= VT= IT= PT=
Punto 3
RESISTEN Ω
VOLTAJE V
CORRIENTE A
POTENCIA W
R1= 10 V1=20 I1=2 P1=40R2= 20 V2=20 I2=1 P2=20R3= 15 V3=20 I3=1.33 P3= 26.6RT= 4.76 VT= 20 IT=4.23 PT= 86.6
RT: 1/1/R1+1/R2+1/R3
RT: 1/1/10+1/20+1/15
RT: 1/0.1+0.05+0.06
RT: 1/0.21: 4.76
I1=V1/R1=20/10
I1=2
I2=V2/R2=20/20
I2=1
I3=20/15=1.33
IT= VT/RT = 20/4.76
IT= 4.23
P=I*V
P1= 40
P2= 20
P3= 26.6
PT= 86.6
Punto 4
RESISTEN VOLTAJE CORRIENTE POTENCIAR1= V1= I1= P1=R2= V2= I2= P2=R3= V3= I3= P3=R4 V4= I4= P4=RT= VT= IT= PT=
