Μαθηματικά Ε΄ 6.37. ΄΄ Κριτήρια διαιρετότητας του 2, του 5...

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Transcript of Μαθηματικά Ε΄ 6.37. ΄΄ Κριτήρια διαιρετότητας του 2, του 5...

  • :

    - 6 - 37

    2, 5 10

    http://e-taksh.blogspot.gr

    : http://e-taksh.blogspot.gr .1

  • : http://e-taksh.blogspot.gr .2

    Xristos

  • : http://e-taksh.blogspot.gr .3

    Xristos

  • Nansy Tzg

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    : http://e-taksh.blogspot.gr .4

  • Nansy Tzg

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    275, 9.580, 72.148, 451.672, 1.024.536

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    : http://e-taksh.blogspot.gr .5

  • Nansy Tzg

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    : http://e-taksh.blogspot.gr .6

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    : http://e-taksh.blogspot.gr .7

  • eva-edu

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    : http://e-taksh.blogspot.gr .8

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    : http://e-taksh.blogspot.gr .9

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    : http://e-taksh.blogspot.gr .10

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    : http://e-taksh.blogspot.gr .11

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    : http://e-taksh.blogspot.gr .12

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    : http://e-taksh.blogspot.gr .13

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    : http://e-taksh.blogspot.gr .14

  • 2, 5 10 , . 2, 0 2 4 6 8( )

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    : http://e-taksh.blogspot.gr .15

    http://egpaid.blogspot.com/

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    : http://e-taksh.blogspot.gr .16

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    : http://e-taksh.blogspot.gr .17

  • : http://e-taksh.blogspot.gr .18

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    : http://e-taksh.blogspot.gr .19

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    : http://e-taksh.blogspot.gr .20

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    : http://e-taksh.blogspot.gr .21

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    : http://e-taksh.blogspot.gr .23

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    4 + 5 = 9 3 9

    3 + 4 + 5 + 8 + 4 = 24 3 24

    2 + 3 + 1 + 2 = 8 3 8

    : http://e-taksh.blogspot.gr .24

  • 9; 9

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    : http://e-taksh.blogspot.gr .25

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    : http://e-taksh.blogspot.gr .26

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    : http://e-taksh.blogspot.gr .27

  • 11; 11

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    41 + 47 = 88

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    : http://e-taksh.blogspot.gr .28

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    : http://e-taksh.blogspot.gr .29

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    : http://e-taksh.blogspot.gr .30

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    www.schoolarxeio.weebly.com : http://e-taksh.blogspot.gr .31

  • 2 ( 2;)

    1 2 = 2

    2 2 = 4

    2 3 = 6

    2 4 = 8

    2 5 = 10

    2 6 = 12

    2 7 = 14

    2 8 = 16

    2 9 = 18

    2 10 = 20

    2 (2,4,6,8,20) 2 2;

    2 :

    , 2, 4, 6, 8

    : http://e-taksh.blogspot.gr .32

  • ( 2;) 2

    ( 2)

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    : http://e-taksh.blogspot.gr .33

  • 3 1 = 3

    3 2 = 6

    3 3 = 9

    3 4 = 12 1 + 2 = 3

    3 5 = 15 1 + 5 = 6

    3 6 = 18 1 + 8 = 9

    3 7 = 21 2 + 1 = 3

    3 8 = 24 2 + 4 = 6

    3 9 = 27 2 + 7 = 9

    3 10 = 30 3 + 0 = 3

    3 ( 3;)

    3 (3, 6, 930) 3 3;

    3

    3, 6, 9

    : http://e-taksh.blogspot.gr .34

  • 3 ( 3;)

    ( 3)

    3,

    3 6 9

    : http://e-taksh.blogspot.gr .35

  • 5 ( 5;)

    5 1 = 5

    5 2 = 10

    5 3 = 15

    5 4 = 20

    5 5 = 25

    5 6 = 30

    5 7 = 35

    5 8 = 40

    5 9 = 45

    5 10 = 50

    5 (2,4,6,8,20) 5 5;

    5 :

    5, 0

    : http://e-taksh.blogspot.gr .36

  • 5 ( 5;)

    ( 5)