Accelerated Motion Velocity, acceleration and gravity.

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Transcript of Accelerated Motion Velocity, acceleration and gravity.
Accelerated MotionAccelerated MotionVelocity, acceleration and gravityVelocity, acceleration and gravity
How fast do things fallHow fast do things fall
ReflexesReflexes
PositionTime GraphsPositionTime Graphs
11 22 33 44
Velocity v. TimeVelocity v. Time
DefinitionsDefinitions VelocityVelocity
Change in Change in position with position with respect to timerespect to time
v = v = ΔΔd/d/ΔΔt t Which can be written as:Which can be written as:
(d(dfinalfinalddinitialinitial)/(t)/(tfinalfinalttinitialinitial))
Common notation:Common notation:
(d(dff––ddii)/(t)/(tff–t–tii))
AccelerationAcceleration Change in Change in
velocity with velocity with respect to timerespect to time
a = a = ΔΔv/v/ΔΔt t Which can be written as:Which can be written as:
(v(vfinalfinalvvinitialinitial)/(t)/(tfinalfinalttinitialinitial))
Common notation :Common notation :
(v(vff–v–vii)/(t)/(tff–t–tii))
Velocity to AccelerationVelocity to Acceleration
v=v=ΔΔd/d/ΔΔt=(dt=(dfinalfinal–d–dinitialinitial)/(t)/(tfinalfinal–t–tinitialinitial))
a=a=ΔΔv/v/ΔΔt=(vt=(vfinalfinal–v–vinitialinitial)/(t)/(tfinalfinal–t–tinitialinitial))
Average AccelerationAverage Acceleration a =a =ΔΔv/v/ΔΔt=(vt=(vfinalfinal–v–vinitialinitial)/(t)/(tfinalfinal–t–tinitialinitial))
ff = final= final ii = initial = initial
If tIf tinitial initial = 0= 0 a = (va = (vfinalfinal – v – vinitialinitial)/t)/tfinalfinal
Or:Or: vvff = v = vii +at +atff
Positive and Negative Positive and Negative Acceleration Acceleration
Practice ProblemPractice Problem A soccer player is running at a A soccer player is running at a
constant velocity of 50.0km/h constant velocity of 50.0km/h (31mph). The player falls and (31mph). The player falls and skids to a halt in 4.0 seconds.skids to a halt in 4.0 seconds. What is the average acceleration of What is the average acceleration of
the player during the skid?the player during the skid? What is the plot of the velocity vs. What is the plot of the velocity vs.
time?time?
Practice ProblemPractice Problem
A water balloon in the sling of a A water balloon in the sling of a water balloon launcher undergoes water balloon launcher undergoes a constant acceleration 25m/s^2 a constant acceleration 25m/s^2 for 1.5s.for 1.5s. What is the velocity of the water What is the velocity of the water
balloon right after launch?balloon right after launch?
Practice ProblemPractice Problem
A car accelerates from rest at 5 m/s2 for A car accelerates from rest at 5 m/s2 for 5 seconds. It moves with a constant 5 seconds. It moves with a constant velocity for some time, and then velocity for some time, and then decelerates at 5 m/s2 to come to rest. decelerates at 5 m/s2 to come to rest. The entire journey takes 25 seconds. The entire journey takes 25 seconds. Plot the velocitytime graph of the Plot the velocitytime graph of the motion.motion.
Practice ProblemPractice Problem
Determine the Determine the accelerations for accelerations for aa11, a, a22, a, a33, and a, and a44 for each time for each time interval. interval.
aa11= 4/5= 4/5
aa22= (44)/(105)= (44)/(105)
aa33= (164)/(2010)= (164)/(2010)
aa44= (016)/(3020)= (016)/(3020)
Frictionless CarsFrictionless Cars
HypotenuseHypotenuseGravityGravity
Frictionless Car PlotsFrictionless Car Plots
Good Reading on PlotGood Reading on Plot
Velocity with Constant Velocity with Constant AccelerationAcceleration
Given:Given:
Solve Solve for tfor tff::
Substitute in: Substitute in:
Yeilds:Yeilds:
2½
½
2
Velocity with Constant Velocity with Constant AccelerationAcceleration
Solve for Solve for vfvf ½
2
½
2
1 12
2
21 12
2
2
22
2 2 22 2
222
GraphsGraphs Determine which equations provide the Determine which equations provide the
area under the graph. (let ti = 0)area under the graph. (let ti = 0)
½ ½ (v(vffvvii))
ttff½ ½ aa
(t(tffttii))
22
(v(vffvvii))(t(tffttii))
22
(t(tffttii))1122
Vel
ocity
(m
/s)
Vel
ocity
(m
/s)
Time (s)Time (s)
1)1)
2)2)
3)3)
Velocity with Constant Velocity with Constant AccelerationAcceleration
Equation to remember:Equation to remember: vvff^2 = v^2 = vii^2 +2a(d^2 +2a(dffddii))
Position with Average Position with Average AccelerationAcceleration
ΔΔd/d/ΔΔt = t = ΔΔv + ½ a v + ½ a ΔΔtt ΔΔd = d = ΔΔvvΔΔt + ½ a t + ½ a ΔΔt^2t^2
When tWhen tii = 0: = 0: ddff  d  dii = v = viittff + ½ at + ½ atff^2^2
Position with Average Position with Average AccelerationAcceleration
Equation to remember:Equation to remember: Final position = initial position + (change in velocity)*time + ½ Final position = initial position + (change in velocity)*time + ½
(acceleration)*(time squared)(acceleration)*(time squared)
ddff = d = dii + (v + (vffvvii)t + ½ at^2 )t + ½ at^2
Table 33 Page 68Table 33 Page 68 Equations of Motion for Uniform Equations of Motion for Uniform
AccelerationAcceleration
EquationEquation VariableVariabless
Initial Initial ConditiConditionsons
Average AccelerationAverage Acceleration ttff,v,vff,a,a vvii
Velocity with Constant Velocity with Constant AccelerationAcceleration
ttff,d,dff,a,a ddii,v,vii
Position with Average Position with Average AccelerationAcceleration
ddff,v,vff,a,a ddii,v,vii
Free Fall on the Moon Free Fall on the Moon
Free Fall on the Moon Free Fall on the Moon
Group Project pg 78Group Project pg 78 How fast is the How fast is the
Earth spinning?Earth spinning? 0.5 km/sec 0.5 km/sec
How fast is the How fast is the Earth revolving Earth revolving around the Sun?around the Sun? 30 km/sec 30 km/sec
How fast is the Solar How fast is the Solar System moving System moving around the Milky around the Milky Way Galaxy?Way Galaxy? 250 km/sec 250 km/sec
How fast is our Milky How fast is our Milky Way Galaxy moving Way Galaxy moving in the Local Group of in the Local Group of galaxies?galaxies? 370 km/sec370 km/sec
2
21
os
tt
vc
2
21
os
tt
vc
Free FallFree Fall
All Objects fall at All Objects fall at the same speed the same speed regardless of regardless of mass (if you can mass (if you can neglect wind neglect wind resistance).resistance).
Free FallFree Fall
A ball or a A ball or a bullet?bullet?
..
..
21
2f i id d v t at
21
2iy v t gt
Position with Average AccelerationPosition with Average Acceleration
Height with constant gravityHeight with constant gravity
FallingFalling21
2iy v t gt
Poor little guyPoor little guy21
2iy v t gt
GraphsGraphs
Cart MovementCart Movement
Practice ProblemsPractice Problems
If you throw a ball straight upward, it If you throw a ball straight upward, it will rise into the air and then fall will rise into the air and then fall back down toward the ground.back down toward the ground.
Imagine that you throw the ball with Imagine that you throw the ball with an initial velocity of 10.0 m/s.an initial velocity of 10.0 m/s. a. How long does it take the ball to reach a. How long does it take the ball to reach
the top of its motion?the top of its motion? b. How far will the ball rise before it b. How far will the ball rise before it
begins to fall?begins to fall? c. What is its average velocity during c. What is its average velocity during
this period?this period?
a. How long does it take the ball to reach the a. How long does it take the ball to reach the top of its motion?top of its motion?
2
0.00 10.0 /1.02
9.80 /
f i
f if
v v at
v v m st s
a m s
b. How far will the ball rise before it begins to b. How far will the ball rise before it begins to fall?fall?
1
21
(10.0 / 0.00 / )(1.02 )2
5.1
f id v v t
m s m s s
m
c. What is its average velocity during this c. What is its average velocity during this period?period?
5.1 0.0
1.025 /
f id dv
tm m
sm s
Practice ProblemPractice Problem
A sudden gust of wind increases A sudden gust of wind increases the velocity of a sailboat relative the velocity of a sailboat relative to the water surface from 3.0 to the water surface from 3.0 m/s to 5.5 m/s over a period of m/s to 5.5 m/s over a period of 60.0 s.60.0 s. a. What is the average a. What is the average
acceleration of the sailboat?acceleration of the sailboat? b. How far does the sailboat travel b. How far does the sailboat travel
during the period of acceleration?during the period of acceleration?
a. What is the average acceleration of the a. What is the average acceleration of the sailboat?sailboat?
2
5.5 / 3.0 /
60.0
0.042 /
f iv vva
t tm s m s
s
m s
b. How far does the sailboat travel during the b. How far does the sailboat travel during the period of acceleration?period of acceleration?
2
22
1
21
0.0 (3.0 / )(60.0 ) 0.042 / 60.02
0.0 180 75.6 255
f i id d v t at
m m s s m s s
m m m m
Practice ProblemPractice Problem
A car starts from rest with an acceleration A car starts from rest with an acceleration of 4.82 m/s^2 at the instant when a of 4.82 m/s^2 at the instant when a second car moving with a velocity of 44.7 second car moving with a velocity of 44.7 m/s (100mph by the way) passes it in a m/s (100mph by the way) passes it in a parallel line. How far does the first car parallel line. How far does the first car move before it overtakes the second car?move before it overtakes the second car? Setup an equation or graphSetup an equation or graph
Setup the equation Setup the equation
2 21 1 1 2 2 2
1 1
2 2car car car car car card v t a t d v t a t
00 00
21 2
1
2 car cara t v t
PositionPositiondd
VelocityVelocityv=v=ΔΔd/d/ΔΔtt
AccelerationAccelerationa=a=ΔΔv/v/ΔΔt t