Κ6-Ορισμός Παραγώγου (6)
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Transcript of Κ6-Ορισμός Παραγώγου (6)
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12 + 1 , 2 - .http://lisari.blogspot.gr/2011/01/1-2-3.html
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1. f 0, f 3(x)2x f 2(x)+ x 2 f (x) = x 2 2x , x ! .
) f (0) , f (0) .
) imx0
f (x)x +1x
.
) f ! , , (x 2) [f (x)+ f (x)] = x , , (0,2) .
2. , x,
f 2(x)+ g 2(x) = x 6 + 2x 3 +1 (1), f, g
x0 =1 , :
) f (1) = g(1) = 0 . ) [ f (1)]2 + [ g (1)]2 = 9 .
3. f :! ! 1, f
3(x)+ (x 1)2 f (x)2(x 1)3 = 0 , x ! . f (1) = 1 .
4. f :! ! 1, x 2 f 3(x)+ f (x)+1 = x 3 , x ! . f (1) = 3 .
5. f, g 1 f
2(x)+ g 2(x) = (x 21)2 , x ! , [ f (1)]2 + [ g (1)]2 = 4 .
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1. f 0, f 3(x)2x f 2(x)+ x 2 f (x) = x 2 2x , x ! .
) f (0) , f (0) .
) imx0
f (x)x +1x
.
) f ! , , (x 2) [f (x)+ f (x)] = x , , (0,2) .
) x ! , x = 0
f 3(0)2 0 f 2(0)+ 02 f (0) = 02 0 f 3(0) = 0 f (0) = 0 .
f (0) = im
x0
f (x) f (0)x 0
f (0) = imx0
f (x)x
(1)
x 0 , x 3 0 ,
f 3(x)x 3
2x f 2(x)
x 3+
x 2 f (x)x 3
=x 2 2x
x 3
f (x)x
3
2f (x)x
2
+f (x)x
=2x
x
imx0
f (x)x
3
2f (x)x
2
+f (x)x
= imx0
2xx
(2)
= im
x0
2xx
= imx0
2 2x2x
= 2 imx0
2x2x
, 2x = y .
x 0 , y 0 , = 2 im
y0
yy
= 2 1 = 2 (2),
(1), [ f (0)]3 2[ f (0)]2 + f (0) = 2 .
f (0) = ! 322 +2 = 0 (2)(2 +1) = 0 .
2 +1 > 0 , ! , 2 = 0 = 2f (0) = 2 .
. , , , , , , , .
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1. .
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)
1
= imx0
f (x)x +1x
= imx0
f (x)(x 1)xxx
= imx0
f (x)x
x 1x
xx
1=
201
1= 2 .
) (x 2) [f (x)+ f (x)]+ x = 0 . g(x) = (x 2) [f (x)+ f (x)]+ x , x [0,2] , - g(x) = 0 , , (0,2) .
. f ! , ! . f - ! , g ! , [0,2] , .
. g(0) = (02) [f (0)+ f (0)]+ 0 = 2(0 + 2) = 4 < 0 .
III. g(2) = (22) [f (2)+ f (2)]+ 2 = 2 > 0 .
Bolzano, g(x) = 0 , , (0,2) .
2. , x,
f 2(x)+ g 2(x) = x 6 + 2x 3 +1 (1), f, g
x0 =1 , :
) f (1) = g(1) = 0 . ) [ f (1)]2 + [ g (1)]2 = 9 .
) (1) x ! , x =1
f 2(1)+ g 2(1) = (1)2 + 2 (1)3 +1 f 2(1)+ g 2(1) = 0 f (1) = g(1) = 0 .
) f 1 ,
f (1) = imx1
f (x) f (1)x (1)
= imx1
f (x)x +1
(2)
g 1 ,
g (1) = imx1
g(x)g(1)x (1)
= imx1
g(x)x +1
(3)
x 1 , x +1 0 (1)
f 2(x)+ g 2(x)(x +1)2
=x 6 + 2x 3 +1
(x +1)2
f 2(x)(x +1)2
+g 2(x)
(x +1)2=
(x 3 +1)2
(x +1)2
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f (x)x +1
2
+g(x)x +1
2
=[(x +1)(x 2 x +1)]2
(x +1)2
f (x)x +1
2
+g(x)x +1
2
=(x +1)2(x 2 x +1)2
(x +1)2
f (x)x +1
2
+g(x)x +1
2
= (x 2 x +1)2 imx1
f (x)x +1
2
+g(x)x +1
2
= imx1
(x 2 x +1)2 (3)
(2)
[ f (1)]2 + [ g (1)]2 = [(1)2 (1)+1]2 [ f (1)]2 + [ g (1)]2 = 9 .
3. f :! ! 1, f
3(x)+ (x 1)2 f (x)2(x 1)3 = 0 , x ! . f (1) = 1 .
f (1) = im
x1
f (x) f (1)x 1
.
x ! , x = 1
f3(1)+ (11)2 f (1)2(11)3 = 0 f 3(1) = 0 f (1) = 0 .
f (1) = im
x1
f (x)x 1
(1)
x 1 , x 1 0 ,
f 3(x)(x 1)3
+(x 1)2 f (x)
(x 1)3
2(x 1)3
(x 1)3=
0(x 1)3
f (x)x 1
3
+f (x)x 1
2 = 0
imx1
f (x)x 1
3
+f (x)x 1
2
= imx1
0 (1)
[ f (1)]3 + f (1)2 = 0 .
f (1) = ! , 3 +2 = 0 (1)(2 ++ 2) = 0 1 = 0
= 1 f (1) = 1 , 2 ++ 2 12 4 1 2 = 7
( , ! ).
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4. f :! ! 1, x 2 f 3(x)+ f (x)+1 = x 3 , x ! . f (1) = 3 .
f (1) = im
x1
f (x) f (1)x 1
.
x ! , x = 1
12 f 3(1)+ f (1)+1 = 13 f 3(1)+ f (1) = 0 f (1) [f 2(1)+1] = 0 f (1) = 0 ,
f2(1)+1 > 0 , f(1).
f (1) = im
x1
f (x)x 1
(1)
x 1 , x 1 0 ,
x 2 f 3(x)+ f (x) = x 3 1
x 2 f 3(x)x 1
+f (x)x 1
=x 3 1x 1
x 2 f 2(x)
f (x)x 1
+f (x)x 1
=(x 1)(x 2 + x +1)
x 1
f (x)x 1
[x 2 f 2(x)+1] = x 2 + x +1
f (x)x 1
=x 2 + x +1
x 2 f 2(x)+1 (2) , x
2 f 2(x)+1 > 0 , f(x).
f 1, imx1
f (x) = f (1) = 0 , (2)
imx1
f (x)x 1
= imx1
x 2 + x +1x 2 f 2(x)+1
(1)
f (1) =12 +1+112 0 +1
f (1) = 3 .
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5. f, g 1 f
2(x)+ g 2(x) = (x 21)2 , x ! , [ f (1)]2 + [ g (1)]2 = 4 .
f 1, f (1) = im
x1
f (x) f (1)x 1
.
g 1, g (1) = im
x1
g(x)g(1)x 1
.
x ! , x = 1
f2(1)+ g 2(1) = (121)2 f 2(1)+ g 2(1) = 0 f (1) = g(1) = 0 .
f (1) = im
x1
f (x)x 1
, g (1) = imx1
g(x)x 1
.
x 1 , x 1 0 ,
f 2(x)(x 1)2
+g 2(x)
(x 1)2=
(x 2 1)2
(x 1)2
f (x)x 1
2
+g(x)x 1
2
=[(x 1)(x +1)]2
(x 1)2
f (x)x 1
2
+g(x)x 1
2
=(x 1)2(x +1)2
(x 1)2
f (x)x 1
2
+g(x)x 1
2
= (x +1)2
imx1
f (x)x 1
2
+g(x)x 1
2
= imx1
(x +1)2 [ f (1)]2 + [ g (1)]2 = (1+1)2 [ f (1)]2 + [ g (1)]2 = 4 .
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