ΑΝΑΛΥΣΗ ΕΝΟΣ ΑΠΟΣΠΑΣΜΑΤΟΣ ΑΠΟ ΤΟ «DEMONSTRATION OF THE BEING AND...

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    XIII

    DEMONSTRATION OF THE BEING

    AND ATTRIBUTES OF GOD, DR. SAMUEL CLARKE

    ETHICA ORDINE GEOMETRICO

    DEMONSTRATA SPINOZA.

    1. , , , .

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    3. Demonstration of the Being and Attributes of God, ,

    , , , ,

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    , a

    priori. , , ,

    , .

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    , ,

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    4. Ethics Benedict Spinoza , , ,

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    . Dr. Samuel Clarke ,

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    CLARKE.

    I.

    5. . :-

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    . ,

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    Dr. Clarke

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    .

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    :-

    1

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    2

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    .

    3

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    .

    4 , .

    5

    , ,

    , .

    .

    x = .

    y = .

    z = .

    p = .

    q = .

    , , x = " ,

    x (XI.

    7), x = 1, x = 0, .

    :-

    1

    x = 1

    2 x = v[y(1x) + z(1y)]

    3

    x = v[p(1q) + q(1p)]

    4

    p = vy

    5

    q = v(1z)

    v,

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    1x = 0 (1)

    x = [yz + (1y) (1z)] = 0 (2)

    x = [pq + (1p) (1q)] = 0 (3)

    p(qy) = 0 (4)

    qz = 0 (5)

    6. , ,

    y, z, p, q, , ,

    ,

    ,

    .

    y,

    z, .

    .

    x (1), (2), (3),

    (2) (3) x (1). ,

    yz +(1y)(1z)=0 (6)

    pq +(1p)(1q)=0 (7)

    p (4) (7), ,

    p(1y) + pq + (1p)(1q) = 0 (8)

    ,

    (1y)(1q)=0. (9)

    q (5) (9),

    qz + (1y)(1q) = 0

    x(1y) = 0. (10)

    (6) (10), , , ,

    yz + 1y = 0.

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    z,

    1y = 0, , y = 1. (11)

    y,

    z = 0. (12)

    (11)

    .

    (12)

    .

    (6), (7), (4), (5),

    p q . y (4)

    (6),

    p(1y) + yz +(1y)(1z) = (0)

    (p + 1z)z = 0, or, pz = 0. (13)

    z (5) (13),

    qz + pz = 0

    ,

    0 = 0.

    (7), q, 0 = 0

    , p.

    , ,

    . , p,

    0 = 0, q, ,

    , , .

    ,

    (7) p q,

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    .

    (7),

    p(1q) + q(1p) = 1, ,

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    .

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    ,

    .

    .

    Dr. Clarke,

    .

    II.

    7. . :

    1

    .

    2

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    .

    3

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    , .

    4

    (, ,

    ).

    5 ( ,

    , ).

    , ,

    ,

    :

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    x = .y = .

    z = .

    p = .

    q = .

    , :

    1

    x = 1

    2

    x = v{y(lz) + z(1y)}

    3

    z = v{p(lq) + (1p)q}

    4 p = 0

    5

    q = 0,

    , v,

    lx = 0 (1)

    x{yz + (1y)(1z)} = 0 (2)

    z{pq + (1p)(1q)} = 0 (3)

    p = 0 (4)

    q = 0. (5)

    x, p, q, y, z = 0.

    x, p, q, z,

    y=1.

    :

    1

    .

    2.

    Dr. Clarke . ,

    , x, y, z, p, q,

    ,

    .

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    ., .

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    Clarke,

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    8. .

    III.

    .

    :-

    1

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    , .

    2

    .

    3

    .

    , ,

    x = .

    y = .

    z = .

    w = .

    x(1y)(1z) + y(1x)(1z) + z(1x)(1y) = l, (1)

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    x = 0, (2)

    w=v(1y), (3)

    v,

    wy = 0. (4)

    , , 0 1,

    . x

    y(1z) + z(1y) = 1 (5)

    , yz +(1y)(1z) = 0. (6)

    (4) (6), y,

    w(1z) = 0,

    w = vz

    ,-.

    (5), , ,-

    , .

    9. Dr. Samuel Clarke ,

    . :

    ,

    , . , ,

    , ,

    , ,

    . : ,

    ( Sir Isaac Newton

    ,

    ), , .

    ,

    .- (. 25, 26).

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    :

    1

    ,

    , .

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    2

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    3

    ,

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    4

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    5

    ,

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    6 .

    , ,

    .

    :

    x = .

    y = .

    t = .

    z = ,

    .

    w = .

    v = .

    ,

    q :

    x = q{y(1t) + (1y)t}.

    tz = q(1w).

    y = qv.

    v = q(1x).

    x = qz.

    w = 1.

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    , q, ,

    .:

    x{yt +(1 y)(1 t)} = 0. (1)

    tzw = 0. (2)

    y(1 v) = 0. (3)

    vx = 0. (4)

    x(1 z) = 0. (5)

    1 w = 0. (6)

    w, v, z, y, t,

    x = 0,

    , .

    Dr. Clarke.

    ( v, z, y, t, x, w = 1),

    0 = 0.

    .

    ,

    , .:- ,

    , .

    tz = 0,

    z = q(1 t) .

    , ,

    ,

    .

    .

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    10. Dr. Clarke ,

    ,

    .

    IV. .

    ,

    ,- , , .

    V.

    ,

    , .

    VI.

    .

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    .

    :

    1

    , .

    2

    , ,

    3

    .

    4

    .

    x = .

    y = .

    z = .

    w = .

    t = .

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    , , ,

    xy(1 z) = 0. (1)

    x(1w) = 0. (2)

    w(1t) = 0. (3)

    tz = 0. (4)

    t,w, z,

    xy = 0,

    y = 0/0 (1x);

    ,- .

    VII. .

    , ,

    ,

    ,

    .

    :1. ,

    .

    2. ,

    .

    3. ,

    .

    :-

    x = .

    y = .

    z = .

    , ,

    x(1y) = 0. (1)

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    y(1z) = 0. (2)

    zx = 0. (3)

    y z,

    x = 0.

    ,.

    11. , Bishop Butler, Demonstration,

    , ,

    , Dr. Clarke ,

    .

    ,

    , ,-

    Dr. Clarke,

    Butler. Butler :

    , ,

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    Dr. Clarke .

    . Butler

    ,

    ,

    , . Dr.

    Clarke, , ,

    ,

    .

    12. VIII. .

    ,

    , ,

    ,

    .

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    , ,

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    . a posteriori

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    .

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    3. , .

    4. , .5. , , , .

    ,

    x = ( )

    1x = .

    y = .

    p = .

    q = .

    r = .

    s = .

    x = vy.

    1x = v {p (1q) (1r) + q (1p) (1r) + r (1p) (1q)}.

    p = vy.

    q = vs (1s) = 0.

    r (1q) (1p) = 0.

    , , q = 0, , q

    ,

    x = vy, 1x = v {p (1r) + r (1p)},

    p = vy, r (1p) = 0,

    v, ,

    x (1y)=0, (1)

    (1x) {pr +(1p)(1r)} = 0, (2)

    p(1y) = 0, (3)

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    r (1p) = 0. (4)

    y,

    Dr. Clarke. , x (1) (2),

    (1y){pr + (1p)(1r)} = 0. (5)

    , r (4) (5),

    r(lp) + (1y){pr + (1p)(1r)} = 0,

    {1p + (1y)p} x (1y)(1p) = 0;

    (1y)(1p) = 0. (6)

    , p (3) (6),

    1y = 0,

    y = 1 ,

    , .

    .

    y (1), (2), (3),

    (4), , ,

    (1x){pr +(1p)(1r)} = 0, r(1p) = 0. (7)

    x,

    r(1p) = 0, r = vp, ,

    , .

    , , r,

    (1x)(1p) = 0,

    , 1x = vp,

    ,,

    .

    , p,

    (1x) r = 0,

    ,

    1x = r(1r),

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    , ,

    .

    r = vx,

    ,

    , .

    13. .

    , , 1

    ,

    2

    , ,-

    . , .

    , , , ,

    . , , .

    ,

    , . ,

    .

    ( VI. 16)

    , , , ,

    , ,

    .

    , (2) (4)

    px = 0,

    .

    (1x) {pr + (1p)(1r)} + r(1p) + px = 0. (8)

    p,

    r = 0,

    , .

    r (8),

    (1x)(1p) + px = 0, or, 1x = p

    , ,

    .

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    IX. ,

    , .

    ,

    , .

    ,

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    .

    14. . , , , . ,

    ,

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    , (

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    , , ,

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    .

    .- . 112.

    :

    1

    , , .

    2

    .

    3,

    , .

    4

    ,

    , .

    5

    .

    :

    w = .

    x = .

    y = .

    z = .

    p = .

    q = .

    r = .

    t = .

    , ,

    , , , ,

    :

    w = v {x(1y)(1q) + y(1x)(1z) + z(1x)(1y)}.

    x = v(1t).

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    y = v {p(1q)(1r) + q(1p)(1r) + r(1p)(1q)}.

    p(lq) + q(lp) = v(1t).

    t = vw.

    , v,

    w {1x(1y)(1z)y(1x)(1z)z(1x)(1y)} = 0, (1)

    xt = 0, (2)

    y {1p(1q)(1r)q(1p)(1r)r(1p)(1q)} = 0, (3)

    {p(1q) + q(1p)} t = 0, (4)

    t(1w) = 0. (5)

    , ,

    , ,

    , .

    t z r.

    w, x, y, p, q . ,

    .

    w (1) (5),

    t{1x(1y)(1z)y(1x)(1z)z(1x)(1y)} = 0. (6)

    p (3) (4)

    yqr + yqt + yt(1r)(1q) = 0. (7)

    q

    yt(1r) = 0. (8)

    x (2) (6)

    t{yz + (1y)(1z)} = 0. (9)

    y (8) (9)

    t(1z)(1r) =0.

    t, z, r.

    t = 0/{(1z)(1r)}

    = (0/0)zr + (0/0)z(1r)+(0/0)(1z)r+0(1z)(1r)

    = (0/0)z + (0/0)(1z)r

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    , , , ,

    .

    . (8)

    t=0/y(1r) = (0/0)yr + (0/0) (1y)r + 0/0(1y)(1r)=(0/0)yr + (0/0)(1y)

    , , ,

    .

    .

    , .

    1.

    , : , ,

    ;

    . .

    z, p, q, 0 = 0.

    2. ,

    , ;

    x, t, p

    xt + pt = 0;

    t = 0/(p+x)=(0/0)=(1p)(1x).

    , , .

    3.,

    .

    pqy = 0,

    y = 0/pq = (0/0)p(1q)+(0/0)(1p).

    ,

    , .

    4.

    ;

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    y(1z) = s, , ,

    ts(1r) = 0

    s = 0/t(1r )=(0/0)tr+0/0(1t).

    , , , ,

    , .

    .

    ,

    .:

    , ,

    .

    , ,

    .

    .

    , ,

    .

    ,

    1t = yz + (0/0)y(1z) + (0/0)(1y)z + (1y)(1z).

    ,

    .

    ,

    , .

    , ,

    , .

    15. , , , , ,

    , , , ,

    .

    1. (w) (x), (y), (z).2. (x) (t).3. (y) (p), (q), (r).

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    4. (p) (t).5. (q) (t).6. (z) (u).7. (r) (u).

    8. .

    ,

    v, :

    w(1x)(1y)(1z) = 0, (1)

    xt = 0, (2)

    y(1p)(1q)(1r) = 0, (3)

    pt = 0, (4)

    qt = 0, (5)

    z(1u) = 0, (6)

    r(1u) = 0, (7)

    t(1w) = 0. (8)

    V(1V) = 0.

    , ,

    .

    ,

    , ..

    , ,

    .

    ,

    , , .

    , ,

    , .

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    16. . . Spinoza.

    .

    1. (causa sui), , .

    2. (in suo genere finita) ..

    ,

    . .

    , .

    3. , (in se), (per seconcipitur), ,

    .

    4. , , .

    5. , , , .

    6. , , , .

    ., .

    () .

    ,

    .

    7. , , , ,

    , .

    8. , , .

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    ., ,

    , ,

    .

    .

    1. .2. .

    3. , , , .

    4. .5. .

    6. . (Idea vera debet cum suoideato convenire.)

    7. . , ,

    . , .,

    , 3 5,

    , ,

    . ,

    V. .

    . , ,

    ,

    Ethics ,

    . ,

    ,

    ,

    Spinoza.

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    17. , , , Spinoza ,

    1

    , x,

    , x' , ,

    x + x' = 1; (. I.)

    , x = 1 - x'.

    2

    , y,

    , y'

    y =1 - y'. (. II.)

    3

    , z, , z'

    z =1 - z'. (. III.,V.)

    4

    , f, , f';

    f =1 - f'. (. VII.)

    5

    , e,

    , e'

    e =1 - e'. (. I. . VII.)

    ,

    , . . III.,

    ,

    z = y.

    , . IV., Spinoza,

    y = e.

    , . VII.,

    f = e.

    , . V

    z' = x', ,

    z = x.

    ,

    :

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    x = y = z = f = e = 1 - x' = 1 - y' = 1 - f' = 1 - z' = 1 - e'.

    , Spinoza ,

    .

    z = 1 - e',

    , ,

    .

    z = e,

    , , .

    . Spinoza

    ,

    . ,

    ,

    , .

    18. V. , . :

    ,

    ,

    , , ,

    . .

    . , . IV.,

    . . VI. . , ,

    ,

    .

    VIII. , .

    . , , V

    , VII. , ,

    . , , ..

    ,

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    , VII. , ,

    , V. , , .

    ,

    , . .

    , .

    . Spinoza

    ,

    , , ,

    .

    .

    : Quum finitum esse revera sit ex parte negatio, et infinitum absoluta

    affirmatio existentiae alicujus naturae, sequitur ergo ex sola Prop. VII. omnem substantiam

    debere esse infinitam.

    Clarke, Butler (. 11),

    .

    , a priori,

    ,

    , Spinoza

    . , ,

    , ,

    .

    , . , . , XIV.

    ,

    , XV. , XVII.

    , XVIII. .

    VI., ,

    .

    , V.

    , .

    Ethics Spinoza, ,

    , .

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    , ,

    ,

    , ,

    .

    ,

    , ,

    , .

    19. , , Clarke Spinoza

    , a priori, , ,

    . , ,

    , , ,

    .

    ; ,

    ,

    , a priori,

    . Spinoza

    : Mens humana adaequatum habet cogni-tionem aeternae et infinitae

    essentiae Dei (. XLVII., 2). . XXXIV., 2

    Omnis idea quae in nobis est absoluta sive adaequata et perfecta, vera est

    VI., 1, Idea vera debet cum suo ideato convenire. ,

    : De natura rationis est res sub quadam aeternitatis

    specie percipere (. XLIV., 2). ,

    , ,

    , ,

    ,

    . , , ,

    ,-

    ,

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    ,

    , , ,

    . ,

    .

    , ,

    .

    ,

    ,

    - ,

    ,

    .

    , ,

    ,

    .