| No. 1 APP for Banking & SSC Preparation Website: Email · Literate man =150000×90 100 = 135000...

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Transcript of | No. 1 APP for Banking & SSC Preparation Website: Email · Literate man =150000×90 100 = 135000...

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S1. Ans.(c)

Sol.

(2467)153 × (341)72

(2467)153 = (7)153

= 7152 × 21

= (74)38 × 71

= (1)38 × 7 [74 = 1]

= 7

(341)72 = 1

(2467)153 × (341)72 = 7 × 1

= 7 (unit digit)

S2. Ans.(b)

Sol.

x +1

x= 1

x² +1 = x

x² - x + 1= 0

x² - x + 1 + 1 = 1

x² - x + 2 = 1 2

x2 − x + 2=

2

1= 2

S3. Ans.(a)

Sol.

x =1

2 + √3=

1

2 + √3×

2 − √3

2 − √3

= 2 − √3

y =1

2 − √3=

1

2 − √3×

2 + √3

2 + √3

= 2 + √3

8xy(x² + y²) = 8(2 – √3)(2 + √3) [4 + 3 − 4√3 + 4 + 3 + 4√3]

= 8 (4 – 3) (14)

= 112

S4. Ans.(c)

Sol.

Let H.C.F = x

Let two numbers be xa & xb (xa > xb)

LCM = xab

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LCM =2xa

xab = 2 × xa

b = 2

Smallest number – HCF = 4

xb – x = 4

2x – x = 4

X = 4

Smaller number = 4 × 2 = 8

S5. Ans.(b)

Sol.

Strength of women = 311250 ×43

83

= 161250

Literate women = 161250 ×24

100

= 38700

Strength of men = 311250 ×40

83

= 150000

Literate man = 150000 ×90

100

= 135000

Total literate = 135000 + 38700

= 173700 Rs

S6. Ans.(b)

Sol.

CP SP

Case I 100 90

Case II 100 110

(110 – 90)r → 108

20r → 108

r = 5.4

CP = 5.4 × 100 = Rs 540

S7. Ans.(a)

Sol.

Let Rs 100 be MP

Arvind bought watch at = 100 ×70

100

= Rs 70

SP of watch = 70 ×140

100

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= Rs 98

Loss on labelled price =100−98

100× 100

= 2%

S8. Ans.(c)

Sol.

In ∆ABD,

tan60° =AB

BD

√3 =AB

50

AB = 50√3 m

In ∆ABC

tan30° =AB

BC

1

√3=

50√3

BC

BC = 150 m

DC = 150 – 50 = 100m

Speed of boat =100m

8sec

=100

18

8 km/hr

= 45 km/hr

S9. Ans.(a)

Sol. n1

n2=

5

6

(n1−2)×180

n1

(n2−2)×180

n2

=24

25

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(n1 − 2)

(n2 − 2)×

n2

n1=

24

25

(n1 − 2)

(n2 − 2)×

6

5=

24

25

(n1 − 2)

(n2 − 2=

4

5

5n1 – 10 = 4n2 – 8

5n1 – 4n2 = 2 25n2

6− 4n2 = 2

n2 = 12

n1 = 10

S10. Ans.(b)

Sol.

∠BAC = 180° - (65 + 55°)

= 180° - 120

= 60°

∠BIC = 90 +∠A

2

= 90 + 30 = 120°

S11. Ans.(a)

Sol.

EO = x, OF = 17 – x

AB = 10 CD = 24

AE = 5cm CF = 12

In ∆AOE

AO² = 25 + x²

In ∆COF

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CO² = 144 + (17 – x)²

AO = CO =r

25 + x² = 144 + 289 + x² - 34x

34x = 144 + 289 – 25

x = 12

AO² = 25 + 144

AO² = 169

AO = 13 cm

Radius = 13 cm

S12. Ans.(b)

Sol. Run10

10= 60

Run10 = 600 Run11

11= 62

Run11 = 682

Run10 + 11th Inning = 682

Run required in 1th inning = 682 – 600

= 82

S13. Ans.(a)

Sol.

Ratio by which total wage of worker be decreased

= 330 : 275

= 6 : 5

S14. Ans.(b)

Sol.

Interest on ¼ capital =1

3

100

=3

400

Interest on 2

3 capital =

2

5

100=

1

30

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Interest on 1

12 capital =

1

12×

11

100=

11

1200

Total interest =3

400+

1

30+

11

1200

=9 + 40 + 11

1200

=60

1200=

1

20

% he receives on the whole

=120

1

× 100

= 5%

S15. Ans.(c)

Sol.

n1

1

t1 = n2

1

t2

21

4 = 41

t2

21

4 = 22

t2 1

4=

2

t2

t2 = 8 years

S16. Ans.(c)

Sol.

x →1

4thwork → 6days

Whole work → 24 days

y →3th

4 work → 12 days whole work ⇒ 16 days

x & y will complete the whole work is

⇒1

24+

1

16

⇒24 + 16

24 × 16

⇒40

24 × 16

⇒5

48

Days required =48

5

= 93

5 days

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S17. Ans.(c)

Sol.

(2M + 3B) × 10 = (3M + 2B) × 8

20M + 30B = 24M + 16B

4M = 14B

M =7

2 B

2M + 3B ⇒ 2 ×7

2B + 3B ⇒ 10B

2M + 1B ⇒ 2 × 7

2 B + 1B ⇒ 8B

10B × 10 = 8B × Days

Days =100

8

=25

2

= 121

2 days

S18. Ans.(c)

Sol.

Work done by A in 1 hour = 3

Remaining work = 6 – 3 = 3

Efficiency of A & B = 3 + 1 = 4

Time required by A & B to till the tank

=3

4 hours

=3

4× 60 min

= 45 min

The tank will be full at 11 : 45 am

S19. Ans.(c)

Sol.

Distance travelled = 8 × 2πr

16πr = Speed × Time

16πr = Speed × 40

60

Increased Radius = 10r

Distance to be travelled = 2π × 10r

L.C.MEfficiency

(Total Work)

A 2 3

6

B 6 1

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= 20πr

20πr = Speed × Time

20πr =16πr × 60

40× Time

Time =800

16 × 16 hours

=50

60 hours = 50 minutes

S20. Ans.(c)

Sol.

Area × cost = 7700 22

7× r2 ×

1

2= 7700

r² = 7 × 7 × 10 × 10

r = 70 m

Perimeter = 2πr

= 2 ×22

7× 70

= 440 m

Cost = 440 × 1.20

= 528 Rs

S21. Ans.(b)

Sol.

They will meet after =27

6=

9

2 hours

QR =9

2× 18

= 81 km

S22. Ans.(a)

Sol.

33% → 165 crores

Income From others = 67%

1% ⇒ 5 crore

67% ⇒ 335 crore

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S23. Ans.(c)

Sol.

100% → 733 crore

Income tax + Excise duty

= 10% + 35% = 45%

1 → 7.33 crore

45% = 45 × 733 crore

= 329.85 crore

S24. Ans.(c)

Sol.

Number → 3x, 4x

LCM ⇒ 12x = 240

x = 20

Smaller number = 60

S25.Ans(d)

Sol. 𝑥

12+

𝑥

9= 2

20

60

3𝑥 + 4𝑥

36=

7

3

7𝑥

36=

7

3

x = 12 km

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