5 5.1 © 2012 Pearson Education, Inc. Eigenvalues and Eigenvectors EIGENVECTORS AND EIGENVALUES.

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Transcript of 5 5.1 © 2012 Pearson Education, Inc. Eigenvalues and Eigenvectors EIGENVECTORS AND EIGENVALUES.

  • Slide 1
  • 5 5.1 2012 Pearson Education, Inc. Eigenvalues and Eigenvectors EIGENVECTORS AND EIGENVALUES
  • Slide 2
  • Slide 5.1- 2 2012 Pearson Education, Inc. EIGENVECTORS AND EIGENVALUES Definition: An eigenvector of an matrix A is a nonzero vector x such that for some scalar . A scalar is called an eigenvalue of A if there is a nontrivial solution x of ; such an x is called an eigenvector corresponding to .
  • Slide 3
  • EIGENVECTORS AND EIGENVALUES Slide 5.1- 3 2012 Pearson Education, Inc. is an eigenvalue of an matrix A if and only if the equation ----(1) has a nontrivial solution. The set of all solutions of (1) is just the null space of the matrix.
  • Slide 4
  • Slide 5.1- 4 2012 Pearson Education, Inc. EIGENVECTORS AND EIGENVALUES So this set is a subspace of and is called the eigenspace of A corresponding to . The eigenspace consists of the zero vector and all the eigenvectors corresponding to . Example 1: Show that 7 is an eigenvalue of matrix and find the corresponding eigenvectors.
  • Slide 5
  • Slide 5.1- 5 2012 Pearson Education, Inc. EIGENVECTORS AND EIGENVALUES Solution: The scalar 7 is an eigenvalue of A if and only if the equation ----(2) has a nontrivial solution. But (2) is equivalent to, or ----(3) To solve this homogeneous equation, form the matrix
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  • Slide 5.1- 6 2012 Pearson Education, Inc. EIGENVECTORS AND EIGENVALUES The columns of are obviously linearly dependent, so (3) has nontrivial solutions. To find the corresponding eigenvectors, use row operations: The general solution has the form. Each vector of this form with is an eigenvector corresponding to.
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  • Slide 5.1- 7 2012 Pearson Education, Inc. EIGENVECTORS AND EIGENVALUES Example 2: Let. An eigenvalue of A is 2. Find a basis for the corresponding eigenspace. Solution: Form and row reduce the augmented matrix for.
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  • Slide 5.1- 8 2012 Pearson Education, Inc. EIGENVECTORS AND EIGENVALUES At this point, it is clear that 2 is indeed an eigenvalue of A because the equation has free variables. The general solution is, x 2 and x 3 free.
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  • Slide 5.1- 9 2012 Pearson Education, Inc. EIGENVECTORS AND EIGENVALUES The eigenspace, shown in the following figure, is a two-dimensional subspace of. A basis is
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  • Slide 5.1- 10 2012 Pearson Education, Inc. EIGENVECTORS AND EIGENVALUES Theorem 1: The eigenvalues of a triangular matrix are the entries on its main diagonal. Proof: For simplicity, consider the case.
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  • Slide 5.1- 11 2012 Pearson Education, Inc. EIGENVECTORS AND EIGENVALUES Theorem 2: If v 1, , v r are eigenvectors that correspond to distinct eigenvalues 1, , r of an matrix A, then the set {v 1, , v r } is linearly independent.
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  • Slide 5.1- 12 2012 Pearson Education, Inc. EIGENVECTORS AND DIFFERENCE EQUATIONS If A is an matrix, then ----(7) is a recursive description of a sequence {x k } in. A solution of (7) is an explicit description of {x k } whose formula for each x k does not depend directly on A or on the preceding terms in the sequence other than the initial term x 0.
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  • Slide 5.1- 13 2012 Pearson Education, Inc. EIGENVECTORS AND DIFFERENCE EQUATIONS The simplest way to build a solution of (7) is to take an eigenvector x 0 and its corresponding eigenvalue and let ----(8) This sequence is a solution because