| No. 1 APP for Banking & SSC Preparation Website: Email · Literate man =150000×90 100 = 135000...
Transcript of | No. 1 APP for Banking & SSC Preparation Website: Email · Literate man =150000×90 100 = 135000...
1 Adda247 | No. 1 APP for Banking & SSC Preparation Website:store.adda247.com | Email:[email protected]
2 Adda247 | No. 1 APP for Banking & SSC Preparation Website:store.adda247.com | Email:[email protected]
S1. Ans.(c)
Sol.
(2467)153 × (341)72
(2467)153 = (7)153
= 7152 × 21
= (74)38 × 71
= (1)38 × 7 [74 = 1]
= 7
(341)72 = 1
(2467)153 × (341)72 = 7 × 1
= 7 (unit digit)
S2. Ans.(b)
Sol.
x +1
x= 1
x² +1 = x
x² - x + 1= 0
x² - x + 1 + 1 = 1
x² - x + 2 = 1 2
x2 − x + 2=
2
1= 2
S3. Ans.(a)
Sol.
x =1
2 + √3=
1
2 + √3×
2 − √3
2 − √3
= 2 − √3
y =1
2 − √3=
1
2 − √3×
2 + √3
2 + √3
= 2 + √3
8xy(x² + y²) = 8(2 – √3)(2 + √3) [4 + 3 − 4√3 + 4 + 3 + 4√3]
= 8 (4 – 3) (14)
= 112
S4. Ans.(c)
Sol.
Let H.C.F = x
Let two numbers be xa & xb (xa > xb)
LCM = xab
3 Adda247 | No. 1 APP for Banking & SSC Preparation Website:store.adda247.com | Email:[email protected]
LCM =2xa
xab = 2 × xa
b = 2
Smallest number – HCF = 4
xb – x = 4
2x – x = 4
X = 4
Smaller number = 4 × 2 = 8
S5. Ans.(b)
Sol.
Strength of women = 311250 ×43
83
= 161250
Literate women = 161250 ×24
100
= 38700
Strength of men = 311250 ×40
83
= 150000
Literate man = 150000 ×90
100
= 135000
Total literate = 135000 + 38700
= 173700 Rs
S6. Ans.(b)
Sol.
CP SP
Case I 100 90
Case II 100 110
(110 – 90)r → 108
20r → 108
r = 5.4
CP = 5.4 × 100 = Rs 540
S7. Ans.(a)
Sol.
Let Rs 100 be MP
Arvind bought watch at = 100 ×70
100
= Rs 70
SP of watch = 70 ×140
100
4 Adda247 | No. 1 APP for Banking & SSC Preparation Website:store.adda247.com | Email:[email protected]
= Rs 98
Loss on labelled price =100−98
100× 100
= 2%
S8. Ans.(c)
Sol.
In ∆ABD,
tan60° =AB
BD
√3 =AB
50
AB = 50√3 m
In ∆ABC
tan30° =AB
BC
1
√3=
50√3
BC
BC = 150 m
DC = 150 – 50 = 100m
Speed of boat =100m
8sec
=100
8×
18
8 km/hr
= 45 km/hr
S9. Ans.(a)
Sol. n1
n2=
5
6
(n1−2)×180
n1
(n2−2)×180
n2
=24
25
5 Adda247 | No. 1 APP for Banking & SSC Preparation Website:store.adda247.com | Email:[email protected]
(n1 − 2)
(n2 − 2)×
n2
n1=
24
25
(n1 − 2)
(n2 − 2)×
6
5=
24
25
(n1 − 2)
(n2 − 2=
4
5
5n1 – 10 = 4n2 – 8
5n1 – 4n2 = 2 25n2
6− 4n2 = 2
n2 = 12
n1 = 10
S10. Ans.(b)
Sol.
∠BAC = 180° - (65 + 55°)
= 180° - 120
= 60°
∠BIC = 90 +∠A
2
= 90 + 30 = 120°
S11. Ans.(a)
Sol.
EO = x, OF = 17 – x
AB = 10 CD = 24
AE = 5cm CF = 12
In ∆AOE
AO² = 25 + x²
In ∆COF
6 Adda247 | No. 1 APP for Banking & SSC Preparation Website:store.adda247.com | Email:[email protected]
CO² = 144 + (17 – x)²
AO = CO =r
25 + x² = 144 + 289 + x² - 34x
34x = 144 + 289 – 25
x = 12
AO² = 25 + 144
AO² = 169
AO = 13 cm
Radius = 13 cm
S12. Ans.(b)
Sol. Run10
10= 60
Run10 = 600 Run11
11= 62
Run11 = 682
Run10 + 11th Inning = 682
Run required in 1th inning = 682 – 600
= 82
S13. Ans.(a)
Sol.
Ratio by which total wage of worker be decreased
= 330 : 275
= 6 : 5
S14. Ans.(b)
Sol.
Interest on ¼ capital =1
4×
3
100
=3
400
Interest on 2
3 capital =
2
3×
5
100=
1
30
7 Adda247 | No. 1 APP for Banking & SSC Preparation Website:store.adda247.com | Email:[email protected]
Interest on 1
12 capital =
1
12×
11
100=
11
1200
Total interest =3
400+
1
30+
11
1200
=9 + 40 + 11
1200
=60
1200=
1
20
% he receives on the whole
=120
1
× 100
= 5%
S15. Ans.(c)
Sol.
n1
1
t1 = n2
1
t2
21
4 = 41
t2
21
4 = 22
t2 1
4=
2
t2
t2 = 8 years
S16. Ans.(c)
Sol.
x →1
4thwork → 6days
Whole work → 24 days
y →3th
4 work → 12 days whole work ⇒ 16 days
x & y will complete the whole work is
⇒1
24+
1
16
⇒24 + 16
24 × 16
⇒40
24 × 16
⇒5
48
Days required =48
5
= 93
5 days
8 Adda247 | No. 1 APP for Banking & SSC Preparation Website:store.adda247.com | Email:[email protected]
S17. Ans.(c)
Sol.
(2M + 3B) × 10 = (3M + 2B) × 8
20M + 30B = 24M + 16B
4M = 14B
M =7
2 B
2M + 3B ⇒ 2 ×7
2B + 3B ⇒ 10B
2M + 1B ⇒ 2 × 7
2 B + 1B ⇒ 8B
10B × 10 = 8B × Days
Days =100
8
=25
2
= 121
2 days
S18. Ans.(c)
Sol.
Work done by A in 1 hour = 3
Remaining work = 6 – 3 = 3
Efficiency of A & B = 3 + 1 = 4
Time required by A & B to till the tank
=3
4 hours
=3
4× 60 min
= 45 min
The tank will be full at 11 : 45 am
S19. Ans.(c)
Sol.
Distance travelled = 8 × 2πr
16πr = Speed × Time
16πr = Speed × 40
60
Increased Radius = 10r
Distance to be travelled = 2π × 10r
L.C.MEfficiency
(Total Work)
A 2 3
6
B 6 1
9 Adda247 | No. 1 APP for Banking & SSC Preparation Website:store.adda247.com | Email:[email protected]
= 20πr
20πr = Speed × Time
20πr =16πr × 60
40× Time
Time =800
16 × 16 hours
=50
60 hours = 50 minutes
S20. Ans.(c)
Sol.
Area × cost = 7700 22
7× r2 ×
1
2= 7700
r² = 7 × 7 × 10 × 10
r = 70 m
Perimeter = 2πr
= 2 ×22
7× 70
= 440 m
Cost = 440 × 1.20
= 528 Rs
S21. Ans.(b)
Sol.
They will meet after =27
6=
9
2 hours
QR =9
2× 18
= 81 km
S22. Ans.(a)
Sol.
33% → 165 crores
Income From others = 67%
1% ⇒ 5 crore
67% ⇒ 335 crore
10 Adda247 | No. 1 APP for Banking & SSC Preparation Website:store.adda247.com | Email:[email protected]
S23. Ans.(c)
Sol.
100% → 733 crore
Income tax + Excise duty
= 10% + 35% = 45%
1 → 7.33 crore
45% = 45 × 733 crore
= 329.85 crore
S24. Ans.(c)
Sol.
Number → 3x, 4x
LCM ⇒ 12x = 240
x = 20
Smaller number = 60
S25.Ans(d)
Sol. 𝑥
12+
𝑥
9= 2
20
60
3𝑥 + 4𝑥
36=
7
3
7𝑥
36=
7
3
x = 12 km
11 Adda247 | No. 1 APP for Banking & SSC Preparation Website:store.adda247.com | Email:[email protected]