angle of rotation ( rads )

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a tan r v r 2 2 f angle of rotation (rads angular velocity (rad/s angular acceleration (rad Recall that centripetal acceleration is expressed in terms of tangential velocity as: a r = v 2 /r. How is it expressed in terms of angular velocity ω? A) a r = ω 2 /r B) a r = rω C) a r = rω 2 D) a r = r 2 ω 2 a r = v 2 /r = (rω) 2 /r = rω 2 Clicker Question Room Frequency B

description

Clicker Question. Room Frequency BA. angle of rotation ( rads ). angular velocity ( rad/s ). angular acceleration (rad/s 2 ). Recall that centripetal acceleration is expressed in terms of tangential velocity as: a r = v 2 /r. How is it expressed in terms of angular velocity ω ? - PowerPoint PPT Presentation

Transcript of angle of rotation ( rads )

Page 1: angle of rotation ( rads )

atan

r

vr

2

2 f

angle of rotation (rads)

angular velocity (rad/s)

angular acceleration (rad/s2)

Recall that centripetal acceleration is expressed in terms of tangential velocity as: ar = v2/r. How is it expressed in terms of angular velocity ω?

A) ar = ω2/r B) ar = rω

C) ar = rω2 D) ar = r2ω2

ar = v2/r = (rω)2/r = rω2

Clicker Question Room Frequency BA

Page 2: angle of rotation ( rads )

Remember: This Week

• Read Ch. 8: And read Dr. Dubson’s excellent notes on Ch. 8.

• CAPA assignment #10 is due this Friday at 10 PM.

• Recitation: Review 1

• Lab Make-up (Labs 1-3): arrange with your TA.

Page 3: angle of rotation ( rads )

atan

r

vr

2

2 f

IC

angle of rotation (rads)

angular velocity (rad/s)

angular acceleration (rad/s2)

torque (N m)moment of inertia (kg m2)Newton’s 2nd Law

Today:

KE PE constant KEtrans KErot PE constant

(Conservation of Mechanical Energy)

Rotational Kinematics

Page 4: angle of rotation ( rads )

atan

r

vr

2

2 f

constant

angle of rotation (rads)

angular velocity (rad/s)

angular acceleration (rad/s2)

v v0 at

x x0 vot 12at 2

v2 v02 2ax

0 t

0 ot 12t 2

2 02 2

Constant acceleration a: Constant angular acceleration α:

Rotational Kinematics

Page 5: angle of rotation ( rads )

0 t

vr

2

2 f

0 ot 12t 2

2 02 2

A space ship is initially rotating on its axis with an angular velocity of ω0 = 0.5 rad/sec. The Captain creates a maneuver that produces a constant angular acceleration of α = 0.1 rad/sec2 for 10 sec.

1) What is its angular velocity at the end of this maneuver?

A) 1 rad/sec B) 1.5 rad/sec

C) 0.6 rad/sec D) 5 rad/sec

0 t 0.5 rad/sec (0.1 rad / sec2 )(10sec) 1.5 rad/sec

Clicker Question Room Frequency BA

Page 6: angle of rotation ( rads )

A space ship is initially rotating on its axis with an angular velocity of ω0 = 0.5 rad/sec. The Captain creates a maneuver that produces a constant angular acceleration of α = 0.1 rad/sec2 for 10 sec.

1) What is its angular velocity at the end of this maneuver? 1.5 rad/sec

f 2revols

sec

1.52revols

sec60secmin

45revolsmin

45rpm

Clicker Question Room Frequency BA

0 t

vr

2

2 f

0 ot 12t 2

2 02 2

2) At how many rpms is it rotating after the maneuver?

A) 10 rpm B) (30/π) rpm C) (45/π) rpmD) π rpm

Page 7: angle of rotation ( rads )

3) How far (in radians) did the space ship rotate while the Captain was applying the angular acceleration?

A) 1 rad B) 5 rad C) 10 rad D) 45 rad

1.5 rad/sec

f 45rpm

0 ot 12t 2 = (0.5 rad/sec)(10 sec) +

12

(0.1 rad/sec2 )(10 sec)2

= 5 rad +5 rad = 10 rad

Clicker Question Room Frequency BA

0 t

vr

2

2 f

0 ot 12t 2

2 02 2

A space ship is initially rotating on its axis with an angular velocity of ω0 = 0.5 rad/sec. The Captain creates a maneuver that produces a constant angular acceleration of α = 0.1 rad/sec2 for 10 sec.

1) What is its angular velocity at the end of this maneuver?

2) At how many rpms is it rotating after the maneuver?

Page 8: angle of rotation ( rads )

4) How many degrees is this?

A) 180° B) 1800°

C) (1800/π) degrees D) 360°

1.5 rad/secf

45rpm

= 10 rad

10rad180 deg rad

1800

deg

Clicker Question Room Frequency BA

0 t

vr

2

2 f

0 ot 12t 2

2 02 2

A space ship is initially rotating on its axis with an angular velocity of ω0 = 0.5 rad/sec. The Captain creates a maneuver that produces a constant angular acceleration of α = 0.1 rad/sec2 for 10 sec.

1) What is its angular velocity at the end of this maneuver?

2) At how many rpms is it rotating after the maneuver?

3) How far (in radians) did the space ship rotate while the Captain was applying the angular acceleration?

Page 9: angle of rotation ( rads )

atan

r

vr

2

2 f

IC

angle of rotation (rads)

angular velocity (rad/s)

angular acceleration (rad/s2)

torque (N m)moment of inertia (kg m2)Newton’s 2nd Law

Today:

KE PE constant KEtrans KErot PE constant

Rotational Dynamics

Page 10: angle of rotation ( rads )

r

s F

F

A

Consider the work done by a constant force in moving an object from point A to point B on a circle.

F

W

= Fs F(r) = (rF )

(Component of force along displacement) x displacement

rF Units: N mTorque

Torque Rotational Dynamics

Page 11: angle of rotation ( rads )

Torques are related to F

Torque:

rF

= (lever arm) x (Component of force perpendicular to lever arm)

The amount of work done by increases linearly with r and .F

F

Torque

Page 12: angle of rotation ( rads )

F

rF

Therefore, to easily rotate an object about an axis, you want a large lever arm r and a large perpendicular force :

Torque

Page 13: angle of rotation ( rads )

F

Therefore, to easily rotate an object about an axis, you want a large lever arm r and a large perpendicular force :

rFTorque

Page 14: angle of rotation ( rads )

What’s the torque you exerted on the door? (Note: sin 30° =1/2)

A) 8 Nm B) 10 Nm

C) 12 Nm D) 20 Nm

rF rF sin (1m)(20N )(1 / 2) 10Nm

rF

Clicker Question Room Frequency BA

Torque

You pull on a door handle a distance r = 1m from the hinge with a force of magnitude 20 N at an angle θ =30° from the plane of the door.

Page 15: angle of rotation ( rads )

Three forces labeled A, B, and C are applied to a rod which pivots on an axis through its center.

Which force causes the largest size torque?sin 45 cos 45 1 / 2 0.707

| A |LF sin 45 0.707LF

| B |L2F 0.5LF

| C |L4

2F 0.5LF

Clicker Question Room Frequency BA

Torque rF

Page 16: angle of rotation ( rads )

Three forces labeled A, B, and C are applied to a rod which pivots on an axis through its center.

What is the net torque on the rod?

A) 0.707 LF B) -0.707 LF C) 1.707 LF D) -1.707 LF

E) Zero

A LF sin 45 0.707LF

B L2F 0.5LF

C L4

2F 0.5LF

net (0.707 0.5 0.5)LF 1.707LF

Clicker Question Room Frequency BA

Torque rF

Page 17: angle of rotation ( rads )

Torque and Moment of Inertia

Rotational Analog to Newton’s Second Law (F = ma):

I

Torque = (moment of inertia) x (rotational acceleration)

Moment of inertia I depends on the distribution of mass and, therefore, on the shape of an object.

Units of τ: NmUnits of I: kg m2

Units of α: rad/s2

rF

Ipoint mr2Moment of inertia for a point mass is the mass times the square of the distance of the mass from the axis of rotation.

Page 18: angle of rotation ( rads )

Torque and Moment of Inertia

Consider a point mass m to which we apply a constant tangential force .m

r

r F

atan rF matan mr

rF mr2 I

I mr2

Thus, the moment of inertia for apoint mass is equal to mr2.

rF I

Page 19: angle of rotation ( rads )

A light rod of length 2L has two heavy masses (each with mass m) attached at the end and middle. The axis of rotation is at one end. What is the moment of inertia about the axis?

A) mL2 B) 2mL2 C) 4mL2 D) 5mL2 E) 9mL2

I miri2 = mL2 m(2L)2 5mL2

up

down

rF I

Ipoint mr2

Clicker Question Room Frequency BA

Page 20: angle of rotation ( rads )

Rotational Dynamics

atan

r

vr

2

2 f

IC

angle of rotation (rads)

angular velocity (rad/s)

angular acceleration (rad/s2)

torque (N m)

moment of inertia (kg m2)

Newton’s 2nd Law

Tod

KE PE constant KEtrans KErot PE constant(Conservation of Mechanical Energy)

ptot mii vi constant Ltot Ii

i i constant

Kinetic Energy (joules J)