6.1 & 6.4 an overview of the area problem area

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An Overview of the Area Problem

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Transcript of 6.1 & 6.4 an overview of the area problem area

Page 1: 6.1 & 6.4 an overview of the area problem area

An Overview of the Area Problem

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n = number of intervals arbitrary

Δx = size of intervals

i = which interval 1 to n

Finding the area could be broken down into the following parts:

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Here, x1 = 0, n = 4, and Δx = 0.5

Lower estimate → left endpoints approximation method - LAM

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Upper estimate → right endpoints approximation method - RAM

Here, x1 = 0, n = 4, and Δx = 0.5

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Average estimate → mid endpoints approximation method -

MAM

Here, x1 = 0, n = 4, and Δx = 0.5

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At some point we will use these formulas (pg.375 and pg. 376)

At some point you may want to use this formula:

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How would we find the actual area?

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Example Find the area of the region under the curve using: LAM

y = x2 [0, 2] n = 4

0 0.5 1 1.5 2

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Example Find the area of the region under the curve using: RAM

y = x2 [0, 2] n = 4

0 0.5 1 1.5 2

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Example Find the area of the region under the curve using: MAM

y = x2 [0, 2] n = 4

0.25 0.75 1.25 1.75

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The Antiderivative method for Finding Areas

a x

A (x)

A’ (x) = f(x)

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Let’s see how that worksExample: Find the area A(x) between the graph of f(x) = 2 and the interval [a, x] = [-1 ,x], and find the derivative A’(x) of this area function.

-1 x

y =2

2

x + 1

A = L* w

A = 2 * (x + 1)

A = 2 x + 2

A’ = 2 = f (x)

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More Examples !!!Example: Find the area A(x) between the graph of f(x) = x + 1 and the interval [a, x] = [-1 ,x], and find the derivative A’(x) of this area function.

A =1/2 * b* h

A =1/2 * (x + 1) * (x + 1)

A =1/ 2 (x2 + 2x+ 1)

A = x2/2 + x + 1/2

y = x + 1

x + 1

-1 x x + 1

A’ = x + 1 = f (x)

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One More Example !!!Example: Find the area A(x) between the graph of f(x) = 2x + 3 and the interval [a, x] = [-1 ,x], and find the derivative A’(x) of this area function.

A =1/2 *( b1 + b2) * h

A =1/2 *[ (2x + 3) + (2*(-1) + 3) ]* (x + 1)

A =1/2 * (2x + 4) * (x + 1)

A = 1/2 * (2x2 + 6x + 4)

A’ =2x + 3 = f (x)

y = 2x + 3

2x + 3

-1 x

x + 1

A = x2 + 3x + 2