3(ln40 2 .563)novakmath.com/precalchonorsfinalexamreviewanswers.pdfPrecalculus Honors Final Exam...

3
Precalculus Honors Final Exam Review Answers Page Problem # Answer 1 274 146 98.6% 2 273 126 4 5 272.991 e 3 273 108 ( ) 1 ln 40 2 .563 3 4 272 93 ( ) 2 2 1 ln 1 x x + 5 265 27 2.26 g 6 365 11 8.378 7 366 74 3 π θ = 8 365 6 b) I c) , 17 3 3 π π 9 365 39 3.2361 10 367 111 .41 11 365 29 7 1 7 2 6 2 6 7 3 7 2 3 6 2 6 3 7 3 7 3 6 3 6 sin csc cos sec tan cot π π π π π π =− =− =− =− = = 12 367 109 6 π 13 366 79 2 2 sin 495 cos 495 tan 495 1 2 2 = =− =− 14 420 36 5 or 3 3 x π π = 15 365 20 11 meters 11.52 m 3 π 16 367 130 5 12

Transcript of 3(ln40 2 .563)novakmath.com/precalchonorsfinalexamreviewanswers.pdfPrecalculus Honors Final Exam...

Page 1: 3(ln40 2 .563)novakmath.com/precalchonorsfinalexamreviewanswers.pdfPrecalculus Honors Final Exam Review Answers Page Problem # Answer 1 274 146 98.6% 2 273 126 5 272.991e4 ≈ 3 273

Precalculus Honors Final Exam Review Answers

Page Problem # Answer 1 274 146 98.6% 2 273 126 45 272.991e ≈ 3 273 108 ( )1 ln40 2 .5633 − ≈

4 272 93

( )22 1ln

1x

x−

+

5 265 27 2.26g

6 365 11 8.378

7 366 74

3πθ =′

8 365 6

b) I c) , 173 3π π

9 365 39 3.2361 10 367 111 .41 11 365 29 7 1 7 2

6 2 67 3 7 2 3 6 2 6 3

7 3 7 3 6 3 6

sin csc

cos sec

tan cot

π π

π π

π π

= − = −

= − = −

= =

12 367 109 6π−

13 366 79

2 2sin 495 cos495 tan 495 12 2

= =− =−

14 420 36 5 or 3 3

x π π=

15 365 20 11 meters 11.52 m3π ≈

16 367 130 512−

Page 2: 3(ln40 2 .563)novakmath.com/precalchonorsfinalexamreviewanswers.pdfPrecalculus Honors Final Exam Review Answers Page Problem # Answer 1 274 146 98.6% 2 273 126 5 272.991e4 ≈ 3 273

17 366 58 4 5 5 4

3 5 5 3

4 3 3 4

sin csc

cos sec

tan cot

θ θ

θ θ

θ θ

= − = −

= =

= − = −

18 365 10

b) IV c) 315 , 45−

19 423 3 1 20 420 37 , , 2 4 5 ,

3 3 3 3x π π π π=

21 420 40 , , 5 6 2 6

x π π π=

22 366 96

23 367 106

24 369 12

25 421 61 5 7 36 5 9 or 752 52 13

+ +

26 421 76 4 3 4sin2 cos2 tan25 5 3u u u=− = =−

27 423 18 , , 5 3 ,6 2 6 2π π π πα =

28 420 20 22tan 2sec tan 1x x x− + 29 421 77

( )( )( )( )

2

2

3

sin 2(2 )2sin 2 cos22 2sin cos 2cos 1

4sin cos 2cos 1

8sin cos 4sin cos

xx xx x x

x x x

x x x x

30 482 3 26 a=24.89, c=56.23, A∠ =

31 482 23 29.92 86.18 , 63.90, A B C∠ = ∠ = ∠ =

jnovak
Typewritten Text
8
jnovak
Typewritten Text
jnovak
Typewritten Text
Page 3: 3(ln40 2 .563)novakmath.com/precalchonorsfinalexamreviewanswers.pdfPrecalculus Honors Final Exam Review Answers Page Problem # Answer 1 274 146 98.6% 2 273 126 5 272.991e4 ≈ 3 273

32 482 12 40.92 114.08 , c=8.64

139.08 15.92 , c=2.6

,

,

A C

A Cor∠ = ∠ =

∠ = ∠ =

33 483 32 1135.5 miles

34 715 45 25, 250 35 715 42 52 36 716 86 ( ) ( )

11 14412 112 1 121 131 12

nn

− −= − −

+

37 716 72 3/2 38 716 92 -3, -7, -13, -21, -31 39

40