6.002x CIRCUITS AND ELECTRONICS - edX · 2013. 2. 21. · In the last lecture… LC circuit . 5 In...

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1 6.002x CIRCUITS AND ELECTRONICS Damped Second-Order Systems

Transcript of 6.002x CIRCUITS AND ELECTRONICS - edX · 2013. 2. 21. · In the last lecture… LC circuit . 5 In...

  • 1  

    6.002x CIRCUITS AND ELECTRONICS

    Damped Second-Order

    Systems

  • Review

    C A B

    5V

    +!–!

    5V

    CGS large loop

    2KΩ 50Ω

    2KΩ S  

    LvA 5

    0

    vB

    0

    vC

    0

    50Ω

    t

    t

    t

    5

    5

  • 3  

    In the last lecture, we started by analyzing the simpler LC circuit to build intuition

  • 4  

    And for initial conditions

    We solved

    For input

    In the last lecture… LC circuit

  • 5  

    In the last lecture… LC circuit

    Total solution

    +!–! C L +!

    –!)(tv

    )(tvI

    )(ti

  • 6  See A&L Section 13.6

    Today, we will close the loop on our observations in the demo by analyzing the RLC circuit

    +!–! C

    L

    +!

    –!

    i(t)

    v(t) vI (t) LC

    I  v  

    v(t) 2VI

    t

    VI

    0

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    Recall element rules

    Let’s analyze the RLC network

    L:

    C:

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    Set up the differential equation vA

    +!–! C

    L +!

    –!

    R i(t)

    v(t) vI(t) Need to get rid of vA

    v

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    Set up the differential equation differently

    v +!–!

    C

    L +!

    –!

    R i

    vI

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    Solve IvLCvLCdtdv

    LR

    dtvd 112

    2

    =++

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    Let’s solve IvLC

    vLCdt

    dvLR

    dtvd 112

    2

    =++

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    1   Particular solution IvLC

    vLCdt

    dvLR

    dtvd 112

    2

    =++

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    1   Particular solution IvLC

    vLCdt

    dvLR

    dtvd 112

    2

    =++

    IPPP V

    LCv

    LCdtdv

    LR

    dtvd 112

    2

    =++

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    Homogeneous solution 2  IvLC

    vLCdt

    dvLR

    dtvd 112

    2

    =++

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    Homogeneous solution 2   0vLC1

    dtdv

    LR

    dtvd

    HHH =++2

    2

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    0vLC1

    dtdv

    LR

    dtvd

    HHH =++2

    2

    Solution to Homogeneous solution 2  

    Assume solution of the form 2A

    vH = AeST , A, S = ?

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    Homogeneous solution 2   0vLC1

    dtdv

    LR

    dtvd

    HHH =++2

    2

    Solution to

    02 =++LC1s

    LRs

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    Homogeneous solution 2   0vLC1

    dtdv

    LR

    dtvd

    HHH =++2

    2

    Solution to

    02 =++LC1s

    LRs

    Roots o1s22 ωαα −+−=

    os 222 ωαα −−−=

    characteristic equation

    LC1

    o =ω

    LR2

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    Total solution 3  

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    v(t) =VI + A1e−αte

    α2−ω2o( )t + A2e−αte− α2−ω2o( )t

    Let’s stare at this a while longer… 3 v(t) =VI + A1e−α+ α2−ω2o( )t + A2e

    −α− α2−ω2o( )t

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    v(t) =VI + A1e−αte

    α2−ω2o( )t + A2e−αte− α2−ω2o( )t3

    Overdamped o  

    ω  α   >  

    Underdamped o  ω  α   <  

    Critically damped o  

    ω  α   =  

    Overdamped o  ω  α   >  

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    Underdamped o  ω  α  <  3 v(t) =VI + A1e−αte

    α2−ω2o( )t + A2e−αte− α2−ω2o( )t

    Overdamped o  

    ω  α   >  

    Underdamped o  ω  α   <  

    Critically damped o  

    ω  α   =  

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    Underdamped contd… o  ω  α  <  3   teKteKVtv d

    td

    tI ωω

    αα sincos)( 21−− ++=

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    Underdamped contd… o  ω  α  <  

    Remember, scaled sum of sines (of the same frequency) are also sines! -- Appendix B.7

    v(t) =VI −VIe−αt cosωdt −VI

    αωd

    e−αt sinωdt3  

    ⎟⎟⎠

    ⎞⎜⎜⎝

    ⎛−+=+ −

    1

    2122

    2121 tancossincos A

    AAAAA θθθ

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    Critically damped o  ω  α   =  

    Section 13.2.3

    3  

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    Remember this? We have now closed the loop…

    vA 5

    0

    vB

    0

    vC

    0

    50Ω

    t

    t

    t

    5

    5

  • 27  See Sec. 12.7 of A&L textbook

    “ringing” v(t)

    VI 0

    t

    Easy way: Characteristic equation tells the whole story!

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    Intuitive Analysis +!–! C

    L +!

    –!)(tvIv

    )(ti

    R

    )0(i)0(v

    given -ve +ve

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    Next, introduce R: RLC Circuits

    More in the next sequence! If you are impatient, see A&L Section 13.2

    +!–! C

    L

    +!

    –!vI (t)

    i(t)

    v(t)

    v(t)

    t

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    What about other variables?

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    Parallel RLC – Characteristic equation says it all